The p-Block Elements Test

Result

The p-Block Elements Test - 54

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following elements occur free in nature?

A
Nitrogen

B
Phosphorus

C
Arsenic

D
Antimony

Solution

The nitrogen which exists free in nature which is made up of 78% of Earth atmosphere and naturally found in mineral deposits, soil and organic compounds.
Question 2
1 / -0

Which of the following displaces $$Br_{2}$$ from an aquenous solution containing bromide ions?

A
$$Cl^{-}$$

B
$$Cl_{2}$$

C
$${ I }^{-}_{3}$$

D
$$I_{2}$$

Solution

chlorine displaces bromine from an aqueous solution containing bromide
Reactivity of chlorine is more than that of bromine. So chlorine replaces Bromine.
Hence answer is option B
Question 3
1 / -0

Which of the following has $$p\pi -d\pi$$ bonding?

A
$${ NO }_{ 3 }^{ - }$$

B
$${ CO }_{ 3 }^{ -2 }$$

C
$${ BO }_{ 3 }^{ -3 }$$

D
$${ SO }_{ 3 }^{ -2 }$$

Solution

$$p\pi-d\pi$$ bonding includes d-orbitals,if you observe the options only S belongs to $$3^{rd}$$ period and has d-orbitals(though unoccupied in ground state).
Other options $$C$$ and $$N$$ belongs to $$2^{nd}$$ period while B belongs to $$1^{st}$$ period and doesn't have d-orbitals.
Question 4
1 / -0

In Haber's process of manufacturing of ammonia:
$${ N }_{ 2 }\left( g \right) +{ 3H }_{ 2 }\left( g \right) \longrightarrow 2{ NH }_{ 3 }\left( g \right) ;{ H }_{ { 25 }^{ 0 }C }^{ o }=-92.2kJ$$
Molecule: $${ C }_{ p }{ JK }^{ -1 }{ mol }^{ -1 }$$
$${ N }_{ 2 }\left( g \right) $$: 29.1
$${ H }_{ 2 }\left( g \right) $$: 28.8
$${ NH }_{ 3 }\left( g \right) $$: 35.1
If $${ C }_{ p }$$ is independent of temperature, then reaction at $${ 100 }^{ 0 }C$$ as compared to that of $$25^{ 0 }C$$ will be:

A
more endothermic

B
less endothermic

C
more exothermic

D
less exothermic

Solution
Question 5
1 / -0

$$p\pi -d\pi \quad$$ bonding is present in:

A
$${ NO }_{ 3 }^{ - }$$

B
$${ SO }_{ 3 }^{ 2- }$$

C
$${ BO }_{ 3 }^{ 3- }$$

D
$${ CO }_{ 3 }^{ 2- }$$

Solution

So, $$1p\pi - d\pi$$ bonding is present is it.
The structure of $$SO_3^2-$$ is
Question 6
1 / -0

$$NH_3$$ is formed in the following steps
I. $$Ca+2C\rightarrow CaC_2$$ 50% yield
II. $$CaC_2+N_2\rightarrow CaCN_2+C$$ 100% yield
III. $$CaCN_2+3H_2O\rightarrow 2NH_3+CaCO_3$$ 50% yield
To obtain 2 moles $$NH_3$$, calcium required is:

A
1 mol

B
2 mol

C
3 mol

D
4 mol

Solution

It can be easily observed from the reaction given that 1mole of Ca is required to get 2 moles of $$NH_3$$
Question 7
1 / -0

As per Braun's principle, yield of Ammonia will be more in Haber's process under ______, conditions ($$L=$$ Low; $$H=$$ high; $$T=$$ Temp; $$P=$$ Pressure)

A
$$LT;LP$$

B
$$LT;HP$$

C
$$HT;HP$$

D
$$HT;LP$$

Solution

The manufacture of $$NH_3$$ by Haber's process is given as
$${ N }_{ 2 }(g)+{ 3H }_{ 2 }(g)\rightleftharpoons { 2NH }_{ 3 }(g)\\ \triangle 6H°=-92.4\\ $$
so, it is an exothermic reversible reaction and occurs with decrease in volume.
so, the low temperature will favour the forward reaction which is exothermic in nature
and since the reaction occurs with a decrease in volume .so, high pressure will favour the formation of of$$NH_3$$.
Question 8
1 / -0

When two atoms of chlorine combine to form one molecule of chlorine gas, the energy of the molecule:

A
Greater than that of separate atom

B
Equal to that of separate atom

C
Lower than that of separate atoms

D
None of the above

Solution

The energy of the molecule is less than that of a separate atom because the $$Cl_2$$ molecule is more stable than the $$Cl$$ atom.

$$Cl$$ atom is more reactive and it has more energy and less stability. It combines with other $$Cl$$ atom to form $$Cl_2$$ which has less energy and more stability than an individual atom.

Hence, option $$C$$ is correct.
Question 9
1 / -0

The role of zinc stearate in the process of vulcanisation is:

A
to accelerate the process

B
to slow down the process

C
to stop the process

D
to initiate the process
Solution
- In sulphur vulcanization of natural rubber excess zinc stearate enhances the yield of crosslinks, reduces their average length, and inhibits their destruction.
- It is an "activator" for accelerated rubber sulfur vulcanization.
Question 10
1 / -0

Which of the following characteristics regarding 7 halogens is not correct?

A
Ionization energy decreases with increase in atomic number.

B
Electronegativity decreases with increase in atomic number.

C
Electron affinity decreases with increase in atomic number.

D
Enthalpy of fusion increases with increase in atomic number
Solution
- Electron Affinity (decreases down the group) Since the atomic size increases down the group, electron affinity generally decreases (At < I < Br < F < Cl). An electron will not be as attracted to the nucleus, resulting in a low electron affinity.
- However, fluorine has a lower electron affinity than chlorine. Chlorine has higher electron gain enthalpy than fluorine because due to the small size of fluorine some energy is utilized in overcoming the force of repulsion among electrons.
- Hence option C is an incorrect answer.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 54

Result

The p-Block Elements Test - 54

Score

-

Rank

-

SHARING IS CARING

Question 1

Nitrogen

Phosphorus

Arsenic

Antimony

Solution

Question 2

$$Cl^{-}$$

$$Cl_{2}$$

$${ I }^{-}_{3}$$

$$I_{2}$$

Solution

Question 3

$${ NO }_{ 3 }^{ - }$$

$${ CO }_{ 3 }^{ -2 }$$

$${ BO }_{ 3 }^{ -3 }$$

$${ SO }_{ 3 }^{ -2 }$$

Solution

Question 4

more endothermic

less endothermic

more exothermic

less exothermic

Solution

Question 5

$${ NO }_{ 3 }^{ - }$$

$${ SO }_{ 3 }^{ 2- }$$

$${ BO }_{ 3 }^{ 3- }$$

$${ CO }_{ 3 }^{ 2- }$$

Solution

Question 6

1 mol

2 mol

3 mol

4 mol

Solution

Question 7

$$LT;LP$$

$$LT;HP$$

$$HT;HP$$

$$HT;LP$$

Solution

Question 8

Greater than that of separate atom

Equal to that of separate atom

Lower than that of separate atoms

None of the above

Solution

Question 9

to accelerate the process

to slow down the process

to stop the process

to initiate the process

Solution

Question 10

Ionization energy decreases with increase in atomic number.

Electronegativity decreases with increase in atomic number.

Electron affinity decreases with increase in atomic number.

Enthalpy of fusion increases with increase in atomic number

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.