Wave Optics Test

Result

Wave Optics Test - 54

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

If $$I_0$$ is the intensity of the principal maximum in the single slit diffraction pattern, then what will be its intensity when the slit width is doubled

A
$$I_0$$

B
$$\dfrac{I_0}{2}$$

C
$$2I_0$$

D
$$4I_0$$

Solution

$$(I_0)$$ Maximum independent of slit width. Thus intensity will remains unchanged.
Question 2
1 / -0

The separation between two coherent point sources is $$3 \ \lambda$$. On a line perpendicular to $$S_1S_2$$ and passing through $$S_2$$. Find the smallest distance where minimum of intensity occurs:

A
$$\cfrac {11 \ \lambda}{20}$$

B
$$\cfrac { \lambda}{2}$$

C
$$\cfrac {9 \ \lambda}{20}$$

D
$$\cfrac {35 \ \lambda}{4}$$

Solution

From the above,

$$d=3\lambda$$

Condition for minima,

$$\Delta x=(n+1)\dfrac{1}{\lambda}$$

For $$n=3$$

$$\Delta x=\dfrac{5\lambda}{2}$$. . . . . . . .(1)

Path difference, $$S_1P-S_2P=\dfrac{5}{2}\lambda$$

$$\dfrac{5}{2}\lambda=\sqrt{(d)^2+y^2}-y$$

$$\dfrac{5}{2}\lambda=\sqrt{(3\lambda)^2+y^2}-y$$

$$\sqrt{(3\lambda)^2+y^2}=\dfrac{5}{2}\lambda+y$$

$$(3\lambda)^2+y^2=(\dfrac{5}{2}\lambda+y)^2$$

$$y^2+9\lambda ^2=\dfrac{25}{4}\lambda^2+y^2+5\lambda y$$

$$9\lambda ^2-\dfrac{25}{4}\lambda ^2=5\lambda y$$

$$5y=\dfrac{36\lambda-25\lambda}{4}$$

$$5\lambda=\dfrac{11}{4}\lambda$$

$$y=\dfrac{11}{20}\lambda$$

The correct option is A.
Question 3
1 / -0

The limit of resolution of 100 cm telescope for $$\lambda=5000 \mathring {A}$$ is approximately equal to

A
0.13"

B
0.3"

C
1"

D
1.4"

Solution

Given,
$$\lambda=5000\times 10^{-10}=5\times 10^{-7}m$$
$$D=100cm=1m$$
The limit of resolution of telescope
$$\theta=\dfrac{1.22\lambda}{D}$$
$$\theta=\dfrac{1.22\times 5\times 10^{-7}}{1}$$
$$\theta=6.1\times 10^{-7} radian$$
$$\theta=0.13''$$
The correct option is A.
Question 4
1 / -0

A plane wave front of wave length $$6000A$$ is incident upon a slit of $$0.2mm$$ width, which enables fraunhofer's diffraction pattern to be obtained on a screen $$2m$$ away. Width of the central maxima in mm will be

A
$$10$$

B
$$12$$

C
$$8$$

D
$$2$$

Solution

Given,
$$\lambda=6000\times 10^{-10}m$$
$$d=0.2mm$$
$$D=2m$$
Fringe width, $$\beta=\dfrac{\lambda D}{d}$$
$$\beta=\dfrac{6000\times 10^{-10}\times 2}{0.2\times 10^{-3}}=6mm$$
Width of the central maxima,
$$W=2\beta=2\times 6=12mm$$
The correct option is B.
Question 5
1 / -0

Parallel beam is

A
produced by a source at infinity

B
produced by a source at finite distance

C
produced by a virtual source

D
None of these

Solution

According to Newton's corpuscular theory of light, light is composed of very tiny, elastic and rigid particles called corpuscules. When this corpuscules enters into our eye, we get the sensation of light or sensation of vision. This theory explains that each of parallel beam is coming from a source situated at infinity.
Question 6
1 / -0

In Y.D.S.E. how many maxima can be obtained on the screen if wave length of light used is $$200 mm$$ & $$d = 700 mm$$ :-

A
$$12$$

B
$$7$$

C
$$18$$

D
$$14$$

Solution
Question 7
1 / -0

Newton's corpuscular model of light.

A
successfully explain the rectilinear propagation of light, reflection of light and refraction of light

B
does not explain the phenomena of interference of light, diffraction of light and polarisation of light

C
is based upon particle theory of light

D
None of the above

Solution

According to Newton's corpuscular theory of light, light is composed of very tiny, elastic and rigid particles called corpuscules. When this corpuscules enters into our eye, we get the sensation of light or sensation of vision. This theory was able to successfully explain the rectilinear propagation of light, reflection of light and refraction of light
Question 8
1 / -0

In the case of parallel beam,

A
intensity gradually increases

B
intensity gradually decreases

C
intensity remains constant

D
None of these

Solution

According to Huygens' theory, light always propagate in form of wavefront where all particles are in same phase. So intensity of light is maximum at wavefront and zero otherwise. So answer is D.
Question 9
1 / -0

According to Huygen's theory of light

A
light is stream of photon

B
light is wave

C
light behaves as particle

D
None of the above

Solution

According to Huygens' theory, light always propagates in the form of wavefront. Wavefront is an imaginary surface on which all particles vibrate in the same phase. Huygens' theory of light refraction is based on the concept of the wave-like nature of light. So according to this theory, light is wave.
Question 10
1 / -0

A beam of plane polarised light falls on a polarizer which rotates about axis of ray with angular velocity $$\omega $$. The energy passing through polrizer in one revolution if incident power is P is :

A
$$ \dfrac {\pi P} {2\omega} $$

B
$$ \dfrac {\pi P} {\omega} $$

C
$$ \dfrac {2 \pi P} {\omega} $$

D
$$ \dfrac {3 \pi P} {2\omega} $$

Solution

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Wave Optics Test - 54

Result

Wave Optics Test - 54

Score

-

Rank

-

SHARING IS CARING

Question 1

$$I_0$$

$$\dfrac{I_0}{2}$$

$$2I_0$$

$$4I_0$$

Solution

Question 2

$$\cfrac {11 \ \lambda}{20}$$

$$\cfrac { \lambda}{2}$$

$$\cfrac {9 \ \lambda}{20}$$

$$\cfrac {35 \ \lambda}{4}$$

Solution

Question 3

0.13"

0.3"

1"

1.4"

Solution

Question 4

$$10$$

$$12$$

$$8$$

$$2$$

Solution

Question 5

produced by a source at infinity

produced by a source at finite distance

produced by a virtual source

None of these

Solution

Question 6

$$12$$

$$7$$

$$18$$

$$14$$

Solution

Question 7

successfully explain the rectilinear propagation of light, reflection of light and refraction of light

does not explain the phenomena of interference of light, diffraction of light and polarisation of light

is based upon particle theory of light

None of the above

Solution

Question 8

intensity gradually increases

intensity gradually decreases

intensity remains constant

None of these

Solution

Question 9

light is stream of photon

light is wave

light behaves as particle

None of the above

Solution

Question 10

$$ \dfrac {\pi P} {2\omega} $$

$$ \dfrac {\pi P} {\omega} $$

$$ \dfrac {2 \pi P} {\omega} $$

$$ \dfrac {3 \pi P} {2\omega} $$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.