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Magnetism and Matter Test 33

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Magnetism and Matter Test 33
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  • Question 1
    1 / -0
    The magnetic susceptibility is negative for
    Solution
    Given: Magnetic susceptibility=-ve
    Solution: Magnetic susceptibility is the degree to which a material is magnetized.
    Diamagnetic substance has negative susceptibility.
    Negative magnetic susceptibility mean that the magnetization (M) is repelling in nature so they move from stronger to weaker region.
    Hence the correct option is B

  • Question 2
    1 / -0
    The $$\chi-(\dfrac{1}{T})$$ graph for an alloy of paramagnetic nature is shown in figure. The curie constant is, then

    Solution
    $$X = C \times \frac{1}{T} = \dfrac{0.4}{{1 \times {{7}^{ - 3}}}} = 57K$$
  • Question 3
    1 / -0
    The susceptibility of a diamagnetic material is
    Solution
    Solution:  As we know that$$,$$ On the basis of our 
    understanding about Diamagnetic material that
    susceptibility is independent of the magnetising
    field and the temperature.
    hence,
    The correct opt:C
  • Question 4
    1 / -0
    The susceptibility of a paramagnetic substance was found for different temperatures and a graph of $$\chi $$ against $$\frac{1}{T}$$ was plotted. From the graph, it was found that what $$\chi =0.5, \frac{1}{T}=5 \times 10^{-3}/K$$. What is the curie constant for the substance ?
    Solution
    Curie's law :      $$\chi = \dfrac{c}{T}$$
    So,     $$0.5 =c\times 5\times 10^{-3}$$
    $$\implies \ c = 100 \ K$$
  • Question 5
    1 / -0
    A conducting wire frame is placed in a magnetic field which is directed in to the paper. The magnetic field increasing at a constant rate. The directions of induced current in wires AB and CD are:

    Solution
    $$Solution:$$ Inward magnetic field (')
    increasing. Therefore, induced
    current in both the loops should be
    anticlockwise. But as the area of
    loop on right side is more, induced
    emf in this will be more compared
    to the left side loop

    $$\left(e=-\frac{d \varphi}{d t}=-A . \frac{d B}{d t}\right)$$

    Therefore net current in the
    complete loop will be in a direction
    shown above.
    $$So,the$$ $$correct$$ $$option:A$$

  • Question 6
    1 / -0
    If the magnetic flux linked up with a coil is changed by 40%, the energy storied in the coil changes by 
  • Question 7
    1 / -0
    The intensity of magnetic field is H and moment of magnet is M. The maximum potential energy is
    Solution
    When the magnetic field $$=H$$
    and moment of magnet $$=M$$
    Now, the maximum potential energy $$=HM$$
    when $$\sin{ 90 }^{ 0 }=1$$
  • Question 8
    1 / -0
    The mass of a specimen of a ferromagnetic material is  $$0.6 kg$$  and its density is  $$7.8\times 10^{ { 3 } }{ kg }/{ m }^{ { 3 } }.$$  If the area of hysteresis loop of alternating magnetising field of frequency  $$50 { Hz }$$  is  $$0.722{ MKS }$$  units then the hysteresis loss per second will be :-
    Solution
    $$\begin{array}{l} Accorrding\, \, to\, \, question....................... \\ Here, \\ Hysteresis\, energy\, lost\, per\, \, \, second\, \, is: \\ E=nA\frac { m }{ p } =\dfrac { { 50\times 0.722\times 0.6 } }{ { 7.8\times \, { { 10 }^{ 3 } } } }  \\ \, \, \, \, \, \, \, \, \, \therefore \, \, \, \, 277.7\times { 10^{ -5 } }J/S \\ So\, the\, correct\, option\, is\, A. \end{array}$$
  • Question 9
    1 / -0
    Mark out the correct options.
    Solution
    Solution : 
    Diamagnetism is the only contribution of magnetism, it is the quantum mechanical effect that occurs in all materials. In ferromagnetic and paramagnetic substance weak diamagnetic force is present which is overcome by the attractive force of magnetic dipoles present in material.
    The Correct Opt:A
  • Question 10
    1 / -0
    Magnetic flux in the circuit containing a coil of resistance 2 ohm changes from 2.0 wb to 10 wb in 0.2 sec. the charge passed through the coil in this time is 
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