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Current Electricity Test - 12

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Current Electricity Test - 12
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  • Question 1
    1 / -0

    A potentiometer has a uniform wire of length 10m and resistance 5 ohms. The potentiometer is connected to an external battery of emf of 10V and negligible internal resistance and a resistance of 995 ohms in series. The potential gradient along the wire is:

    Solution

    The total resistance is the sum of the resistance of the potentiometer and the external resistance.
    R = Rpot + Rext = 5 + 995 = 1000 ohms .

    The current through the potentiometer wire I = E/R = 10/1000 = 0.01AI = E/R = 10/1000 = 0.01A.

    The potential drop across the potentiometer wire is
    V = I × Rpot
    ⇒ V = 0.01 × 5
    V = 0.05V

    The potential gradient = (potential drop across the potentiometer wire)/ length of the potentiometer wire)
    = 0.05/10
    = 5 × 10−3V/m
    = 5 mV/m

  • Question 2
    1 / -0

    In the measurement of resistance by a meter bridge, the current is necessarily reversed through the bridge wire to eliminate

    Solution

    The connecting metal strips include a small resistance in the circuit called the end resistance.
    On reversing the current, the end resistance tends to get canceled out.

  • Question 3
    1 / -0

    According to Ohm's law,

    Solution

    Ohm’s law states I is proportional to V. This holds good at steady temperatures and for the flow of constant current.

  • Question 4
    1 / -0

    Drift is the random motion of the charged particles within a conductor,

    Solution

    The electrons in a conductor have random velocities and when an electric field is applied, they suffer repeated collisions and in the process move with a small average velocity, opposite to the direction of the field. This is equivalent to positive charge flowing in the direction of the field.

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