Current Electricity Test

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Current Electricity Test - 31

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following methods does not help to minimize the error due to contact resistance in Wheatstone's meter bridge experiment:

A
The wire used must be uniform

B
The wire used must be non-uniform

C
Null point is obtained near the middle of the wire

D
Interchange the positions of unknown resistance (X) and known resistance(R)

Solution

Non-uniform wires leads to increased error in the measurement of resistance in wheatstone's bridge experiment.
Question 2
1 / -0

Kirchhoff's law of junction, $$\displaystyle \sum { I } =0$$, is based on

A
Conservation of energy

B
Conservation of charge

C
Conservation of energy as well as charge

D
Conservation of momentum

Solution

Kirchoff's law of junction is based on conservation of charge. It states that charge will not accumulate at any node.
Question 3
1 / -0

The circuit shows a battery and a variable resistor supplying power to a light circuit. As the variable resistor is moved towards left, the bulbs dim a little. What happens if the variable resistor is moved all the way to the right?

A
The lights brighten considerably

B
The total circuit resistance increases

C
The total circuit current decreases

D
The total applied voltage increases

E
The total power used in the circuit increases

Solution

When the resistor is moved towards left , total resistance of the circuit increases and hence current in circuit decreases , so bulbs dim a little . The reverse process will happen when the resistor is moved towards right , total resistance decreases and current increases therefore bulbs will light brighten considerably and also the total power used will increase.
Question 4
1 / -0

Identify the changes in a circuit on adding a light bulb to a series circuit. It will:

A
increase the total resistance

B
make the current through each light bulb different

C
decrease the total resistance

D
change the voltage of the battery

E
make the voltage lost in each light bulb equal

Solution

For series combination of two resistances $$R_{eq} = R_1 + R_2$$
Light bulb has its own resistance and thus the total resistance of the circuit increases when it is connected in series with the circuit.
Question 5
1 / -0

The five different colored graphs below represent different possible relationships between voltage across resistor and current through the resistor.
Which of the graphs shows the correct relationship for a resistor that obeys Ohm's law?

A
red

B
orange

C
blue

D
purple

E
green

Solution

According to obey's law : $$V = IR$$
$$\implies$$ $$V \propto I$$ $$(\because R = constant)$$
Thus V- I graph is a straight line having a finite slope and passing through origin as represented by blue colour.
Hence option C is correct.
Question 6
1 / -0

The five different colored graphs above represent different possible relationship between voltage across a resistor and current through the resistor.
Which of the graphs shows the correct relationship for a resistor that obeys Ohm's law?

A
Red

B
Orange

C
Blue

D
Purple

Solution

Ohm's law states that if physical condition are unchanged then voltage is directly proportional to current ,
$$V\propto I$$ ,
this relation is best depicted by blue graph , therefore blue graph obeys Ohm's law .
Question 7
1 / -0

Mobility of free electrons in a conductor is:

A
directly proportional to electron density

B
directly proportional to relaxation time

C
inversely proportional to electron density

D
inversely proportional to relaxation time

Solution

Mobility of free electrons, $$\mu = \dfrac{q\tau}{m}$$
$$\implies$$ $$\mu \propto \tau$$ $$(\because q$$ and $$m$$ are constants $$)$$
Hence mobility of free electrons in a conductor is directly proportional to relaxation time.
Question 8
1 / -0

Which of the following is not the disadvantage of wire wound resistor?

A
It has a big size which is not suitable for many of the applications.

B
It has high power rating with a low tolerance value.

C
Resistance value gets changed by a change in temperature, humidity etc.

D
It is not suitable for high-frequency circuits.

Solution

In wired resistors are mainly produced with alloys, since pure metal has a high temperature co-efficient.
Due to alloy temperature co-efficient of wire wound resistor is very low.
Therefore it is very less effected by temperature change.
Question 9
1 / -0

A carbon film resistor has colour code Green Black Violet Gold. The value of the resistor is:

A
$$50 M\Omega$$

B
$$500 M\Omega$$

C
$$500 \pm 5 \%$$ $$M\Omega$$

D
$$500 \pm 10 \%$$ $$M\Omega$$

Solution

The attached diagram is useful for the calculation of resistance using colour coding. Hence, resistance is:
$$R = 50 \times 10^7 \pm 5 \%\ \Omega = 500 \pm 5 \% \ M\Omega$$
Question 10
1 / -0

Which of the following is not true for wire wound resistor?

A
It has a lower order of stability and reliability.

B
It has high power rating with a low tolerance value.

C
Easy to make wire wound resistor of value 0.01 Ohm.

D
It is not suitable for high-frequency circuits.

Solution

A wire wound resistor is an electrical passive component that limits current. The resistive element exists out of an insulated metallic wire that is winded around a core of non-conductive material. The wire material has a high resistivity, and is usually made of an alloy such as Nickel-chromium (Nichrome) or a copper-nickel-manganese alloy called Manganin. Common core materials include ceramic, plastic and glass.
It has a lower order of stability and reliability is not true for wire wound resistor

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Current Electricity Test - 31

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Current Electricity Test - 31

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Question 1

The wire used must be uniform

The wire used must be non-uniform

Null point is obtained near the middle of the wire

Interchange the positions of unknown resistance (X) and known resistance(R)

Solution

Question 2

Conservation of energy

Conservation of charge

Conservation of energy as well as charge

Conservation of momentum

Solution

Question 3

The lights brighten considerably

The total circuit resistance increases

The total circuit current decreases

The total applied voltage increases

The total power used in the circuit increases

Solution

Question 4

increase the total resistance

make the current through each light bulb different

decrease the total resistance

change the voltage of the battery

make the voltage lost in each light bulb equal

Solution

Question 5

red

orange

blue

purple

green

Solution

Question 6

Red

Orange

Blue

Purple

Solution

Question 7

directly proportional to electron density

directly proportional to relaxation time

inversely proportional to electron density

inversely proportional to relaxation time

Solution

Question 8

It has a big size which is not suitable for many of the applications.

It has high power rating with a low tolerance value.

Resistance value gets changed by a change in temperature, humidity etc.

It is not suitable for high-frequency circuits.

Solution

Question 9

$$50 M\Omega$$

$$500 M\Omega$$

$$500 \pm 5 \%$$ $$M\Omega$$

$$500 \pm 10 \%$$ $$M\Omega$$

Solution

Question 10

It has a lower order of stability and reliability.

It has high power rating with a low tolerance value.

Easy to make wire wound resistor of value 0.01 Ohm.

It is not suitable for high-frequency circuits.

Solution

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