Electric Charge...

$$5$$ charges each of magnitude $$10^{-5}$$ $$C$$ and mass $$1 kg$$ are placed (fixed) symmetrically about a movable central charges of magnitude $$5 \times 10^{-5}C$$ and mass $$0.5 kg$$ as shown. The charge at $$P_{1}$$, is removed. The acceleration of the central charge is

$$[$$Given $$OP_1 = OP_2 = OP_3 = OP_4 = OP_5 = 1m;$$$$\displaystyle \frac{1}{4\pi \varepsilon _{0}}=9\times 10^{9}$$ in $$SI$$ units$$]$$

Two particles having charges $$q_{1}$$ and $$q_2$$ when kept at a certain distance, exert force $$F$$ on each other. If distance is reduced to half, force between them becomes :

Two charges of $$+1$$ $$\mu C$$ $$\&+5$$ $$\mu C$$ are placed $$4 cm$$ apart, the ratio of the force exerted by both charges on each other will be -

Two identical charges of magnitude +Q are fixed as shown . A third charge -Q is placed mid way between them at point P. Then small displacements of -Q are made in the directions indicated by arrows. The -Q is stable with respect to displacement .

If two non-identical charges are kept at a certain distance $$d$$, which one experiences more force?

When the distance between two charged particles is halved, then the force between them becomes :

Two charges are placed a certain distance apart in air. Ifa glass slab is introduced between them, the force between them will

$$12$$ positive charges of magnitude $$q$$ are placed on a circle of radius $$R$$ in a manner that they are equally spaced. $$A$$ charge $$+Q$$ is placed at the centre. If one of the charges $$q$$ is removed, then the force on $$Q$$ is :

Two charges of 10C and -15C are separated in air by 1 m. The ratio of magnitude of force exerted by one on the other is

In the given figure calculate the force on unit positive charge placed at $$A$$. The length of each side on the square is $$4 cm$$.