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Wave Optics Test - 26

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Wave Optics Test - 26
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  • Question 1
    1 / -0
    In double slit experiment, for light of which colour, the fringe width will be minimum?
    Solution
    $$\beta \propto \lambda. $$
    $$ \therefore \lambda_v =$$ minimum.
    Correct answer is violet, as it has minimum wavelength . Fringe width is directly proportional to the wavelength. So, purple or violet has the minimum fringe width  whereas red has maximum fringe width.
  • Question 2
    1 / -0
    The driver of a car traveling with speed 30 m/sec towards a hill sounds a horn of frequency 600 Hz. If the velocity of sound in air is 330 m/s, the frequency of reflected sound as heard by driver is :

    Solution
    $$n'=v\left[\dfrac{c+u}{c-u}\right]$$

           $$=600\left[\dfrac{330+30}{330-30}\right]=720Hz$$

  • Question 3
    1 / -0
    A telescope has an objective lens of 10 cm diameter and is situated at a distance of one kilometer from two objects. The minimum distance between these two objects, which can be resolved by the telescope, when the mean wavelength of light is $$5000 \dot{A}$$, is of the order of :
    Solution
    We know, 

    Resolving Power = $$\theta = \dfrac{d} {D}$$ but $$\theta \approx \dfrac{\lambda} {a}$$

    $$\left (Note :  exact\ relation,  \theta = \dfrac{1.22} {a}\lambda \right )$$

    $$\dfrac{d} {D} = \dfrac{\lambda} {a} \Rightarrow = d = \dfrac{\lambda D} {a}$$

    $$\Rightarrow d = \dfrac{5000 \times 10^{-10} \times 10^{3}} {10  \times 10^{-2}} = 5 mm$$

  • Question 4
    1 / -0
    Identify the correct statement from the following :
    Solution
    Wave nature of light was proposed by Huygens. The direction of light ray and its wavefront are perpendicular to each other. Huygen's wave theory could not explain phenomenon of polarisation. A monochromatic ray of light after passing through the prism should be made of one colour only.
  • Question 5
    1 / -0
    The wave front is a surface in which:
    Solution
     A wavefront is the locus of points having the same phase.
  • Question 6
    1 / -0
    An astronomical telescope has a large aperture to
    Solution

  • Question 7
    1 / -0
    The phenomenon of interference is shown by
    Solution

    Correct option is : (D) All kind of waves

    $$\bullet$$Interference occurs in all kinds of waves, pattern depending upon  the phases of the interfering waves.

    $$\bullet$$Interference in longitudinal waves occurs in sound waves.

    $$\bullet$$ Interference in transverse mechanical waves occurs in water ripples.

    $$\bullet$$ Interference in transverse non mechanical waves occurs in light.

  • Question 8
    1 / -0
    An astronomical telescope has on objective and an eyepiece of focal lengths $$10 cm$$ and $$1 cm$$ respectively. Find its tube length in normal adjustment.
    Solution
    $$f_0=10 cm; \quad f_e=1 cm$$

    In normal adjustment,
    Magnifying power $$=\cfrac {f_0}{f_e}=\cfrac {10}{1}=10$$
    Tube length $$=f_0+f_e$$
                         $$=(10+1)$$
                         $$=11\ cm$$
  • Question 9
    1 / -0
    Light is a form of .........
    Solution
    A Light has a dual nature Sometimes it behaves like a particle (called a photon), which explains how light travels in straight lines, Sometimes it behaves like a wave, which explains how light bends around an object.
  • Question 10
    1 / -0
    Magnification of an object ($$m$$), is equal to
    Solution
    we know,mirror formula
    $$\cfrac {1}{f}=\cfrac{1}{v}+\cfrac{1}{u}, magnification(m)=\cfrac{-v}{u}$$
    $$\cfrac{1}{u}=\cfrac{1}{f}-\cfrac{1}{v}$$
    $$\cfrac{1}{u}=\cfrac{v-f}{fv}$$
    $${u}=\cfrac{fv}{v-f}$$
    $$(m)=\cfrac{-v}{u}$$,substituting $$u$$.
    $$m=\cfrac{-v}{1}\times\cfrac{v-f}{fv}$$
    $$m=\cfrac{f-v}{f}$$
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