Electric Charge...

A charged water drop whose radius  is $$ 0.1\mu m$$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be $$(g = 10 { m }^{ -1 }$$)

An electron and a proton are in a uniform electric field, the ratio of their accelerations will be

The total flux associated with the given cube will be where $$'a'$$ is side of the cube:- 
$$\left(\dfrac{1}{\epsilon_0} = 4\pi \times 9 \times 10^{9}\  SI\  units\right)$$

Identify the wrong statement in the following:
Coulomb's law correctly describes the electric force that

Equal charges  q are placed at the vertices A and B of an aquilateral triangle ABC of side a. The magnitude of electric field at the point C due to two charges is. 

Two point charges $$q _ { 1 } \text { and } q _ { 2 }$$ terminates at are kept as shown.
One of the electric field line coming out from $$q _ { 1 }$$ makes an angle $$30 ^ { \circ }$$ with the line joining $$q _ { 1 } q _ { 2 }$$ terminates at $$q _ { 2 }$$ makes an angle $$60 ^ { \circ }$$.The ratio $$\frac { q _ { 1 } } { q _ { 2 } }$$ is

A charge q is divided into two parts q $$\left(q-q\right)$$. If the coulomb repulsion between them when they are separated is to be maximum the ratio of $$q/q$$ should be:

Two identical metal balls with charges $$+2Q$$ and $$-Q$$ are separated by some distance and exert a force $$F$$ on each other. They are joined by a conducting wire, which is then removed. The magnitude force between them will now be 

Six charges +Q each are placed at the corners of a regular hexagon of side (a), the electric field at the centre of hexagon is - 

Two positive ions, each carrying a charge $$q$$ , are separated by a distance $$d$$. If $$F$$ is the force of repulsion between the ions, the number of electronsmissing from each ion will be (e being the charge on an electron)