Wave Optics Tes...

In a Youngs double-slit experiment, let $$\beta$$ be the fringe width, and let $${l}_{0}$$ be the intensity at the central bright fringe. At a distance $$x$$ from the central bright fringe, the intensity will be:

In Young's double slit experiment, the slits are $$2$$ mm apart and are illuminated by photons of two wavelengths $$\lambda_1=12000\overset{o}{A}$$ and $$\lambda_2=10000\overset{o}{A}$$. At what minimum distance from the common central bright fringe on the screen $$2$$ m from the slit will a bright fringe from one interference pattern coincide with a bright fringe from the other?

A source and a listener arc moving towards each other with a speed $$(1/10)th$$ that of sound. If frequency of sound emitted by the source is $$f$$ than the frequency heard by listener will be

In $$YDSE$$, the central bright fringes is at mid-point of screen. On both side of mid-point fringes are obtained. Number of fringes on either side is $$n_1$$, with air between slits and screen. When water $$^a\mu_{W}=\dfrac {4}{3}$$ is filled $$'n_2'$$, number of fringes are obtained on either side, then $$n_{2}$$ is

Two coherent sources of wavelengths $$4.8\times {10}^{-7}m$$ produce a steady interference pattern
The path difference corresponding to $$10th$$ order maximum will be

In a YDSE experiment if a slab whose refractive index can be varied is placed in front of one of the slits then the variation of resultant intensity at mid-point of screen with $$\mu(\mu\ge 1)$$ will be best represented by (assume  slits of equal width and there is not absorption by slab)

In a Young's double slit experiment , a slab of thickness $$1.2 \mu m$$ and refractive index $$1.5$$ is placed in front of one slit and another slab of thickness t and refractive index $$2.5$$ is placed in front of the second slit. If the position of the central fringe remains unaltered, then the thickness is

A source of sound emitting a note of frequency $$500\ Hz$$ moves towards an observer with a velocity $$v$$ equal to half the velocity of sound. If the observer moves away from the source with the same velocity, then the apparent frequency heard by the observer is

Consider that the screen starts moving towards right with speed $$v$$. At $$t=0$$, second maxima was lying at point $$P$$. At what time $$t$$, first minima will be lying at the point $$P$$?

A source of sound of frequency $$258\ Hz$$ is moving rapidly towards a wall with a velocity of $$5m/s$$. How many beats per second will be heard by the observer situated on the source itself if sound travels at a speed of $$330\ m/s$$