Moving Charges and Magnetism Test

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Moving Charges and Magnetism Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

If the current is doubled, the deflection is also doubled in

A
a tangent galvanometer

B
a moving-coil galvanometer

C
both

D
None of these

Solution

In MCG, deflection is proportional to torque on the coil and torque is proportional to current.
Hence, when current is doubled, deflection is doubled.
Question 2
1 / -0

The magnetic field produced by a current-carrying wire at a given point depends on

A
the current passing through it.

B
the voltage across it

C
the power through it

D
all

Solution

The magnetic field produced by a current-carrying wire at a given point depends directly on the current passing through it. Therefore, if there is a circular coil having n turns, the field produced is n times as large as that produced by a single turn. This is because the current in each circular turn has the same direction, and the field due to each turn then just adds up.
Question 3
1 / -0

1 gauss is equal to

A
$$10^4T$$

B
$$10^{-4}T$$

C
$$10^3 T$$

D
none of these

Solution

The Gauss is defined by the Ampère's force law when it is applied to CGS units. A wire 1 centimetre long, sitting in a flux density equal to one Gauss and carrying a current of 1 abampere experiences a force equal to 1 dyne.

Thus $$1G=\dfrac{1dyne}{(1cm*10A)}=\dfrac{10^{-5}N}{(10^{-2}m*10A)}=\dfrac{10^{-4}N}{Am}=10^{-4}T$$
Question 4
1 / -0

A magnetic field exerts no force on:

A
A magnet

B
An unmagnetised iron bar

C
A moving charge

D
Stationary charge

Solution

Moving charge can develop magnetic field and also experience the magnetic field.
But stationary charge do no have the ability to develop or experience magnetic field from the other magnetic fields. Because moving charge gives rise to current which is responsible for the magnetic effects.
Question 5
1 / -0

Scale used in moving coil galvanometer is :

A
function scale

B
linear scale

C
exponential scale

D
none of these

Solution

Linear scale is used in moving coil galvanometer.
Question 6
1 / -0

In ballistic galvanometer, the frame on which the coil is wound is non-metallic to:

A
Avoid the production of induced emf

B
Avoid the production of eddy currents

C
Increase the production of eddy currents

D
Increase the production of induced emf

Solution

The moving coil galvanometer have their coil wound on a 'metallic (copper or aluminum) frame, so as to make the motion dead beat due to the production of eddy currents. In the ballistic galvanometer, on the other hand, the damping is to be reduced to the minimum and hence the frame is of a non-conducting material eg, paper or bamboo.
Question 7
1 / -0

If magnetic field produced by a straight current carrying wire at a distance 10cm from it is X. Then the magnetic field produced at a distance 29cm will be

A
>X

B
<X

C
=X

D
all

Solution

The Magnitude of magnetic field produced by a straight current carrying wire at a given point is
A) directly proportional to the current passing in the wire and
B) inversely proportional to the distance of that point from the wire.
Question 8
1 / -0

The force of repulsion between two parallel wires is $$f$$ when each one of them carries a certain current I. If the current in each is doubled, the force between them would be

A
4/$$f$$

B
4$$f$$

C
2$$f$$

D
$$f$$

Solution

Force of repulsion per unit length between two wires carrying current in opposite direction is
$$\dfrac{F}{l}=\dfrac{\mu_0 i_1i_2}{2\pi d}$$
Thus when both $$i_1$$ and $$i_2$$ are doubled, the force between them becomes four times.
Question 9
1 / -0

An electron enters a magnetic field at right angle to it as shown in the figure. The direction of the force acting on the electron will be:-

A
To the right.

B
To the left.

C
Coming out of paper at right angle.

D
Going into the paper at right angle.

Solution

We know that both the directions are perpendicular, thus for force direction=?
Using Fleming's left hand rule,
Direction of force is perpendicular to the direction of magnetic field and current.
Thus direction of force is opposite to electron motion into the page at $$90°$$
Question 10
1 / -0

Ampere rule is used to find the

A
direction of current

B
direction of magnetic field

C
direction of motion of the conductor

D
magnitude of current

Solution

Ampere's law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.
Mathematically $$\mu_0I_{enc }=\int \vec{B}.d\vec{l}$$
This is used to find the magnetic field due to a current carrying conductor.

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Moving Charges and Magnetism Test - 28

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Moving Charges and Magnetism Test - 28

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Question 1

a tangent galvanometer

a moving-coil galvanometer

both

None of these

Solution

Question 2

the current passing through it.

the voltage across it

the power through it

all

Solution

Question 3

$$10^4T$$

$$10^{-4}T$$

$$10^3 T$$

none of these

Solution

Question 4

A magnet

An unmagnetised iron bar

A moving charge

Stationary charge

Solution

Question 5

function scale

linear scale

exponential scale

none of these

Solution

Question 6

Avoid the production of induced emf

Avoid the production of eddy currents

Increase the production of eddy currents

Increase the production of induced emf

Solution

Question 7

>X

<X

=X

all

Solution

Question 8

4/$$f$$

4$$f$$

2$$f$$

$$f$$

Solution

Question 9

To the right.

To the left.

Coming out of paper at right angle.

Going into the paper at right angle.

Solution

Question 10

direction of current

direction of magnetic field

direction of motion of the conductor

magnitude of current

Solution

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