Dual Nature of ...

A particle 'P' is formed due to a completely inelastic collision of particles 'x' and 'y' having de-Broglie wavelengths $$'\lambda_x'$$ and $$'\lambda_y'$$ respectively. If x and y were moving in opposite directions, then the de-Broglie wavelength of 'P' is?

A particle of mass M at rest decays into two particles of masses $$m_{1}$$ and $$m_{2}$$, having non-zero velocities. The ration of the de-Broglie wavelengths of the particles, $$I_{1}$$/$$I_{1}$$ is

If a proton and electron have same de Broglie wavelength, then

Two particle are moving perpendicular to each other with de-Broglie wave length $$\lambda_1$$ and $$\lambda_2$$. If they collide and stick together, then the de-Broglie wave length of system after collision is:

In a H-atom, an electron is in $$2^{nd}$$ excited state and its radius $$= 4.75 \mathring{A}$$. Calculate de-broglie wavelength of the electron.

Consider an electron in a hydrogen atom, revolving in its second excited state (having radius $$4.65 \mathring{A}$$). The de-Broglie wavelength of this electron is:

For the same speed, de Broglie wavelength.

Radiation of frequency, $$v$$, are incident on a photosensitive metal. The maximum kinetic energy of photoelectric is $$E$$. When the frequency of the incident radiation is doubled, what is the maximum kinetic energy of the photoelectrons? 

Two particles A and B of same mass have their total energies $$E_A$$ and $$E_B$$  in the ratio $$E_A:E_B=1:2$$. Their potential energies $$U_A$$ and $$U_B$$ are in the ratio $$U_A:U_B=1:2$$ . If $$\lambda_A$$ and $$\lambda_B$$ are their de-Broglie wavelengths, then $$\lambda_A:\lambda_B$$ is

The de-Broglie wavelength of electron in $$3^{rd}$$ orbit of $$He^{+1}$$ ion is approximately.