Dual Nature of ...

In a photocell circuit the stopping potential, $$v_0$$ , is a measure of the maximum kinetic energy of the photoelectrons. The following graph shows experimentally measured values of stopping potential versus frequency v of incident light.
The values of Planck's constant and the work function as determined from the graph are (taking the magnitude of electronic charge to be $$ e= 1.6 \times 10^{-19} C $$ )

A proton and an alpha particle are subjected to same potential difference $$V$$. Their de-Broglies wavelengths $$\lambda_{p}, \lambda_{\alpha}$$ will be in the ratio.

A proton and an alpha particle both are accelerated through the same potential difference. The ratio of corresponding de-Broglie wavelengths is :

The de Broglie wavelength of an electron is $$0.4\times { 10 }^{ -10 }m$$ when its kinetic energy is $$1.0keV$$. Its wavelength will be $$1.0\times { 10 }^{ -10 }m$$, when its kinetic energy is

A particle is dropped from a height '$$H$$'. The de Broglie wavelength of the particle depends on height as

A photon will have less energy, if its :

An isotropic point source emits light with wavelength $$500 nm$$. The radiation power of the source is $$P=10 W$$. Find the number of photons passing through unit area per second at a distance of $$3 m$$ from the source.

A photon and an electron possesses same de-Broglie wavelength. Given that C$$=$$ speed of light and v$$=$$ speed of electron, which of the following relation is correct? (Here, $$E_e=K.E$$ of electron, $$E_{Ph}=K.E$$ of photon, $$P_e=$$ momentum of electron, $$P_{ph}=$$ momentum of photon).

The postulate on which the photoelectric equation is derived is :

The de-Broglie wavelength '$$\lambda$$' of a particle