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Electromagnetic Waves Test - 31

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Electromagnetic Waves Test - 31
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  • Question 1
    1 / -0
    Electromagnetic weave of frequency $$6 \times 10^{12}$$ Hz are traveling through free space. In which region of the e. m. spectrum, the waves will life?
    Solution

  • Question 2
    1 / -0
    A light beam travelling in the x-direction is described by the electric field $${E_y} = 300v/m\sin \left( {t - \frac{x}{c}} \right)$$. An electron is constrained to move along the y-direction with a speed of $$2.0 \times {10^7}m/s.$$ Find the maximum magnetic force on the electron.
    Solution

    As we know that, 
             $${ B }_{ \circ  }=\dfrac { { E }_{ \circ  } }{ C } $$
    Where, 
                $${ B }_{ \circ  }$$ = Max. Magnetic Field
                $${ E }_{ \circ  }$$ = Max. Electric Field
                                          C= speed of light
     It is given that,
                          $${ E }_{ \circ  }$$= 300 V/m
    So,    $${ B }_{ \circ  }$$=$$\dfrac { 300 }{ 3\times { 10 }^{ 8 } }$$ = $${ 10 }^{ -6 }$$ T
    Now,  maximum magnetic force= qv$${ B }_{ \circ  }$$
                                                         = $$1.6\times { 10 }^{ -19 }\times 2\times { 10 }^{ 7 }\times { 10 }^{ -6 }$$
                                                         =$$3.2\times { 10 }^{ -18 }$$ N

  • Question 3
    1 / -0
    A magnetic field can be produced by
    Solution

  • Question 4
    1 / -0
    If at a certain instant, the magnetic induction of the electromagnetic wave in vacuum is $$6.7\times 10^{-12}T$$, then the magnitude of electric field intensity will be?
    Solution

  • Question 5
    1 / -0
    Mark the correct option in impure spectrum :
    Solution
    For impure spectrum:
    1. The order of colours is are straight, hence option a is false
    2. Order of colours are regular
    3. Colours are overlapped each other in impure spectrum
    4. Colours are present in impure spectrum
    Hence option C is the correct statement according to the impure spectrum
  • Question 6
    1 / -0
    The electric field portion of an electromagnetic wave is given by(all variables in SI units) $$E=10^{-4}\sin(6\times 10^5t-0.01x)$$. The frequency (f) and the speed(v) of electromagnetic wave are?
    Solution
    $$\omega =6\times 10^5=2\pi f$$
    $$f=\dfrac{6}{2\pi}\times 10^5=\dfrac{3}{\pi}\times 10^5Hz$$
    $$=\dfrac{300}{\pi}\times 10^3Hz$$
    $$=\dfrac{300}{\pi}kHz$$
    Wave speed, $$v=\dfrac{\omega}{k}$$
    $$\Rightarrow\dfrac{6\times 10^5}{0.01}=6\times 10^7m/s$$.
    So, the correct option is $$(C)$$
  • Question 7
    1 / -0
    An electric field $$\vec {E}$$ and a magnetic field $$\vec{B}$$ exist in the region. The fields are not perpendicular to each other
    Solution

  • Question 8
    1 / -0
    The electric field 'E' and magnetic field 'B' in electromagnetic waves are?
    Solution

  • Question 9
    1 / -0
    Microwaves from a transmitter are directed normally towards a plane reflector. A detector moves along the normal to the reflector. Between positions of $$14$$ successive maxima the detector travels a distance $$0.14 m$$. The frequency of the transmitter is $$(c=3 \times 10_{8} m/s)$$
    Solution

    The detector receives direct as well as reflected waves. The distance moved between two consecutive position of maxima is $$\lambda/2$$.

                    $$14 \times \dfrac{\lambda}{2}= 71= 0.14 m$$

    $$\Rightarrow   \lambda = 0.02m$$

                     $$ c=n\lambda$$

    Putting $$c = 3 \times 10^{8} m/s,$$ we

     have

            $$n =\dfrac{c}{\lambda}= \dfrac{3 \times 10^{8}}{0.02}=1.5 \times 10^{10} Hz$$




  • Question 10
    1 / -0
    An electromagnetic wave, going through vacuum is described by $$E=E_0 \sin (kx -\omega t)$$. Which of the following is independent of wavelength 
    Solution
    The angular wave number $$k=\dfrac {2\pi}{\lambda}$$, where $$\lambda$$ is the wave length. The angular frequency is $$w=2\pi v$$
    The ratio $$\dfrac {k}{\omega}=\dfrac {2\pi / \lambda}{2\pi v}=\dfrac {1}{v \pi}=\dfrac {1}{c}=$$ constant
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