Dual Nature of Radiation and Matter Test

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Dual Nature of Radiation and Matter Test - 17

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Weekly Quiz Competition

Question 1
1 / -0

Two different sources of light A and B have wavelength $$0.7\mu m$$ and $$0.3\mu m$$ respectively. Then which of the following statement is true.

A
A has greater energy than B

B
B has greater energy than A

C
Both has equal energy

D
None of the above

Solution

$$\lambda_A=0.7\times 10^{-6}m$$,
$$\lambda_B=0.3\times 10^{-1}m$$
$$E=\dfrac {hc}{\lambda}$$
$$\lambda_A > \lambda_B$$
Hence, E_A < E_B
Question 2
1 / -0

The effective mass of photon in microwave region, visible region and x -ray region is in the following order:

A
Microwave > X-rays > Visible

B
X-rays > Microwave > Visible

C
Microwave > Visible> X-ray

D
X-rays > Visible > Microwave

Solution

Relation between wavelength and mass is given as $$ \lambda = \dfrac {h} {mv}$$
Since h and v are constant, higher the wavelength less the mass wavelength of x ray is least followed by visible ray and then microwave.
So effective mass of photon follows $$X-rays>Visible>Microwave$$
So, the answer is option (D).
Question 3
1 / -0

A particle of mass 1 mg has the same
wavelength as an electron moving with a
velocity of $$3\times 10^{6}ms^{-1}$$
The velocity of the
particle is :
$$\left ( mass of electron =9.1\times 10^{-31}kg \right )$$

A
$$3\times 10^{-31}ms^{-1}$$

B
$$2.7\times 10^{-21}ms^{-1}$$

C
$$2.7\times 10^{-18}ms^{-1}$$

D
$$9\times 10^{-2}ms^{-1}$$

Solution

de-Broglie wavelength associated with electron
moving with velocity ,
$$\lambda = \frac{h}{mv}$$
so, $$\lambda_{e} = \frac{h}{9.1\times10^{-31}\times 3 \times10^{6}}$$
Wavelength of particle of mass 1 mg moving with velocity .
$$\lambda_{p} = \frac{h}{10^{-3}\times v}$$
As given,$$\lambda_{e} = \lambda_{p} $$
$$\Rightarrow \frac{h}{10^{-3}\times v}=\frac{h}{9.1\times10^{-31}\times 3 \times10^{6}}$$
$$v=\frac{27.3 \times10^{-25}}{10^{-3}}m/s=2.73 \times10^{-21}m/s$$
Question 4
1 / -0

The number of photo electrons emitted for light of a frequency v (higher than the threshold frequency $$v_0$$) is proportional to :

A
Frequency of light (v)

B
$$v-v_0$$

C
$$Threshold\;frequency\;(v_0)$$

D
Intensity of light

Solution

No. of photo electrons emitted is independent of frequency but depends on intensity.
Question 5
1 / -0

The correct curve between the stopping potential (V) and intensity of incident light (I) is

A

B

C

D

Solution

Stopping potential is a characteristic of the material, hence it does not change with intensity of incident light. Hence it has a constant plot against intensity.
Question 6
1 / -0

Albert Einstein got a nobel prize in physics for his work on:

A
Special theory of relativity

B
General theory of relativity

C
Photoelectric effect

D
Theory of specific heats

Solution

In 1905, Albert Einstein extended Planck's hypothesis to explain the photoelectric effect, which is the emission of electrons by a metal surface when it is irradiated by light or more-energetic photons.
Question 7
1 / -0

The photoelectric effect was successfully explained by

A
Hertz

B
Planck

C
Millikan

D
Einstein

Solution

Einstein showed mathematically, the energy of the incoming photons was precisely related to the frequency or wavelength of the light shining and equal to the energy of the electrons they ejected. Einstein's explanation of the photoelectric effect was powerful evidence that energy could exist only in fixed amounts called quanta.
So, the answer is option (D).
Question 8
1 / -0

Einstein's photoelectric equation is

A
$$hv=\frac {W_0}{w}-mv^2$$

B
$$hv=W_0-\frac {1}{2}mv^2$$

C
$$hv=W_0+\frac {1}{2}mv^2$$

D
$$hv=\frac {1}{2}m^2-W_0$$

Solution

K.E. of the photo-electrons = (Energy obtained from the Photon) – (energy used to escape the metallic surface)
Rearranging the equation gives us option c as the correct answer.
Question 9
1 / -0

Louis de -Broglie is credited for his work on

A
Theory of relativity

B
Electromagnetic theory

C
Matter waves

D
Law of distribution of velocities

Solution

De Broglie, in his 1924 PhD thesis, proposed that just as light has both wave-like and particle-like properties, electrons also have wave-like properties. Here he worked on matter waves. Hence option C is the correct answer.
Question 10
1 / -0

Name the unit in which work function of a metal is generally expressed.

A
Newton

B
Kilojoule

C
eV

D
V

Solution

Work function in generally expressed in electron volt.
So, the answer is option (C).

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Dual Nature of Radiation and Matter Test - 17

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Dual Nature of Radiation and Matter Test - 17

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Question 1

A has greater energy than B

B has greater energy than A

Both has equal energy

None of the above

Solution

Question 2

Microwave > X-rays > Visible

X-rays > Microwave > Visible

Microwave > Visible> X-ray

X-rays > Visible > Microwave

Solution

Question 3

$$3\times 10^{-31}ms^{-1}$$

$$2.7\times 10^{-21}ms^{-1}$$

$$2.7\times 10^{-18}ms^{-1}$$

$$9\times 10^{-2}ms^{-1}$$

Solution

Question 4

Frequency of light (v)

$$v-v_0$$

$$Threshold\;frequency\;(v_0)$$

Intensity of light

Solution

Question 5

Solution

Question 6

Special theory of relativity

General theory of relativity

Photoelectric effect

Theory of specific heats

Solution

Question 7

Hertz

Planck

Millikan

Einstein

Solution

Question 8

$$hv=\frac {W_0}{w}-mv^2$$

$$hv=W_0-\frac {1}{2}mv^2$$

$$hv=W_0+\frac {1}{2}mv^2$$

$$hv=\frac {1}{2}m^2-W_0$$

Solution

Question 9

Theory of relativity

Electromagnetic theory

Matter waves

Law of distribution of velocities

Solution

Question 10

Newton

Kilojoule

eV

V

Solution

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