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Current Electricity Test - 14

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Current Electricity Test - 14
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  • Question 1
    1 / -0

    According to Kirchhoff’s Loop Rule,

    Solution

    Kirchhoff’s loop rule is based on the principle of conservation of energy. Since work done in transporting a charge in a closed loop is zero. The algebraic sum ( since potential differences can be both positive and negative) of potential differences around any closed loop is always zero.

  • Question 2
    1 / -0

    Potentiometer is

    Solution

    Potentiometer is a long wire of uniform cross section made of manganin.It is actually a wire with high resistivity (ρ) with uniform cross-sectional area A. Thus, throughout the wire, it has uniform resistance.

  • Question 3
    1 / -0

    The SI unit of current is

    Solution

    Unit of electric current assigned by institute of standards is Ampere. 1 ampere is the constant current that will produce an attractive force of 2 × 10−7 newton per metre of length between two straight, parallel conductors of infinite length and negligible circular cross section placed one metre apart in a vacuum.

  • Question 4
    1 / -0

    Power is represented by-

    Solution

    Power is the rate of doing work per unit time. It is the amount of energy consumed per unit time. In the SI system unit of power is Joules per second which is also called Watt in honour of James Watt, the eighteenth-century developer of steam engine.

  • Question 5
    1 / -0

    Ammeter is always used

    Solution

    Ammeter is a device used to measure current. Since it has to allow the complete current flowing in the circuit through it, it has to be connected in series. For this reason, ammeters have very low values of resistances so that they do not add to the value of resistance connected in the circuit.

  • Question 6
    1 / -0

    Kirchhoff’s second law is a consequence of____________

    Solution

    If a charge moves around a closed loop in a circuit, it must gain as much energy as it loses.Hence, the gain in electrical energy by the charge = corresponding losses in energy through resistances.

  • Question 7
    1 / -0

    To get maximum current in a resistance of 3 ohm, one can use n rows of m cells (connected in series), connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is 0⋅5 ohm, then

  • Question 8
    1 / -0

    A battery is connected with a potentiometer wire. The internal resistance of the battery is negligible. If the length of the potentiometer wire is kept same and radius is doubled then how does potential gradient vary?

    Solution

    Potential gradient = V/I
    If internal resistance of a battery is negligible then it does not affect equivalent resistance of potentiometer so potential gradient of potentiometer remains unchanged.

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