1)
$$_{ 3 }^{ 6 }{ Li } \longrightarrow _{ 2 }^{ 4 }{ He }\quad (\alpha -particle)+ _{ 1 }^{ 2 }{ H }$$
$$_{ 3 }^{ 6 }{ Li } \longrightarrow _{ 2 }^{ 4 }{ He }\quad (\alpha -particle)+ _{ 1 }^{ 2 }{ H }\\ { M }_{ _{ 3 }^{ 6 }{ Li } }= 6.015123u\quad \\ { m }_{ _{ 2 }^{ 4 }{ He } }+{ m }_{ _{ 1 }^{ 2 }{ H } }= 4.002603u+ 2.014102u= 6.016705u\\ \Rightarrow { M }_{ _{ 3 }^{ 6 }{ Li } }> { m }_{ _{ 2 }^{ 4 }{ He } }+{ m }_{ _{ 1 }^{ 2 }{ H } }$$
Therefore, it can emit an alpha particle.
2)
$$_{ 84 }^{ 210 }{ Po } \longrightarrow _{ 1 }^{ 1 }{ H }+ _{ 1 }^{ 3 }{ H } + _{ 82 }^{ 206 }Pb\\ { M }_{ _{ 84 }^{ 210 }Po }= 209.982876u \\ { m }_{ _{ 82 }^{ 206 }{ Pb } }+{ m }_{ _{ 1 }^{ 3 }{ H } }+{ m }_{ _{ 1 }^{ 1 }{ H } }= 205.974455u+ 3.016050u+ 1.007825u= 209.99833u\\ \Rightarrow _{ 84 }^{ 210 }{ Po }< _{ 1 }^{ 1 }{ H }+ _{ 1 }^{ 3 }{ H }+ _{ 82 }^{ 206 }Pb$$
Therefore, polonium cannot emit a proton.
3)
They cannot undergo fusion as proved in the first example.
4)
$$_{ 30 }^{ 70 }{ Zn }+ _{ 34 }^{ 82 }{ Se } \longrightarrow _{ 64 }^{ 152 }{ Gd }\\ { M }_{ _{ 64 }^{ 152 }{ Gd } }= 151.919803u \\ { m }_{ _{ 30 }^{ 70 }{ Zn } }+{ m }_{ _{ 34 }^{ 82 }{ Se } }= 69.925325u+ 81.916709u= 151.842034u\\ \Rightarrow _{ 30 }^{ 70 }{ Zn }+ _{ 34 }^{ 82 }{ Se }< _{ 64 }^{ 152 }{ Gd }$$
Therefore, fusion is not possible.