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Moving Charges and Magnetism Test - 24

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Moving Charges and Magnetism Test - 24
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  • Question 1
    1 / -0
    A charge q is moving with a velocity v parallel to a magnetic field B. Force on the charge due to magnetic field is
    Solution
    $$ F + q(\vec{V}\times \vec{B})$$
    $$\overrightarrow{V}||\overrightarrow{B},\theta=0$$
    $$F=0$$
  • Question 2
    1 / -0
    The following cases in which no force is exerted by a magnetic field on a charge is

    Solution
    $$F_B=q(\overrightarrow{v}\times \overrightarrow{B})$$
    if $$v=0, F_B=0$$
  • Question 3
    1 / -0
    Two streams of electrons are moving parallel to each other in the same direction. They_____
    Solution
    If the beams were stationary, they'd repel (because negative charges repel). Once the beams are moving we get the magnetic effects in addition, which reduces the repulsion. The magnetic attraction only becomes strong enough to cancel the electric repulsion at c. Therefore the streams will repel each other due to electric repulsion.
  • Question 4
    1 / -0
    The coil of the moving coil galvanometer is wound over an aluminium frame
    Solution
    The coil of the moving galvanometer is wound over an aluminium frame to provide electro-magnetic damping because aluminium is diamagnetic and it does not interact with external magnetic field.
  • Question 5
    1 / -0
    The restoring couple in the moving coil galvanometer is due to
    Solution
    When coil rotates the spring is twisted and it exerts an opposing torque on the coil.
  • Question 6
    1 / -0
    Two streams of protons move parallel to each other in the same direction. They will
    Solution
    Two streams of protons move parallel to each other in the same direction. So, we can assume that they are two wires carrying current in same direction. We know that two parallel wires having same direction of current attract each other.
  • Question 7
    1 / -0
    Imagine that you are seated in a room and there is a uniform magnetic field pointing vertically downwards in it . At the center of the room an electron is projected horizontally with a certain speed. The path of the electron in this field are:
    Solution
    $$F = q (\vec{V}\times \vec{B})$$
    Assuming observe is looking from top.
    So, Force will be in left direction by left hand rule.
    So, electron moves in left wards and moves in anti-clock-wise direction.
  • Question 8
    1 / -0
    In a moving coil galvanometer a radial magnetic field is applied with concave magnetic poles, to have
    A) uniform magnetic field
    B) the plane of the coil parallel to field
    Choose the correct option among the following 
    Solution
    In moving coil galvanometer a radial magnetic field is applied with concave magnetic poles, to have uniform magnetic field. 
    Since the magnified field is radial the plane of the coil is parallel to the magnetic field $$\vec{B}$$ such that $$\theta$$ $$=90^o$$ and hence $$\tau=NIBA$$. 
    The plane of coil is parallel to the field.
  • Question 9
    1 / -0
    There will be no force experienced if
    Solution
    Two parallel wires carrying currents in same direction attract each other.
    Two parallel wires carrying currents in opposite direction repel each other.
    A positive charge is projected between the pole pieces of bar magnet feels a force = $$q(\vec{V}\times \vec{B})$$ which is non zero since angle between V and B is non-zero.
    A positive charge projected along the axis of a solenoid carrying current feels no force because in solenoid B is along the axis so $$\vec{V}\times \vec{B}$$ is zero.
  • Question 10
    1 / -0
    The radial magnetic field is used in a suspended coil galvanometer to provide
    Solution
    Radial magnetic field is used in a suspended coil galvanometer to provide a uniform torque on the coil because it provide uniform magnetic field.
    It ensure that the magnetic field is radial and uniform through out the area of the coil
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