Self Studies

Dual Nature of ...

TIME LEFT -
  • Question 1
    1 / -0

    The speed of a proton is $$\dfrac { c }{ 20 } .$$ The wavelength associated with it will be($$ h= 6.6 \times 10^{-34} Js$$) :

  • Question 2
    1 / -0

    The ratio of deBroglie wavelengths of a  proton  and an alpha particle of same energy is

  • Question 3
    1 / -0

    A particle is moving with 3 times faster than speed of $$ e ^ { - }$$. If the ratio of wavelength of particle & electron is $$ 1.8 \times 10 ^ { - 4 } $$ then particle is :

  • Question 4
    1 / -0

    The wavelength of de-Broglie waves associated with neutrons at room temperature T is (E=kT)

  • Question 5
    1 / -0

    In the above diagram if V represent the stopping potential and wavelength of light is $$\lambda $$ if $${ V }_{ 2 }>{ V }_{ 1 }$$ then

  • Question 6
    1 / -0

    The electron level which allows the hydrogen to absorb photons but not to emit is 

  • Question 7
    1 / -0

    An electron, proton and alpha particle have same
    kinetic energy. The corresponding de-Broglie wavelength would have the
    following relationship: 

  • Question 8
    1 / -0

    De broglie wave length of uncharged particle depends on 

  • Question 9
    1 / -0

    When a particle is restricted to move along x-axis between x = 0 and x = a, where a is of nanometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x=0 and x=a. The wavelength of this standing wave is related to the linear momentum p of the particle according to the de Broglie relation. The energy of the particle of mass m is related to its linear momentum as E =$$\frac{\rho^2}{2m}$$. Thus, the energy of the particle can be denoted by a quantum number n taking values 1, 2, 3, . (n = 1, called the ground state) corresponding to the number of loops in the standing wave. Use the model described above to answer the following three questions for a particle moving in the line x = 0 to x = a. Take h = $$6.6 \times 10^{-34} \ Js $$ and $$ e =1.6 \times 10^{-19} $$ C.
    If the mass of the particle is $$m = 1.0 \times 10^{-30}$$ kg and a = 6.6 nm, the energy of the particle in its ground state is closest to

  • Question 10
    1 / -0

    The stopping potentials are $$V_1$$ and $$V_2$$ with incident lights of wavelength $$\lambda_1$$ and $$\lambda_2$$ respectively. Then $$V_1 - V_2 =$$

Submit Test
Self Studies
User
Question Analysis
  • Answered - 0

  • Unanswered - 10

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Submit Test
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now