Wave Optics Tes...

Antinodal curves correspond to _____ interference.

Since the objective lens merely forms an enlarged real image that is viewed by the eyepiece, the overall angular magnification M of the compound microscope is the product of the lateral magnification $$ { m }_{ 1 }$$ of the objective and the angular magnification $$ { M }_{ 2 }$$ of the eyepiece. The former is given by
$$ { m }_{ 1 }=\dfrac { { S }_{ 1 }^{ ' } }{ { S }_{ 1 } } $$
Where $$ { S }_{ 1 }and{ S }_{ 1 }^{ ' }$$ are the object and image distance for the objective lens. Ordinarily the object is very close to the focus, resulting in an image whose distance from the  objective is much larger than the focal length $$ { f }_{ 1 }$$. Thus $$ { S }_{ 1 }$$ is approximately equal to $$ { f }_{ 1 }$$ and $$ { m }_{ 1 }$$ =$$ -\dfrac { { S }_{ 1 }^{ ' } }{ { f }_{ 1 } } $$, approximately. The angular magnification of the eyepiece from $$ { M }=-\dfrac { { u }^{ ' } }{ u } =\dfrac { { y }/{ f } }{ { y }/{ 25 } } =\dfrac { 25 }{ f } $$ (f in centimeters) is $$ { M }_{ 2 }=25cm/{ f }_{ 2 },$$ Where $$ { f }_{ 2 }$$ is the focal length of the eyepiece, considered as a simple lens. Hence the overall magnification M of the compound microscope is, apart from a negative sign, which is customarily ignored,
$$ { M }={ m }_{ 1 }{ M }_{ 2 }=\dfrac { \left( 25cm \right) { S }_{ 1 }^{ ' } }{ f } $$
1. What is the resolving power of the instrument whose magnifying power is given in the passage?

Two coherent points sources $$S_1$$ and $$S_2$$ vibrating in phase emit light of wavelength $$\lambda$$. The separation between them is $$2\lambda$$. The light is collected on a screen $$\sum$$ placed at a distance $$D>>\lambda$$ from the slit $$S_1$$ as shown, in the fig. Find the minimum distance so that intensity at $$P$$ is equal to intensity at $$O$$.

Anti-nodal curves represent the points joining:

An electron beam and a proton beam have the same energy per particle. The wavelength associated with the electron beam is 24 A$$^{\circ}$$.The wavelength associated with the proton beam would approximately be

Using visible light what is the shortest wavelength which can be measured?

ASSERTION: Resolving power of telescope is more if the diameter of the objective lens is more.
REASON:Objective lens of large diameter collects more light.

A CD(Compact disc ) is read from the bottom by a semiconductor laser with wavelength $$700nm$$ passes through a plastic substrate of refractive index $$1.8$$. When the beam encounters $$0$$ pit, part of the beam is reflected from the pit and part from the flat region. These two beams interfere with each other. What must be the minimum depth of the pit, So that part of the beam reflected from the pit and part reflected from the flat surface cancel out? (This cancellation allows the player to recognize beginning and end of a pit).

When a drop of oil is spread on a water surface, it displays beautiful colors in daylight because of 

When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of