Dual Nature of Radiation and Matter Test

Result

Dual Nature of Radiation and Matter Test - 83

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Weekly Quiz Competition

Question 1
1 / -0

Energy of an electron is given by $$E=-2.178\times { 10 }^{ -18 }J\left( \dfrac { { Z }^{ 2 } }{ n^{ 2 } } \right) .$$ Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be ($$h=6.62\times { 10 }^{ -34 }Js$$ and $$c=3.0\times { 10 }^{ 8 }{ ms }^{ -1 }$$)

A
$$8.500\times { 10 }^{ -7 }m$$

B
$$1.214\times { 10 }^{ -7 }m$$

C
$$2.816\times { 10 }^{ -7 }m$$

D
$$6.500\times { 10 }^{ -7 }m$$
Question 2
1 / -0

If the total energy of an electron in a hydrogen atom in excited state is -3,4 eV, then the de Broglie wavelength of the electron is :-

A
3.3*$${ 10 }^{ -10 }m $$

B
6.6×$${ 10 }^{ -10 }m $$

C
3.3*$${ 10 }^{ 10 }m $$

D
9.3*$${ 10 }^{ -12 }m $$

Solution
Question 3
1 / -0

The uncertainty in location of circulating electron is equal to its de Broglie wave length. The minimum present error in its measurement of velocity under this circumstance will be approximately.

A
$$4$$

B
$$8$$

C
$$18$$

D
$$22$$

Solution
Question 4
1 / -0

Calculate the wavelength (in nanometer) associated with a proton moving at $$1.0\times { 10 }^{ 3 }m{ s }^{ -1 }$$
(Mass of proton = $$1.67\times { 10 }^{ -27 }kg$$ and $$h=6.63\times { 10 }^{ -34 }Js$$)

A
0.032 nm

B
0.40 nm

C
2.5 nm

D
14.0 nm

Solution
Question 5
1 / -0

The kinetic energy of one electron is $$2.8\times { 10 }^{ -13 }J.$$ What is the de-Broglie wavelength (Mass of electron $$9.1\times { 10 }^{ -13 }$$ kg)

A
$$9.25\times { 10 }^{ -13 }m$$

B
$$9.25\times { 10 }^{ -16 }m$$

C
$$9.25\times { 10 }^{ -8 }m$$

D
$$18.5\times { 10 }^{ -13 }m$$

Solution
Question 6
1 / -0

Ionization Energy per mole of Na atom is $$ 4.946 \times 10^{2} \mathrm{kJ/mole} $$ . The wavelength of radiation sufficient to ionize sodium atom is

A
$$ 4 \times 10^{24} n m $$

B
$$ 24.2\ nm$$

C
$$ 242\ nm$$

D
$$ 400\ nm$$

Solution
Question 7
1 / -0

Calculate kinetic energy of an electron emitted from a surface of potassium metal $$(work function=3.62\times{ 10 }^{ -16 }J)$$ by light of wavelength $$3\times10^{ -10 }$$m

A
$$3 \times 10 ^ { - 16 } J$$

B
$$3 \times 10 ^ { - 18 } { J }$$

C
$$3 \times 10 ^ { - 20 } { J }$$

D
$$3 \times 10 ^ { - 22 } { J }$$

Solution
Question 8
1 / -0

If $$ \lambda_{0} $$ is the threshold wavelength for photoelectric emission, $$\lambda$$ wavelength of light falling on the surface of the metal, and m is the mass of an electron, then de Broglie wavelength of the emitted electron is :

A
$$ \sqrt{ \frac{ h\lambda \lambda_0}{ 2mc(\lambda_0 - \lambda) }} $$

B
$$ \sqrt{ \frac{ h\lambda \lambda_0}{ mc(\lambda_0 - \lambda) }} $$

C
$$ \sqrt{ \frac{ h\lambda \lambda_0}{ 2mc(\lambda_0 + \lambda) }} $$

D
$$ \sqrt{ \frac{ h\lambda \lambda_0}{ mc(\lambda_0 + \lambda) }} $$
Question 9
1 / -0

The energy required to break one mole of Cl-Cl bonds is $$242kJ/mol $$. The longest wavelength of light capable of breaking a single Cl-Cl bond is

A
494 mn

B
594 mn

C
640 mn

D
700 mn

Solution
Question 10
1 / -0

A gas absorbs a photon of 355 nm and emits at two wavelengths If one of the emission is at 680 nm, The other is at

A
1035 nm

B
325 nm

C
743 nm

D
518 nm

Solution