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Nuclei Test - 40

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Nuclei Test - 40
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  • Question 1
    1 / -0
    Find out the product of a $$Co^{60}$$ atom that undergoes one beta plus decays?
    Solution
    $$\beta^+$$ decay: $$^{60}_{28}Co \rightarrow$$ $$^{A}_{Z}X$$ $$+$$ $$^0_{+1}e$$ 
    In a nuclear reaction, the mass number as well as the atomic number is conserved.
    $$\therefore$$  $$60 = 0 + A$$ $$\implies A =60$$
    Also, $$27 = 1 + Z$$  $$\implies Z = 26$$
    Thus, the product of the reaction is iron-60  i.e $$^{60}_{26}Fe$$.
  • Question 2
    1 / -0
    chlorine atom whose nucleus contains $$17$$ protons and $$20$$neutrons. Find out the composition of the nucleus of an isotope of chlorine?
    Solution
    Isotope nucleus means that those nucleus has same protons number but different neutrons and mass number. Since chlorine has 17 protons so its isotope also will have 17 protons. Thus, option D will correct.   
  • Question 3
    1 / -0
    Compared to the parent nucleus, the daughter nucleus of a $$\beta$$ decay has:
    Solution
    When beta decay occurs, the atomic number of nucleus will increase by one unit and mass number will remain same. Thus, here the after beta decay the daughter nucleus has same mass number as product nuclei and one unit atomic number will increase than parent nuclei.    
  • Question 4
    1 / -0
    Which of the following particles may differ in numbers in neutral isotopes of the same element?
    Solution
    Isotopes of the same element have same number of protons but different number of neutrons.
    For example : $$^{35}_{17} Cl$$  and  $$^{37}_{17} Cl$$ are isotopes of each other.
    Both have $$17$$ protons but first $$Cl$$ has $$18$$ neutrons and other $$Cl$$ has $$20$$ neutrons.
  • Question 5
    1 / -0
    Six protons and six neutrons are brought together to form a carbon nucleus, but the mass of the carbon nucleus is less than the sum of the masses of the individual particles due to the mass defect, This deducted mass has been
    Solution
    Nuclear binding energy accounts for a noticeable difference between the actual mass of an atom's nucleus and its expected mass based on the sum of the masses of its non-bound components. The release in energy accounts for the stability of the bound atom. 
    Quantitatively, mass defect=$$\Delta M=M_{protons}+M_{neutrons}-M_{atom}$$
  • Question 6
    1 / -0
    Which of the following sometimes requires initiation from a neutron?
    Solution
    The process of splitting a nucleus is called nuclear fission. Uranium or plutonium isotopes are normally used as the fuel in nuclear reactors, because their atoms have relatively large nuclei that are easy to split, especially when hit by neutrons.

    When fission of an element takes place when hit by a neutron, further more neutrons are released. The additional neutrons released may also hit other uranium or plutonium nuclei and cause them to split. Even more neutrons are then released, which in turn can split more nuclei. This is called a chain reaction.
  • Question 7
    1 / -0
    When $$_{92}^{238}U$$ undergoes alpha decay, what is the daughter nucleus?
    Solution
    Let the daughter nucleus be $$^A_ZX$$.
    Alpha decay of Uranium :        $$^{238}_{92}   $$ $$ \rightarrow$$  $$^{A}_ZX $$ $$+$$  $$^4_2 He$$

    Conservation of mass number :     $$238 = A+ 4$$                $$\implies A = 234$$
    Conservation of atomic number :     $$92 = Z+2$$                   $$\implies Z =90$$
    Thus the daughter nucleus is   $$^{234}_{90} Th$$.
  • Question 8
    1 / -0
    On bombardment of neutron with boron, $$\alpha$$-particle is emitted. The product nuclei formed is:
    Solution
    $$_{3}Li^{7}$$
    $$^{10}B +n(0.025eV)\rightarrow_{4}He^{2}+_{7}Li^{3}+2.79MeV$$
    Lithium is formed on the bombardedment of neutron with boron by emitting $$\alpha$$ particles. 

  • Question 9
    1 / -0
    Which of the following isotopes is used for treatment of cancer?
    Solution
    $$Co^{60}$$
    Cobalt therapy or cobalt -60 therapy is the medical use of gamma rays from the radioisotope cobalt 60 to treat conditions such as cancer. 
  • Question 10
    1 / -0
    What is the molar mass of ammonium carbonate $${({NH}_{4})}_{2}{CO}_{3}$$?
    Solution
    $$(NH_4)_2CO_3$$ is the chemical formula of ammonium carbonate.

    $$N = 14 \times (2) = 28$$
    $$H = 1 \times (4 \times 2) = 8 $$
    $$C = 12 \times 1 = 12 $$
    $$O = 16 \times 3 = 48 $$

    Molar mass $$= 28 + 8 + 12 + 48 = 96\ g/mol$$
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