The p-Block Elements Test

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The p-Block Elements Test - 40

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Weekly Quiz Competition

Question 1
1 / -0

The comparatively high b.pt of $$HF$$ is due to:

A
high reactivity of fluoring

B
small size of hydrogen atom

C
formation of hydrogen bonds and consequent association

D
high IE of flourine

Solution

Intermolecular hydrogen bonding is found in $${(HF)}_{n}$$ due to higher electronegativity of fluorine atoms
$$\underset { \downarrow \\ hydrogen\quad bonding }{ \cdot \cdot \cdot H-F\cdot \cdot \cdot H-F\cdot \cdot \cdot H-F\cdot \cdot \cdot } $$
Hydrogen bonding is helpful in the association of $$HF$$ molecule, so $$HF$$ is found in liquid form.
Question 2
1 / -0

Pressure is increased in the Haber process for making ammonia. It favors :

A
the reverse reaction

B
the forward reaction

C
neither reaction

D
none

Solution

Pressure is increased in the Haber process for making ammonia. It favors the forward reaction.
$$\displaystyle N_2 + 3H_2 \rightarrow 2NH_3$$
The reaction proceeds with decrease in the number of moles of gaseous species. With increase in pressure, the equilibrium shifts in forward direction with decrease in the number of moles of gaseous species so that, the effect of increased pressure is nullified.
Question 3
1 / -0

Bond energy of $$F_2, Cl_2$$ and $$Br_2$$ follow the order:

A
$$F - F > Cl - Cl > Br - Br$$

B
$$Cl - Cl >Br - Br > F - F$$

C
$$Br - Br > Cl - Cl > F - F $$

D
$$Cl - Cl > F - F > Br - Br $$

Solution

The order of bond energy is :

$$\displaystyle Cl-Cl (57 \: kcal/mol) > Br-Br (45.5 \: kcal/mol) > F-F (38 \: kcal/mol) $$
Question 4
1 / -0

Monatomic gas among the following at STP is :

A
bromine

B
hydrogen

C
calcium

D
neon

E
nitrogen

Solution

Noble gases are the only chemical elements which are stable single atom molecules at standard temperature and pressure. The noble gases are almost entirely unreactive or inert because, they all have a full outer shell of electrons. These are helium $$(He)$$, neon$$(Ne)$$, argon$$(Ar)$$, krypton $$(Kr)$$, xenon $$(Xe)$$ and radon $$(Rn)$$. The heavier noble gases, like $$Xe$$, are exceptions as they can form chemical compounds by expending octet.
Question 5
1 / -0

Ammonia gas can be dried over by:

A
$$Ca{ Cl }_{ 2 }$$

B
conc. $${ H }_{ 2 }S{ O }_{ 4 }$$

C
$${ P }_{ 2 }{ O }_{ 5 }$$

D
quick lime

Solution

Ammonia is prepared by heating a mixture of calcium hydroxide and ammonium chloride.

$$Ca{(OH)}_2(s) + 2NH_4Cl(s) \longrightarrow Ca{Cl}_2(s) + 2H_2O(l) + 2NH_3(g) $$

Concentrated sulphuric acid conc. $$H_2SO_4$$ and anhydrous calcium chloride $$Ca{Cl}_2$$ are not used to dry ammonia because they react with it. The gas is passed through fresh quicklime (solid calcium oxide lumps) to effectively dry it. Ammonia is collected by upward delivery as it is lighter than air.
Question 6
1 / -0

Haber process is used for the production of:

A
$$NH_{3}$$

B
$$HNO_{3}$$

C
$$H_{2}SO_{4}$$

D
$$O_{3}$$

Solution

Haber process is used for the production of ammonia ($$NH_3$$) gas.

$$N_{2}(g) + 3H_{2}(g) \leftrightharpoons 2NH_{3}(g)$$
Question 7
1 / -0

Which of the following elements can be involved in p$$\pi-d\pi$$ bonding?

A
Carbon

B
Nitrogen

C
Phosphorus

D
Boron

Solution

If there is bonding between two atoms where one atom is having one vacant orbital and another is having one lone pair of electrons, then if this electron pair is donated to that respective vacant orbital then the bonding is called $$p\pi -p\pi$$ or $$p\pi -d\pi $$ depending on the orbital to which the electron pair is donated and from which the electron pair is donated.

