The p-Block Elements Test

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The p-Block Elements Test - 44

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Weekly Quiz Competition

Question 1
1 / -0

Nitrogen gas can be obtained by heating :

A
ammonium nitrate

B
ammonium nitrite

C
magnesium nitride

D
ammonium chloride

Solution

$$\begin{array}{l}\text { A.) Ammonium nitrate ( } \mathrm{NH}_{4} \mathrm{NO}_{3} \text { ) } \\\mathrm{NH}_{4} \mathrm{NO}_{3}\longrightarrow\mathrm{\triangle} \underset{\text { Nitrous oxide }}{\mathrm{N}_{2} \mathrm{O}}+2 \mathrm{H}_{2}\mathrm{O}\end{array}$$

$$\begin{array}{l}\text { B.) Ammonium nitrite }\left(\mathrm{NH}_{4} \mathrm{NO}_{2}\right) \\\mathrm{NH}_{4} \mathrm{NO}_{2}\longrightarrow \mathrm{N}_{2} \uparrow+2 \mathrm{H}_{2}\mathrm{O}\end{array}$$

$$\begin{array}{l}\text { C) Megnesium nitride }\left(\mathrm{Mg}_{3} \mathrm{~N}_{2}\right) \\\mathrm{Mg}_{3} \mathrm{~N}_{2} \underset{700-150^{\circ} \mathrm{C}}{\longrightarrow} 3\mathrm{Mg}+\mathrm{N}_{2}[\text { Rare Conditim }]\end{array}$$

$$\begin{array}{l}\text { D ) Ammonium Chloride ( } \mathrm{NH}_{4} \mathrm{Cl} \text { ) } \\\mathrm{NH}_{4} \mathrm{Cl} \quad\underset{\Delta}{\longrightarrow}\mathrm{NH}_{3}+\mathrm{HCl} \\\text { Correct Answer - (B) }\end{array}$$
Question 2
1 / -0

An element with atomic number $$82$$ belongs to the group:

A
16

B
12

C
14

D
2

Solution

The atomic number belongs to lead. It belongs to carbon family group 14 period 6.
Question 3
1 / -0

Hydride of nitrogen is:

A
acidic

B
basic

C
neutral

D
none of the above

Solution

Hydride of nitrogen is basic due to lone pair of electrons on nitrogen atom. The common hydrides of nitrogen are hydrazine,diazene,ammonia out of which only ammonia is thermally stable.
Question 4
1 / -0

Which of the following elements does not forms stable diatomic molecules :

A
$$I$$

B
$$P$$

C
$$N$$

D
$$O$$

Solution

Phosporous forms tetra atomic molecule it do not forms stable diatomic molecule where as the other given elements forms stable diatomic molecules(Due to larger atomic size P is do not form pi bonds and so it exists as a tetra-atomic molecule in which each P atom is bonded with 3 other P atoms by 3 sigma bond. But, due to smaller atomic size N forms 1 sigma and 2 pi bonds i.e. triple bonds with other N atom and exists as diatomic molecule.)
Hence option B is correct.
Question 5
1 / -0

When plant and animal decay, the organic $$N$$ is converted into inorganic $$N$$. The inorganic $$N$$ is in the form of:

A
$$NH_3$$

B
element of $$N$$

C
nitrates

D
nitrides

Solution

During plant and animal decay the organic nitrogen converts into $$NH_3$$ which is inorganic.
Question 6
1 / -0

Which of the following halide of nitrogen is not explosive in nature?

A
$$NCl_3$$

B
$$NI_3$$

C
$$NBr_3$$

D
$$NF_3$$

Solution

The only stable halide of nitrogen $$NF_3$$ is not explosive. The other halides are explosive due to their unstable nature because of much larger sizes.

Hence, the correct option is $$D$$
Question 7
1 / -0

The Xenon compound which has more number of lone pairs in its central atom is :

A
$$XeF_6$$

B
$$XeOF_4$$

C
$$XeF_4$$

D
$$XeO_3$$

Solution

The Xenon compound which has more number of lone pairs in its central atom is $$\displaystyle XeF_4$$. $$Xe$$ atom in $$\displaystyle XeF_4$$ has 2 lone pairs of electrons and 4 bond pairs of electrons.

Note: $$Xe$$ atom in $$\displaystyle XeF_6$$, $$\displaystyle XeOF_4$$ and $$\displaystyle XeO_3$$ has 1 lone pair of electrons each.

Hence, option (C) is the correct answer.
Question 8
1 / -0

Xenon reacts with fluorine at 873 K and 7 bar to form $$XeF_4$$. In this reaction the ratio of Xenon and fluorine required is :

A
1:5

B
10:1

C
1:3

D
5:1

Solution

Xenon reacts with fluorine at 873 K and $$7$$ bar to form $$XeF_4$$. In this reaction, the ratio of Xenon and fluorine required is $$1:5$$

$$\displaystyle Xe + 2F_2 \xrightarrow [7\ bar ]{873\ K} XeF_4$$

Hence, the option (A) is the correct answer.
Question 9
1 / -0

Cyanamide process is used in formation of-

A
$$N_2$$

B
$$HNO_3$$

C
$$NH_3$$

D
$$PH_3$$

Solution

Cyanamide process is a nitrogen fixation process in which Calcium Carbide and nitrogen react with each other at a high temperature to form Calcium Cyanamide.
The following reaction takes place:
$$CaC_2$$ $$+$$ $$N_2$$ $$ \longrightarrow $$ $$CaCN_2$$ $$+$$ $$C$$
At high temperature Calcium Cyanamide react with steam as follows:
$$CaCN_2$$ $$+$$ $$3H_2O$$ $$\longrightarrow $$ $$CaCO_3$$ $$+$$ $$2NH_3$$
Hence, $$NH_3$$ is formed.
Question 10
1 / -0

Which of the following element has metallic lustre?

A
$$F$$

B
$$Cl$$

C
$$Br$$

D
$$I$$

Solution

As we move down the group the metallic character increases which impart lustrousness to the elements.
So the iodine is most lustrous.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 44

Result

The p-Block Elements Test - 44

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SHARING IS CARING

Question 1

ammonium nitrate

ammonium nitrite

magnesium nitride

ammonium chloride

Solution

Question 2

16

12

14

2

Solution

Question 3

acidic

basic

neutral

none of the above

Solution

Question 4

$$I$$

$$P$$

$$N$$

$$O$$

Solution

Question 5

$$NH_3$$

element of $$N$$

nitrates

nitrides

Solution

Question 6

$$NCl_3$$

$$NI_3$$

$$NBr_3$$

$$NF_3$$

Solution

Question 7

$$XeF_6$$

$$XeOF_4$$

$$XeF_4$$

$$XeO_3$$

Solution

Question 8

1:5

10:1

1:3

5:1

Solution

Question 9

$$N_2$$

$$HNO_3$$

$$NH_3$$

$$PH_3$$

Solution

Question 10

$$F$$

$$Cl$$

$$Br$$

$$I$$

Solution

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