Dual Nature of ...

If $$E_{1},E_{2}$$ and $$E_{3}$$ are the kinetic energies of a proton, $$\alpha$$ -particle and deuteron respectively, which all have the same wavelength, then 

If electron is having a wavelength of 100 $$A^{0}$$, then momentum is $$(gm \  cm \ s^{-1})$$ units

The de-broglie wavelength of an electron and the wavelength of a photon are same. The ratio between the energy of the photon and the momentum of the electron is

The wavelength corresponding to a beam of electrons whose kinetic energy is 100 eV is 
($$h=6.6\times 10^{-34}$$ Js, $$1eV=1.6\times10^{-19}J$$ J,$$m_{e}= 9.1 \times 10^{-31}$$ kg)

A proton and an alpha particle are accelerated through the same potential difference. The ratio of wavelengths associated with proton and alpha particle respectively is :

A charged particle drops through V volts. Match the de Broglie wavelength for given particles 
 Particle                                                                         $$\lambda\ in\ A^o$$

If $$\lambda_{0} $$ is the de Broglie wavelength for a proton accelerated through a potential difference of 100V, the de Broglie wavelength for $$\alpha $$ -particle accelerated through the same potential difference is

If the energy of a particle is reduced to one fourth, then the percentage increase in its de Broglie wavelength will be :

Two particles of masses m and 2m have equal kinetic energies. Their de Broglie wavelengths are in the ratio of 

If the velocity of a particle is increased three times, then the percentage decrease in its de Broglie wavelength will be :