Alternating Cur...

What is the phase angle in a series $$RLC$$ circuit at resonance?

What is the rms voltage?

A 100 volt A.C. source of frequency 500 hertz is connected to a L-C-R circuit with L $$=$$ 8.1 millihenry, C $$=$$ 12.5 microfarad and R $$=$$ 10 ohm, all connected in series. The potential difference across the resistance will be:

An AC source of variable frequency is applied across a series L-C-R circuit. At a frequency double the resonance frequency, the impedance is $$\sqrt{10}$$ times the minimum impedance. The inductive reactance is

At a frequency $$\omega_{0} $$ the reactance of a certain capacitor equals that of a certain inductor. If frequency is changed to 2 $$\omega_{0} $$ . The ratio of reactance of the inductor to that of the capacitor is

An ideal inductor takes a current of $$10  A$$ when connected to a $$125$$ $$V$$, $$50$$ $$Hz$$ AC supply. A pure resistor across the same source takes $$12.5$$ $$A$$. If the two are connected in series across a $$100\sqrt{2}V$$, $$ 40$$ $$Hz$$ supply, the current through the circuit will be

When a series combination of $$L$$ and $$R$$ are connected with a $$10V$$, $$50HZ$$ A.C. source, a current 1A flows in the circuit. The voltage leads the current by a phase angle of $$\pi/3$$ radian. Then the resistance is

In an A.C circuit, the resistance $$ R = 0.2\, \Omega$$. At a certain instant, $$V_A - V_B = 0.5\, V$$, $$ I = 0.5\, A$$, and the current is increasing at the rate of  $$\dfrac{\Delta I}{\Delta t} = 8\,A/s$$. The inductance of the coil is:

An AC source of angular frequency $$\omega $$ is fed across a resistor R and a capacitor C in series. The current registered is I. If now the frequency of source is changed to $$\omega /3$$ (but maintaining the same voltage), the current in the circuit is found to be halved. The ratio of reactance to resistance at the original frequency $$\omega $$ is

In the given circuit, $$R$$ is a pure resistor, $$L$$ is a pure inductor, S is a 100V, 50Hz AC source and A is an AC ammeter. With either $$K_1$$ or $$K_2$$ alone closed, the ammeter reading is $$I$$. If the source is changed to 100 V, 100 Hz, the ammeter reading with $$K_1$$ alone closed and with $$K_2$$ alone closed will be respectively