Moving Charges and Magnetism Test

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Moving Charges and Magnetism Test - 50

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Weekly Quiz Competition

Question 1
1 / -0

The magnetic effect of electric current was discovered by

A
Maxwell

B
Oersted

C
Ampere

D
none of these

Solution
Question 2
1 / -0

Two charges of same magnitude move in two circles of radii $$R_1\, =\, R\, and\, R_2\, =\, 2R$$ in a region of constant uniform magnetic field $$\vec{B}$$.
The work $$W_1\, and\, W_2$$ done by the magnetic field in the Two cases, respectively are such that

A
$$W_1\, =\, W_2\, =\, 0$$

B
$$W_1\, >\, W_2$$

C
$$W_1\, =\, W_2\, \neq \, 0$$

D
$$W_1\, <\, W_2$$

Solution

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Question 3
1 / -0

A magnetic field can exert force on a

A
stationary magnet

B
moving charge

C
moving magnet

D
all the above

Solution

$$\textbf{Hint:}$$ Use the magnetic force on the magnet and charge in a magnetic field.
$$\textbf{Explanation:}$$
$$\bullet$$The force on a charged particle is given by
$$\vec{F}=q(\vec{v}\times \vec{B})$$
where $$\vec{v}$$ is the velocity of charged particle placed in magnetic field
$$\bullet$$Also magnetic field exerts force on a a magnet, independent of its motion, due to interaction with the permanent magnetic field around it.
$$\textbf{Hence option D correct}$$
Question 4
1 / -0

A proton and an $$\alpha$$ particle moving with the same speed enter a uniform magnetic field. The proton enters at right angles to the field. The magnetic force $$F$$ on the particles will be the same when the direction of motion of a particle is ________.

A
Parallel to the field

B
Perpendicular to the field

C
At $$30$$ to the field

D
At $$60$$ to the field

Solution

$$F=Bqv sin \theta$$
For Proton $$\theta = 90^{\circ}, F_1 = Bqv$$ newton
For $$\alpha - $$particle charge is $$2q, F_2 = B \times 2q \times v$$ $$sin \theta$$
But $$F_1 = F_2$$
i.e., $$Bqv = 2Bqv$$ $$sin \theta$$
$$\displaystyle \therefore sin\theta = \frac {1}{2}, \theta = 30^{\circ}$$
Question 5
1 / -0

When the free ends of a tester are dipped into a solution, the magnetic needle shows deflection due to:

A
electrical effect

B
mechanical effect

C
magnetic effect

D
lighting effect

Solution

When the free ends of a tester are dipped into a solution, the circuit gets complete and current starts to flow in wires.The magnetic needle shows deflection due to magnetic effect of current which states that an electric current is always associated with magnetic field around it.Due to this magnetism the needle is deflected.
Question 6
1 / -0

When a proton moves in a uniform magnetic field, the momentum change but its kinetic energy does not change because :

A
The magnetic force exerted will be perpendicular to the direction of motion of the proton.

B
Work done will be zero.

C
Kinetic energy does not change.

D
All

Solution

The magnetic force exerted will be perpendicular to the direction of motion of the proton. As we know when when force acting is perpendicular to the direction of moving charge, work done will be zero. It means kinetic energy does not change. The force is able to change the direction (velocity) of the proton but not its speed (magnitude). Thus momentum and velocity changes.
Question 7
1 / -0

The pattern of the magnetic field around a conductor due to an electric current flowing through it depends on

A
amount of current flowing through the conductor

B
amount of voltage supplied to the conductor

C
size of conductor

D
shape of the conductor

Solution

We know that;
$$\vec B=\dfrac{\mu_0}{4\pi}\int { \dfrac { Idl\times {\vec r } }{ \left| { r }^{ 1 } \right| ^{ 3 } } } $$
Where, $$\vec B$$ is magnetic field, $$\vec I$$ is current.
Thus magnitude of $$\vec B$$ depend on I, but pattern of magnetic field depend on shape of conductor as the direction of magnetic field is obtained used Cut finger rule i.e, pointing right hand thumb in current direction, Curl fingers describes direction thus pattern.
Question 8
1 / -0

If a current carrying wire carries 10A current then the magnetic field is X. Now the current in the wire increases to 100A, them magnetic field in the wire becomes

A
>X

B
<X

C
=X

D
all

Solution

The Magnitude of magnetic field produced by a straight current carrying wire at a given point is
A) directly proportional to the current passing in the wire and
B) inversely proportional to the distance of that point from the wire.
Question 9
1 / -0

What is shape of magnet in moving coil galvanometer to make the radial magnetic field?

A
Concave

B
Horse shoe magnet

C
Convex

D
None of the above

Solution

The shape of magnet in moving coil galvanometer to make the radial magnetic field is concave magnets.
Question 10
1 / -0

Positively charged particles are projected into a magnetic field. If the direction of the magnetic field is along the direction of motion of the charge particle, the particles get

A
Accelerated

B
Decelerated

C
Delfected

D
No changed in velocity

Solution

The direction of magnetic field is along the direction of motion of the charge particles, so angle will be $$0^{\circ}$$.
$$\therefore$$ Force $$F = qvB\sin \theta$$
$$= qvB\sin 0$$
$$= 0 (\because \sin 0 = 0)$$
So, there will be no change in the velocity.

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Re-Attempt Weekly Quiz Competition

Moving Charges and Magnetism Test - 50

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Moving Charges and Magnetism Test - 50

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SHARING IS CARING

Question 1

Maxwell

Oersted

Ampere

none of these

Solution

Question 2

$$W_1\, =\, W_2\, =\, 0$$

$$W_1\, >\, W_2$$

$$W_1\, =\, W_2\, \neq \, 0$$

$$W_1\, <\, W_2$$

Solution

Question 3

stationary magnet

moving charge

moving magnet

all the above

Solution

Question 4

Parallel to the field

Perpendicular to the field

At $$30$$ to the field

At $$60$$ to the field

Solution

Question 5

electrical effect

mechanical effect

magnetic effect

lighting effect

Solution

Question 6

The magnetic force exerted will be perpendicular to the direction of motion of the proton.

Work done will be zero.

Kinetic energy does not change.

All

Solution

Question 7

amount of current flowing through the conductor

amount of voltage supplied to the conductor

size of conductor

shape of the conductor

Solution

Question 8

>X

<X

=X

all

Solution

Question 9

Concave

Horse shoe magnet

Convex

None of the above

Solution

Question 10

Accelerated

Decelerated

Delfected

No changed in velocity

Solution

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