Semiconductor Electronics: Materials, Devices and Simple Circuits Test 36

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Semiconductor Electronics: Materials, Devices and Simple Circuits Test 36

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Question 1
1 / -0

In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table

A

B

C

D

Solution

Given that $$A$$ and $$B$$ are inputs for NOR gate
So we get output $$Y^{1}=\overline { A+B } $$
Now $$Y^{1}$$ and $$Y^{1}$$ are inputs for NOR gate
So the output $$Y = A+B$$
For $$A=0$$ and $$B=0$$ , the value of $$Y=0$$
For $$A=1$$ and $$B=0$$ , the value of $$Y=1$$
For $$A=0$$ and $$B=1$$ , the value of $$Y=1$$
For $$A=1$$ and $$B=1$$ , the value of $$Y=1$$
So option C is correct
Question 2
1 / -0

Which of the following gates corresponds to the truth table given below?

A
XOR

B
OR

C
NAND

D
NOR

Solution

If $$A=1$$ and $$B=1$$ then the output $$Y=0,$$
For all remaining combinations of input, the output is $$1$$
We can see that $$Y=\overline { AB } $$ will satisfy the given truth table.
Therefore the given truth table represents NAND gate,
Therefore the correct option is $$C$$
Question 3
1 / -0

The following circuit is equivalent to

A
AND gate

B
NOR gate

C
OR gate

D
NAND gate

Solution

The inputs are $$A$$ and $$B$$ , they are inputs to NOR gate
So $$Y_{1}= \overline{ { A }+ { B } }$$
$$Y_{1}$$ is input to NAND gate , so the output $$Y_{2}= \overline { (\overline { A + B } ) } =A+B$$
$$Y_{2}$$ is input to NOT gate , so the output $$Y=\overline { A+B } $$
So $$Y$$ is NOR gate of $$A$$ and $$B$$
Therefore option $$B$$ is correct
Question 4
1 / -0

If a signal passing through a gate is inhibited by sending a LOW into one of the inputs, and the output is HIGH, the gate is a(n):

A
AND

B
NAND

C
NOR

D
OR

Solution

NAND gate: Output is high if any of the input is low. The truth table for NAND gate is:
A B Output
1 1 0
1 0 1
0 1 1
0 0 1
Question 5
1 / -0

If the output $$Y$$ of the following circuit is $$1$$, the inputs $$ABC$$ must be :

A
$$010$$

B
$$100$$

C
$$101$$

D
$$110$$

Solution

From left, the first gate is OR gate and the output of OR gate is $$Y_1=A+B$$ and the second gate is AND gate.
The output of AND gate is $$Y=Y_1.C=(A+B).C$$
For $$010, Y=(0+1).0=0$$;
For $$100, Y=(1+0).0=0$$;
For $$101, Y=(1+0).1=1$$ and
For $$110, Y=(1+1).0=1.0=0$$
Question 6
1 / -0

The following arrangement performs the logic function of _________ gate.
All the gates present above are NAND gate.

A
AND

B
OR

C
NAND

D
EXOR

Solution

The all gates given in the circuit are $$NAND$$ gate. So the output of left side gates will be $$\bar{A}$$ and $$\bar{B}$$.
The output of right side gate will be: $$Y=\overline{\bar{A}.\bar{B}}=\bar{\bar{A}}+\bar{\bar B}=A+B$$ (using de Morgan's law)
We know that the output of $$OR$$ gate for two inputs $$A$$ and $$B$$ is also $$A+B$$.
Question 7
1 / -0

A logic gate which has an output $$'1'$$ only when the inputs are complement to each other is.

A
AND

B
NAND

C
NOR

D
EXOR

Solution

From the truth table of each gate, we can get only output 1 for complement inputs for $$EXOR$$ gate.
Here, when $$A=0, B=1 \Rightarrow $$ output $$=1$$ and when $$A=1, B=0 \Rightarrow $$ output $$=1$$
Question 8
1 / -0

A photoelectric cell emits electrons when illuminated by a $$60\ W$$ bulb. If the same cell is illuminated by replacing it with a $$40\ W$$ bulb, the observation that can be made is

A
No photoelectric effect takes place

B
Number of photoelectrons increases

C
The kinetic energy of photoelectrons decreases

D
Number of photoelectrons decreases

Solution

A photoelectric cell emits electrons when illuminated by a 60 W bulb. If the same cell is illuminated by replacing it with a 40 W bulb, the observation that can be made is number of photoelectrons decreases.

When the power of bulb is reduced from 60 W to 40 W, the intensity of incident radiation decreases. The number of incident photons decreases. Hence, the number of photoelectrons decreases.
Question 9
1 / -0

If we add impurity to a metal those atoms also deflect electrons. Therefore,

A
The electrical and thermal conductivities both increase

B
The electrical and thermal conductivities both decrease

C
The electrical conductivity increases but thermal conductivity decreases

D
The electrical conductivity decrease but thermal conductivity increases

Solution

If the number of electrons increase, their number of collision, increasing the thermal and electrical resistance.
So, electrical and thermal conductivities both decrease.
Question 10
1 / -0

To get an output $$y = 0$$ from the circuit shown in the figure, the input $$C$$ must be

A
$$0$$

B
$$1$$

C
Either $$0$$ or $$1$$

D
None of these

Solution

As we know, output of OR gate
$$Y = A + B$$
Output of AND gate
$$Y' $$(final output) = $$Y.C$$
$$\Rightarrow Y'$$ (final output) = $$ (A + B).C$$
If $$C = 0$$ irrespective of $$A$$ and $$B$$. then output $$Y$$ must be zero.