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Alternating Current Test - 22

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Alternating Current Test - 22
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  • Question 1
    1 / -0
    The correct curve between inductive reactance (XL) and frequency (f) is
    Solution
    Since,
    $${ X }_{ L }=2\pi fL$$
    therefore its a linear graph hence option(B) is correct
  • Question 2
    1 / -0
    When the values of inductance and capacitance in an $$L-C$$ circuit are $$0.5\  H$$ and $$8\ \mu$$F respectively then current in the circuit is maximum. The angular frequency of alternating e.m.f. applied in the circuit will be
    Solution
    We know that, maximum current flows when the circuit is at resonance
    Therefore, Resonance frequency is given by

    $$\omega =\dfrac { 1 }{ \sqrt { LC }  } $$

    $$\omega =\dfrac { 1 }{ \sqrt { 0.5\times 8\times { 10 }^{ -6 } }  } $$

    this gives 

    $$\omega =5\times { 10 }^{ 2 }$$ Radian/sec
  • Question 3
    1 / -0
    The inductive reactance of a coil is $$2500\ \Omega$$. On increasing its self-inductance three times, the new inductive reactance will be
    Solution
    We know that ,
    $${ X }_{ L }=\omega L$$
    therefore when $$L$$ is made three times inductive reactance will also become three times.
    Therefore new reactance will be equal to $$3\times 2500\ \Omega=7500\ \Omega$$.
  • Question 4
    1 / -0
    The inductive reactance of a choke coil of $$\displaystyle 1/4 \pi\  mH$$ in an $$AC$$ circuit of $$50\  Hz,$$  will be
    Solution
    $${ X }_{ L }=\omega L$$

    $${ X }_{ L }==2\pi fL$$

    $${ X }_{ L }=2\pi \times 50\times \dfrac { { 10 }^{ -3 } }{ 4\pi  } $$

    $${ X }_{ L }=0.025\ \Omega $$
  • Question 5
    1 / -0
    The value of alternating emf in the following circuit will be

    Solution
    $$V=\sqrt { { V }_{ R }^{ 2 }+{ ({ V }_{ L }^{  }-{ V }_{ C }^{  }) }^{ 2 } } $$

    $$V=\sqrt { { 80}^{ 2 }+{ (40^{  }-100^{  }) }^{ 2 } } $$

    $$V=100$$ volt
  • Question 6
    1 / -0
    The correct curve between the resistance of a conductor (R) and frequency (f) is
    Solution
    The resistance of a resistor is independent of the frequency of the AC source to which it is connected. Thus it has a constant curve against frequency.
    However the impedance of an inductor or a capacitor changes with the frequency of the AC source.

    Impedance of an inductor $$=\omega L=2\pi fL$$

    Impedance of a capacitor $$=\dfrac{1}{\omega C}=\dfrac{1}{2\pi fC}$$
  • Question 7
    1 / -0
    The capacitive reactance at $$1600\  Hz$$  is  $$81\ \Omega$$. When the frequency is doubled then capacitive reactance will be
    Solution
    capacitive reactance is inversely proportional to the frequency 
    $${ X }_{ C }=\dfrac{1}{2\pi fC}$$
    therefore when frequency is doubled capacitive reactance will get halved therefore new $${ X }_{ C }$$ is  $$40.5\ \Omega $$
  • Question 8
    1 / -0
    An $$R-C$$ circuit is as shown in the following diagram.The capacity reactance and impedance will be

    Solution
    Since power source is dc therefore,

    $$\omega =0 $$

    $${ X }_{ C }=\dfrac { 1 }{ \omega C } $$

    $${ X }_{ C }=\dfrac { 1 }{0}$$

    $${ X }_{ C }=\infty $$

    $$Z=\infty$$
  • Question 9
    1 / -0
    An alternating voltage frequency $$\omega$$ is induced in electric circuit consisting of an inductance $$L$$ and capacitance $$C$$, connected in parallel. Then across the inductance coil the
    (i) current is maximum when $${\omega}^{2}=1/(LC)$$
    (ii) current is minimum when $${\omega}^{2}=1/(LC)$$
    (iii) voltage is minimum when $${\omega}^{2}=1/(LC)$$
    (iv) voltage is maximum when $${\omega}^{2}=1/(LC)$$
    Solution
    In parallel LC circuits, current is minimum when, $$\omega =\sqrt{\dfrac{1}{LC}}$$

    Also, current and voltage are at angle of 90 degrees. 
    Hence, voltage is maximum when current is minimum. 
    Option D is thus correct.
  • Question 10
    1 / -0
    Of the following about capacitive reactance which is correct?
    Solution
    Capacitative reactance is an opposition to the change of voltage across an element.
    It is denoted by $$X_C$$ and is inversely proportional to the signal frequency(f) and the capacitance C.
    $$X_C=\dfrac{1}{2\pi fC}$$
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