Nitrogen, Carbon, and Boron can not form $$p\pi -d\pi $$ bond because of the absence of d-orbitals in its valence shell. But Phosphorus can form $$ p\pi -d\pi $$ bonds.
Question 8
1 / -0

Nitric acid can be obtained from ammonia via the formations of the intermediate compounds:

A
nitric oxide and nitrogen dioxide

B
nitrogen and nitric oxide

C
nitric oxide and dinitrogen pentoxide

D
nitrogen and nitrous oxide

Solution

Ostwald process for the manufacture of nitric acid:

$$\underset { \text{Ammonia} }{ 4{ NH }_{ 3 } } +{ 5O }_{ 2 }\xrightarrow [ 700-{ 800 }^{ o }C ]{ Pt\;\text{gauge }} \underset { \text{Nitric oxide} }{ 4NO } +6{ H }_{ 2 }O\quad ;\Delta H=-21.5\ kcal$$

$$ 2NO+{ O }_{ 2 }\xrightarrow [ ]{ { 50 }^{ o }C } \underset { \text{Nitrogen dioxide} }{ 2{ NO }_{ 2 } } $$

$$4{ NO }_{ 2 }+2H_2O+{ O }_{ 2 }\longrightarrow \underset {\text{ Nitric acid} }{ 4H{ NO }_{ 3 } } \quad $$
Question 9
1 / -0

Which among the following is inert gas and not very soluble in water too?

A
$$\displaystyle { O }_{ 2 }$$

B
$$\displaystyle { CO }_{ 2 }$$

C
$$\displaystyle { N }_{ 2 }$$

D
$$\displaystyle { H }_{ 2 }{ SO }_{ 4 }$$

E
$$\displaystyle He$$

Solution

$$He$$ is a n inert or noble gas.Noble/Inert gases are any of the seven chemical elements that make up Group $$18$$ (VIIIa) of the periodic table. The elements are helium$$ (He)$$, neon $$(Ne)$$, argon$$ (Ar)$$, krypton $$(Kr)$$, xenon$$ (Xe)$$, radon $$(Rn)$$, and element $$118$$ ununoctium $$(Uuo)$$. The noble gases are colourless, odourless, tasteless, nonflammable gases.
Question 10
1 / -0

Which of the following is most electronegative element?

A
Al

B
F

C
Ca

D
Li

E
C

Solution

F is most electronegative element.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 40

Result

The p-Block Elements Test - 40

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SHARING IS CARING

Question 1

high reactivity of fluoring

small size of hydrogen atom

formation of hydrogen bonds and consequent association

high IE of flourine

Solution

Question 2

the reverse reaction

the forward reaction

neither reaction

none

Solution

Question 3

$$F - F > Cl - Cl > Br - Br$$

$$Cl - Cl >Br - Br > F - F$$

$$Br - Br > Cl - Cl > F - F $$

$$Cl - Cl > F - F > Br - Br $$

Solution

Question 4

bromine

hydrogen

calcium

neon

nitrogen

Solution

Question 5

$$Ca{ Cl }_{ 2 }$$

conc. $${ H }_{ 2 }S{ O }_{ 4 }$$

$${ P }_{ 2 }{ O }_{ 5 }$$

quick lime

Solution

Question 6

$$NH_{3}$$

$$HNO_{3}$$

$$H_{2}SO_{4}$$

$$O_{3}$$

Solution

Question 7

Carbon

Nitrogen

Phosphorus

Boron

Solution

Question 8

nitric oxide and nitrogen dioxide

nitrogen and nitric oxide

nitric oxide and dinitrogen pentoxide

nitrogen and nitrous oxide

Solution

Question 9

$$\displaystyle { O }_{ 2 }$$

$$\displaystyle { CO }_{ 2 }$$

$$\displaystyle { N }_{ 2 }$$

$$\displaystyle { H }_{ 2 }{ SO }_{ 4 }$$

$$\displaystyle He$$

Solution

Question 10

Al

F

Ca

Li

C

Solution

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