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The p-Block Elements Test - 61

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The p-Block Elements Test - 61
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  • Question 1
    1 / -0
    Which of the following represents the outermost shell electronic configuration of halogens?
    Solution
    The general electronic configuration of valence shell of Halogens is $$ns^2np^5$$.
    Hence, Option "D" is the correct answer.
  • Question 2
    1 / -0
    Every noble gas atom 
    Solution
    Every noble gas atom has a saturated outermost shell.
    Hence, Option "A" is the correct answer.
  • Question 3
    1 / -0
    Which statement is not correct for nitrogen?
    Solution
    $$N_7 \to 1s^2, 2s^2, 2p^3$$

    $$d-$$ orbitals are absent in nitrogen.
  • Question 4
    1 / -0
    White Phosphorus contains
    Solution
    White Phosphorus contains $$P_4$$ molecules.
    Hence, Option "B" is the correct answer.
  • Question 5
    1 / -0
    The last member of Group 18 is
    Solution
    Radon is the last member of Periodic Table till now i.e. Atomic No. 118 and is also the last member of Group 18.
    Hence, Option "D" is the correct answer.
  • Question 6
    1 / -0
    Which of the following inert gas liquifies easily?
    Solution
    The maximum temperature at which gas can be liquified is called its critical temperature. The gas which has a high boiling point will change into liquid first and so critical temperature of the gas will be more. $$Kr$$ gas will liquify easily among the given gas since it has highest boiling point because of its mass.
  • Question 7
    1 / -0
    Which of the following statements is correct?
    Solution
    All halogens form oxy acids.
    Hence, Option "B" is the correct answer.
  • Question 8
    1 / -0
    Which of the following substances when boiled with caustic sodasolution will evolve ammonia
    Solution
    $$CH_3CONH_2+NaOH\xrightarrow[]{Boil}CH_3COONa+NH_3$$
           Acetamide

    Option C is correct.
  • Question 9
    1 / -0
    Which compounds is prepared by the following reaction:
    $$\underset { (2:1\ volume \ ratio) }{ Xe+F_{2} }\xrightarrow [ 673\ K ]{ Ni } $$ 
    Solution
    $$\underset{(2:1)}{Xe+F_{2}}\xrightarrow [ 673\ K ]{ Ni } XeF_{2}$$
  • Question 10
    1 / -0
    The incorrect statement regarding $$15^{th}$$ group hydrides $$(EH_{3}) . [E = N, P, As, Sb, Bi]$$
    Solution
    Reducing character $$\propto \dfrac{1}{'E - H' \,bond \,dissociation \,enthalpy}$$

    Hence, correct reducing character is $$NH_{3} < PH_{3} < AsH_{3} < SbH_{3} < BiH_{3}.$$

    Hence, Option "C" is the correct answer.
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