Nuclei Test

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Nuclei Test - 58

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following particles are constituents of the nucleus

A
Protons and electrons

B
Protons and electrons

C
Neutrons and electrons

D
Neutrons and positrons

Solution

The conclusion from Rutherford's experiment was that the majority of the mass of an atom is concentrated at its center called the nucleus. The nucleus therefore contains the two heaviest particles present in atom.
The protons and the neutrons are present in the nucleus which are bound together by strong nuclear forces which overcome the magnetic force of repulsion.
The electrons are found in orbitals outside the nucleus.
The correct answer is option (D).
Question 2
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Assertion : Separation of isotope is possible because of the difference in electron numbers of isotope
Reason : Isotope of an element can be separated by using a mass spectrometer.

A
If both assertion and reason are true and the reason is the correct explanation of the assertion.

B
If both assertion and reason are true but reason is not the correct explanation of the assertion.

C
If assertion is true but reason is false.

D
If the assertion and reason both are false

E
If assertion is false but reason is true.

Solution

The atomic number (number of electrons or protons) remain same in isotope. Isotope of an element can be separated on account of their different atomic weight by using mass spectrograph.
hence, option E is correct.
Question 3
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Which substance is discovered by the Prafulla Chandra Ray the inventor of Indian Chemical Industry ?

A
Sodium Chloride

B
Mercurus Nitrate

C
Nitre

D
Sal Ammonia

Solution
Question 4
1 / -0

The temperature required for the process of nuclear fusion is nearly:

A
$$1000 K$$

B
$$104 K$$

C
$$105 K$$

D
$$10^7K$$

Solution

To make fusion possible, a high temperature of approximately $$10^7 $$ K and high pressure is required.
Question 5
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The nucleus with highest binding energy per nucleon is:

A
$$^{238}_{92}U$$

B
$$^{4}_{2}He$$

C
$$^{16}_{8}O$$

D
$$^{56}_{26}Fe$$

Solution

$$_{26}Fe^{56}$$ as maximum binding energy per nucleon.
Question 6
1 / -0

If the mass of isotope $$^{7}_{3}Li$$ is $$7.016005\,u$$ and masses of H atom and a neutron are $$1.007825 \,u$$ and $$1.008665 \,u$$ respectively. The binding of Li nucleus is:

A
$$5.6 \,MeV$$

B
$$8.8\,MeV$$

C
$$0.42 \,MeV$$

D
$$39.2 \,MeV$$

Solution

$$\Delta m=[3 \times 1.00725\ u+4 \times 1.008665\ u ]- 7.016005\ u$$
$$\Delta m=[3.023475\ u+4.03466\ u ]- 7.016005\ u$$
$$\Delta m=[7.058135\ u - 7.016005\ u$$
$$\Delta m =0.042134\ u$$
$$E_B= \Delta m c^2$$
$$E_B=0.04213 \times 931.5 \dfrac{MeV}{c^2}c^2$$
$$E_B=39.24\ MeV$$
Question 7
1 / -0

On absorbing energy $$^{22}Ne$$ nucleus decays into a-particle and an unknown nucleus. The unknown nucleus is :

A
Oxygen

B
Boron

C
Silicon

D
Carbon

Solution

$$_{22}Ne \rightarrow 2(_2He^4)+_6C^{14}$$
So, unknown nucleus is carbon.
Question 8
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The binding energy per nucleon for a deuterium nucleus is $$1.115\ MeV$$. Mass defect for this nucleus is about :

A
$$2.23\ u$$

B
$$0.0024\ u$$

C
$$0.027\ u$$

D
Data is insufficient

Solution

For $$_1H^2$$ mass number $$A=2$$
Per nucleon binding energy of deuterium
$$\bar E_b=1.115\ MeV$$
Binding energy $$E_b=\bar E_b \times A$$
$$E_b=1.115\ MeV \times 2$$
$$E_b=2.230\ MeV$$
Mass number $$\Delta m=\dfrac{2.230}{931}$$
$$\Delta m=0.0024\ u$$
Question 9
1 / -0

In the decay of $$_{92}^{238}$$ into $$_{82}^{206}Pb$$ the number of emitted $$\alpha$$ and $$\beta$$ particles are respectively :

A
$$8,8$$

B
$$6,6$$

C
$$6,8$$

D
$$8,6$$

Solution

Number of $$\alpha-$$particles
$$=\dfrac{Difference\ in\ mass\ number}{4}$$
Number of $$\alpha-$$particles $$=\dfrac{238-206}{4}$$
$$=\dfrac{32}{4}$$
$$=8$$
Number of $$\beta$$particles $$=2$$(Number of $$\alpha$$-particles) $$- $$ difference in mass number
$$2(8)-(92-82)$$
$$=16-10$$
$$=6$$
Question 10
1 / -0

If the binding energy per nucleon in $$_{ 3 }^{ 4 }{ Li }$$ and $$_{ 3 }^{ 4 }{ He }$$ nuclei are $$5.60MeV$$ and $$7.06MeV$$ respectively, then in reaction $$_{ 1 }^{ 1 }{ Li }+_{ 3 }^{ 4 }{ He }\rightarrow 2\quad _{ 2 }^{ 4 }{ He }$$ energy of proton must be

A
$$28.24MeV$$

B
$$17.28MeV$$

C
$$1.46MeV$$

D
$$39.2MeV$$

Solution

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Re-Attempt Weekly Quiz Competition

Nuclei Test - 58

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Nuclei Test - 58

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Question 1

Protons and electrons

Protons and electrons

Neutrons and electrons

Neutrons and positrons

Solution

Question 2

If both assertion and reason are true and the reason is the correct explanation of the assertion.

If both assertion and reason are true but reason is not the correct explanation of the assertion.

If assertion is true but reason is false.

If the assertion and reason both are false

If assertion is false but reason is true.

Solution

Question 3

Sodium Chloride

Mercurus Nitrate

Nitre

Sal Ammonia

Solution

Question 4

$$1000 K$$

$$104 K$$

$$105 K$$

$$10^7K$$

Solution

Question 5

$$^{238}_{92}U$$

$$^{4}_{2}He$$

$$^{16}_{8}O$$

$$^{56}_{26}Fe$$

Solution

Question 6

$$5.6 \,MeV$$

$$8.8\,MeV$$

$$0.42 \,MeV$$

$$39.2 \,MeV$$

Solution

Question 7

Oxygen

Boron

Silicon

Carbon

Solution

Question 8

$$2.23\ u$$

$$0.0024\ u$$

$$0.027\ u$$

Data is insufficient

Solution

Question 9

$$8,8$$

$$6,6$$

$$6,8$$

$$8,6$$

Solution

Question 10

$$28.24MeV$$

$$17.28MeV$$

$$1.46MeV$$

$$39.2MeV$$

Solution

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