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Dual Nature of Radiation and Matter Test - 74

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Dual Nature of Radiation and Matter Test - 74
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  • Question 1
    1 / -0
    An electron of mass m and a photon have same energy E.The ratio of de-Broglie wavelengths associated with them is
    Solution

  • Question 2
    1 / -0
    What should be the ratio of the energies of radiations whose wavelengths are  $$3000 \mathring { A }$$   and  $$6000 \mathring { A }$$ ?
    Solution
    Area of a sector $$=\cfrac{radian}{2\pi}\times (\pi {r}^{2})$$
    $$\cfrac { \cfrac { 11 }{ 6 } \pi  }{ 2\pi  } \times \pi { r }^{ 2 }=33\pi$$
    $$\pi { r }^{ 2 }$$ area of circle (A)
    $$\cfrac{11}{12}\times A=33\pi$$
    $$A=\cfrac{33\times 12}{11}\pi$$
    $$A=36\pi$$ unit square is area of circle
  • Question 3
    1 / -0
    Mass of a photon with wavelength $$3.6A^{o}$$ moving with velocity of light is 
    Solution

  • Question 4
    1 / -0
    An $$\alpha$$ -particle is accelerated through a potential difference of V volts from rest.The de-Broglie's  was associated with it is-
    Solution
    The potential energy due to potential difference $$V$$ will provide Kinetic energy to $$\alpha-$$particle.
    Mass of $$\alpha-$$ particle $$=4\times1.67\times10^{-27}kg= 6.68\times10^{-27}kg$$
    Charge of  $$\alpha-$$ particle $$=2\times1.6\times10^{-19}C = 3.2\times10^{-19}C$$
    $$\dfrac12mv^2 = qV$$

    $$v = \sqrt{\dfrac{2qV}{m}} = \sqrt{\dfrac{2\times 3.2\times10^{-19}V}{6.68\times10^{-27}}}= 0.978\times10^4\sqrt{V}$$ $$m/s$$

    de-Broglie wavelength is, $$\lambda =\dfrac{h}{p} = \dfrac{h}{mv}$$

    $$\lambda = \dfrac{6.6\times10^{-34}}{6.68\times10^{-27}\times 0.978\times10^4\sqrt{V}}$$

    $$\lambda = \dfrac{0.101}{\sqrt{V}} $$
  • Question 5
    1 / -0
    With what velocity must an electron travel so that its momentum is equal to that of a photon of wavelength $$\lambda$$ = 5200$$\overset { \circ  }{ A } $$?
    Solution

  • Question 6
    1 / -0
    Light of frequency $$7.21 \times {10^{14}}Hz$$ is incident on a metal surface. The maximum speed of the photoelectrons  emitted is $$6.0 \times {10^5}m\,{s^{ - 1}}$$. what is the threshold frequency for the photoemission of electrons?
    Solution

  • Question 7
    1 / -0
    Sodium and copper have work functions 2.3 eV and 4.5 eV respectively. Then the ratio of the wavelengths . nearest to-
  • Question 8
    1 / -0
    What should be the approximate K.E. of an electron so that its de -Broglie wavelength is equal to the wavelength of x -ray of maximum energy produced in an x -ray tube operating at 24,800 V? $$(h = 6.6 /\times 10^{-34}J - sec$$, mass of electron $$m =9.1 \times 10^{-31} kg)$$ (give answer in $$10^2 eV).$$
    Solution

  • Question 9
    1 / -0
    If the first Bohr's orbit of hydrogen is $$r_{ \circ  },$$ the de-Broglie wavelength of electron in $${ 3 }^{ rd }$$ orbit $$He^{ + }$$ is about
    Solution

  • Question 10
    1 / -0

    Find the velocity of electrons liberated by electromagnetic radiation of wavelength $$ \lambda =18.0$$ nm from stationary $$He^+$$ ions in the ground state.




    Solution

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