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Dual Nature of Radiation and Matter Test - 22

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Dual Nature of Radiation and Matter Test - 22
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  • Question 1
    1 / -0
    The mass of a photon electron is
    Solution

    The mass of a photon electron is $$9.1\times 10^{-31}\ \ kg$$.
  • Question 2
    1 / -0
    Photon and electron are given energy $$\left( {{{10}^{ - 2}}J} \right).$$ Wavelengths associated with photon and electeon are $${\lambda _{ph}}$$ and $${\lambda _{el}},$$ then correct statement will be
    Solution
    The wavelength of the photon will be greater than that of the electron because the mass of a photon is less than that of an electron.
    $$\Rightarrow \lambda_{ph} > \lambda_el$$
  • Question 3
    1 / -0
    Mark the correct option of source which is associated with a line emission spectrum :
    Solution
    • Neon lighting consists of brightly glowing, electrified glass tubes or bulbs that contain rarefied neon or other gases. 
    • Neon lights are a type of cold cathode gas-discharge light.
    • Hence neon street sign are associated with line emission spectrum
    • Option B is the right answer
  • Question 4
    1 / -0
    A particle at rest decays into two particles of masses 2 m and 
    3 m having non-zero velocities. The ratio of DE-Imbroglio wavelength of the particle is
    Solution

    $$\lambda  \propto {1 \over m}$$

    $${{{\lambda _1}} \over {{\lambda _2}}} = {{{m_2}} \over {{m_1}}} = {{3m} \over {2m}}$$

    $$ = 3:2$$

  • Question 5
    1 / -0
    Photoelectric effect was successfully explained first by
    Solution

    Photoelectric effect was successfully explained first by Einstein.
  • Question 6
    1 / -0
    Einstein got Nobel prize on which of the following works
    Solution
    Albert Einstein was awarded Nobel prize in $$1921$$ for discovering the photoelectric effect.
  • Question 7
    1 / -0
    Kinetic energy with the electrons are emitted from the metal surface due to photoelectric effect is
    Solution
    Kinetic energy of photoelectrons depends on the frequency of incident radiation and and is independent of the intensity of illumination.
  • Question 8
    1 / -0
    The work function of aluminium is $$4.2\ eV$$.If two photons each of energy $$3.5\ eV$$ strike an electron of aluminium, then emission of electrons will be
    Solution
    For the emission of electrons incident energy of each photon must be greater than the work function (thresholds energy). soo, in this case, the emission of electrons will be not possible.
  • Question 9
    1 / -0
    With the decrease in the wave length of the incident radiation the velocity of the photoelectrons emitted from a given metal
    Solution
    As wavelength decrease , frequency increases and hence K.E of photoelectrons increases , thereby increasing the velocity.
  • Question 10
    1 / -0
    The deBroglie wavelength associated with a particle of mass m, moving with a velocity $$'v\ '$$ and energy E is given by
    Solution
    We know,
    $$\dfrac{1}{2}mv^{2}=E$$
    $$mv=\sqrt{2Em}$$
    so debroglie wavelength $$(\lambda)=\dfrac{h}{mv}$$
                                                      $$=\dfrac{h}{\sqrt{{2E}m}}$$
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