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The p-Block Elements Test - 41

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The p-Block Elements Test - 41
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which element is more likely to exist in many different forms?
    Solution
    Phosphorous is more likely to exist in many different forms.
    Various allotropes of phosphorous include red phosphorous, black phosphorous, white phosphorous or yellow phosphorous.
  • Question 2
    1 / -0
    Find the gases which is the densest at standard temperature and pressure.
    Solution
    The gas which is the densest at standard temperature and pressure is xenon.
    At standard temperature and pressure, pure xenon gas has a density of 5.761 kg/m$$^3$$, about 4.5 times the surface density of the earth's atmosphere, 1.217 kg/m$$^3$$. As a liquid, xenon has a density of up to 3.100 g/mL, with the maximum density occurring at the triple point.
  • Question 3
    1 / -0
     In commercial industry, ammonia is prepared by :
    Solution
     In commercial industry, ammonia is prepared by combining hydrogen and nitrogen gases (Haber process).
    $$N_2 + 3H_2 \rightleftharpoons 2NH_3+24\ kcal$$
  • Question 4
    1 / -0
    What are the missing products of the following reaction? $$\displaystyle { NH }_{ 4 }Cl+{ Ca\left( OH \right)  }_{ 2 }\rightarrow \_ \_ \_ +Ca{ Cl }_{ 2 }$$
    Solution
    Calcium hydroxide reacts with ammonium chloride to give ammonia, water and calcuim chloride.

    $${ 2NH }_{ 4 }Cl+Ca{ (OH) }_{ 2 }\rightarrow { 2NH }_{ 3 }+{ 2H }_{ 2 }O+{ CaCl }_{ 2 }$$
  • Question 5
    1 / -0
    Read the two statements given below and answer whether they are true or false.

    Statement I: $${He}_{2}$$ is not a commonly known form.

    Statement II: $$He$$ is lighter than air.
  • Question 6
    1 / -0
    The number of valence electrons present in noble gases is:
    Solution
    The number of valence electrons present in noble gases is 8.
    For example the noble gas with atomic number 18 has electronic configuration $$\displaystyle 1s^2 \: 2s^22p^6 \: 3s^23p^6$$. Since it has completed its octet, it is stable and least reactive.
  • Question 7
    1 / -0
    Identify the true statement regarding nitrates of all metals.
    Solution

    Nitrates of divalent and trivalent metals (Mg, Ca, Ba, Pb, Cu, Zn, Hg, Al, Fe etc.) decompose on heating to give reddish brown fumes of nitrogen dioxide.

    The nitrates, chlorates, and acetates of all metals are soluble in water.

    Nitrates are not stable to heat they decompose to release nitrogen dioxide.


  • Question 8
    1 / -0
    Formation of $${O}^{-}$$ is ________, whereas formation of $${O}^{-2}$$ is __________.
    Solution
    The formation of an $$O^-$$ ion is exothermic, which means energy is released in the process. This is because adding an electron to $$O$$ is much easier as it is electropositive and has a high electron affinity. The electron gain enthalpy in this case is $$-142 {\text{ kjmol}}^{-1}$$.
    $$O + e^- \rightarrow O^-$$ $$[\Delta r^\circ = -142 {\text { kjmol}^{-1}}]$$

    To form an $$O^{2-}$$ ion, another electron has to be added to $$O^-$$ ion. However, since $$O^-$$ ion is already negatively charged, it resists the addition of a negatively charged electron. Thus, because of the repulsive coulumbic forces between the ion and the electron, more energy is required to overcome these forces. So, the formation of $$O^{2-}$$ is an endothermic process as energy is absorbed. The electron gain enthalpy in this case is $$+844 {\text { kjmol}^{-1}}$$.
    $$O^- + e^- \rightarrow O^{2-}$$ $$[\Delta r^\circ = +844 {\text{ kjmol}^{-1}}]$$
  • Question 9
    1 / -0
    Nitrogen reacts with a metal $$M$$ to produce a compound $$X$$. This compound $$X$$ when dissolved in water forms pungent gas $$Y$$ which can be identified easily by the formation of white fumes in the presence of $$HCl$$.

    Identify Y:
    Solution
    $$ 3Ca+{ N }_{ 2 }\xrightarrow [ \Delta  ]{  } { Ca }_{ 3 }{ N }_{ 2 } $$

    $$ { Ca }_{ 3 }{ N }_{ 2 }+6{ H }_{ 2 }O\xrightarrow [  ]{  } 3Ca{ (OH) }_{ 2 }+2N{ H }_{ 3 } $$
    From the reaction we can see that the metal $$ M $$ is $$Ca$$ and pungent gas $$ Y $$ is Ammonia. 
  • Question 10
    1 / -0
    In crystalline form sulphur existing in $${ S }_{ 8 }$$ molecule has:
    Solution
     In crystalline form sulphur existing in $$\displaystyle S_8$$ molecule has Crown shaped structure.

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