The p-Block Elements Test

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The p-Block Elements Test - 32

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Weekly Quiz Competition

Question 1
1 / -0

Ammonia can be dried by:

A
conc. $$\displaystyle H_{2}SO_{4}$$

B
$$\displaystyle P_{4}O_{10}$$

C
$$CaO$$

D
anhydrous $$\displaystyle CaCl_{2}$$

Solution

Hint: Ammonia $$N{{H}_{3}}$$ gas is highly soluble in water and needs to be dried for its use in industry and commerce.

Explanation:

Ammonium phosphates are formed when ammonia combines with phosphorus pentoxide.

Calcium chloride is highly hygroscopic, absorbing practically all of the water when it comes into contact, although but it interacts exothermically with ammonia to generate calcium chloride complex.

As $$CaO$$ is basic in nature and does not react with ammonia, ammonia can be quickly dried by passing it over fresh quicklime or soda lime (granules of calcium oxide and sodium hydroxide).

Final answer:
So, ammonia can be dried by $$CaO$$.

Hence, the correct answer is option $$C$$.
Question 2
1 / -0

Which is the strongest oxidising agent out of the following?

A
$$\displaystyle { I }_{ 2 }$$

B
$$\displaystyle { Cl }_{ 2 }$$

C
$$\displaystyle { Br }_{ 2 }$$

D
$$\displaystyle { F }_{ 2 }$$

Solution

Fluorine is such a powerful oxidising agent that you can't reasonably do solution reactions with it.
Standard Reduction Potential for fluorine is 2.87 V.
Question 3
1 / -0

Inter- halogen compounds can be :

A
$$ ICl_3 $$

B
$$ BrF_5 $$

C
$$ IF_7 $$

D
all of these

Solution

Halogens can combine and to form inter-halogen compounds which are highly reactive in nature.

Interhalogen Compounds as the subordinates of halogens. These are the compounds having two unique sorts of halogens. For example, the common interhalogen compounds include Chlorine monofluoride, bromine trifluoride, iodine pentafluoride, iodine heptafluoride, etc.
Question 4
1 / -0

The interhalogen compound not obtained is :

A
$$ ICl $$

B
$$IF_5 $$

C
$$ BrF_5 $$

D
$$ BrCl_7 $$

Solution

Possible interhalogen compounds:

$$AX$$ $$AX_3$$ $$AX_5$$ $$AX_7$$

$$CIF$$ $$CIF_3$$ $$CIF_5$$ $$IF_7$$
$$BrF$$ $$BrF_3$$ $$BrF_5$$
$$BrCl$$ $$(ICI_3)_2$$ $$IF_5$$
$$ICI$$ $$IF_3$$(unstable)
$$IBr$$
$$IF$$ (unstable)

Hence,option D is correct.
Question 5
1 / -0

Assuming that the seventh period is $$32$$ members long, what should be the atomic number of the noble gas following radon $$(Rn)$$?

A
$$120$$

B
$$118$$

C
$$116$$

D
$$122$$

Solution

The atomic number of $$Rn$$ is $$86$$.
The atomic number of the noble gas following Rn will be $$86+32=118$$.
The alkali metal following francium $$(Fr)$$ has $$Z=119$$,
Question 6
1 / -0

The $$(IE)_1$$ and the $$(IE)_2$$ in kJ mol$$^{-1}$$ of a few elements designated by Roman numerals are shown below

Element $$(IE)_1$$ $$(IE)_2$$
A 2372 5251
B 520 7300
C 900 1760
D 1680 3380
Based on above information, Which represents a noble gas ?

A
$$A$$

B
$$B$$

C
$$C$$

D
$$D$$

Solution

From the above data, it can be seen that A has the highest value of first and second ionization potential.

$$( IE_1 )$$ is known as first ionisation potential and $$( IE_2 )$$ is known as second ionisation potential.

So (A) represents as a noble gas.
Question 7
1 / -0

The greater reactivity of $$\displaystyle { F }_{ 2 }$$ is due to :

A
lower electron affinity of F.

B
lower bond energy of $$\displaystyle { F-F }$$ bond.

C
higher electronegativity of F.

D
gaseous state of $$\displaystyle { F }_{ 2 }$$.

