Self Studies

Moving Charges ...

TIME LEFT -
  • Question 1
    1 / -0

    A moving coil galvanometer of resistance $$100 \space \Omega$$ is used as an ammeter using a resistance $$0.1 \space \Omega$$. The maximum deflection current in the galvanometer is $$100 \space \mu A$$.Find the minimum current in the circuit so that the ammeter shows maximum deflection.    

  • Question 2
    1 / -0

    A magnetic field $$ \vec{B} = B_{0}\hat{j} $$ exists in the region $$ a  < x < 2a $$ and $$ \vec{B} = -B_{0}\hat{j} $$ , in the region $$ 2a < x < 3a $$ , where $$ B)_{0} $$ is a positive constant . A positive point charge moving with a velocity $$ \vec{v} = v_{0} \hat{i} $$ , where $$ v_{0} $$ is a positive constant , enters the magnetic field at $$ x = a $$ . The trajectory of the charge in this region can be like 

  • Question 3
    1 / -0

    Two infinite long wires, each carrying current I , are lying along x and y -axis , respectively .A charged particle, having a charge q and mass m, is projected with a velocity u along the straight line OP. the path of the particle is ( neglect gravity) 

  • Question 4
    1 / -0

    Bolt-savart law indicates that the moving electrons (velocity v) produce a magnetic field b such that

  • Question 5
    1 / -0

    Two parallel wires are carrying electric currents of equal magnitude and in the same direction. They exert

  • Question 6
    1 / -0

    The radius of curvature of the path of the charges particles in a uniform magnetic field is directly proportional to

  • Question 7
    1 / -0

    Tick the most appropriate answer.
    Which of the following methods is used to magnetize a magnetic without touching it by a magnet?

  • Question 8
    1 / -0

    A magnetic field 

  • Question 9
    1 / -0

    A proton (mass $$=1.67\times 10^{-27} kg$$ and charge $$=1.6\times 10^{-19}C$$) enters perpendicular to a magnetic field of intensity $$2$$ weber $$/m^2$$ with a velocity $$3.4\times 10^7\ m/sec$$. The acceleration of the proton should be

  • Question 10
    1 / -0

    Lorentx force can be calculate dby using the formula

Submit Test
Self Studies
User
Question Analysis
  • Answered - 0

  • Unanswered - 10

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Submit Test
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now