Solution

The greater reactivity of $$F_2$$ is due to lower bond energy of F- F bond and bond energy is lower because of charge repulsion between two F atoms (due to lower size of F atom charge density is high and repulsion is very high so bond energy is low) making its bond enthalpy lower..
Question 8
1 / -0

$$NH_3$$ can't be obtained by :

A
heating of $$NH_4NO_3$$ or $$NH_4NO_2$$

B
heating $$NH_3CI$$ or $$(NH_4)_2CO_3$$

C
heating of $$NH_4NO_3$$ with $$NaOH$$

D
reaction of $$AIN$$ or $$Mg_3N_2$$ or $$CaCN_2$$ with $$H_2O$$

Solution

Reactions are:
$$NH_4NO_3\rightarrow N_2O+H_2O$$
$$NH_4NO_2\rightarrow N_2+H_2O$$
$$NH_4Cl\rightarrow NH_3+HCl$$
$$NH_4NO_3 (aq) + NaOH(s)\rightarrow NH_3(g) +H_2O (l)+ NaNO_3(aq)$$
$$CaCN_2+3H_2O\rightarrow CaCO_3+NH_3$$
Question 9
1 / -0

Major minerals containing nitrogen are:

A
$$DNA$$

B
$$RNA$$

C
$$KNO_3, NaNO_3$$

D
all of these

Solution

Nitrogen gas makes up about 78% of the atmosphere by volume. There are relatively major minerals containing nitrogen as nitrates are 'saltpetre' ($$NaNO_3$$) and $$KNO_3$$.
Question 10
1 / -0

Nitrogen differs from P, As, Sb and Bi in the following properties :

A
It forms diatomic molecule.

B
It is not able to extent its coordination number beyond four.

C
Nitrogen does not function as a Lewis acid whereas P, As, Sb and Bi do so.

D
In all the properties given above.

Solution

As vacant d-orbital are present in P and other elements of this group except N so they can expand their valency and forms stable pentavalence product but due to absence of d-orbitals nitrogen cannot form pentavalence products.

It forms diatomic molecule $$N_2$$.
Nitrogen does not function as a Lewis acid due to absence of d-orbitals and it is a Lewis base due to presence of lone pair.

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Element	$$(IE)_1$$	$$(IE)_2$$
A	2372	5251
B	520	7300
C	900	1760
D	1680	3380

The p-Block Elements Test - 32

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The p-Block Elements Test - 32

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Question 1

conc. $$\displaystyle H_{2}SO_{4}$$

$$\displaystyle P_{4}O_{10}$$

$$CaO$$

anhydrous $$\displaystyle CaCl_{2}$$

Solution

Question 2

$$\displaystyle { I }_{ 2 }$$

$$\displaystyle { Cl }_{ 2 }$$

$$\displaystyle { Br }_{ 2 }$$

$$\displaystyle { F }_{ 2 }$$

Solution

Question 3

$$ ICl_3 $$

$$ BrF_5 $$

$$ IF_7 $$

all of these

Solution

Question 4

$$ ICl $$

$$IF_5 $$

$$ BrF_5 $$

$$ BrCl_7 $$

Solution

Question 5

$$120$$

$$118$$

$$116$$

$$122$$

Solution

Question 6

$$A$$

$$B$$

$$C$$

$$D$$

Solution

Question 7

lower electron affinity of F.

lower bond energy of $$\displaystyle { F-F }$$ bond.

higher electronegativity of F.

gaseous state of $$\displaystyle { F }_{ 2 }$$.

Solution

Question 8

heating of $$NH_4NO_3$$ or $$NH_4NO_2$$

heating $$NH_3CI$$ or $$(NH_4)_2CO_3$$

heating of $$NH_4NO_3$$ with $$NaOH$$

reaction of $$AIN$$ or $$Mg_3N_2$$ or $$CaCN_2$$ with $$H_2O$$

Solution

Question 9

$$DNA$$

$$RNA$$

$$KNO_3, NaNO_3$$

all of these

Solution

Question 10

It forms diatomic molecule.

It is not able to extent its coordination number beyond four.

Nitrogen does not function as a Lewis acid whereas P, As, Sb and Bi do so.

In all the properties given above.

Solution

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