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Parts and Whole Test 12

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Parts and Whole Test 12
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  • Question 1
    1 / -0
    How many more unit squares in the figure must be shaded so that the fraction of shaded squares is $$\displaystyle\frac{7}{9}$$?

    Solution
      Total number of unit square is $$18$$
    $$\Rightarrow$$  Let total number of shaded squares be $$x$$.
    $$\Rightarrow$$  Fraction of shaded squares is $$\dfrac{7}{9}$$
    $$\rightarrow$$   According to the question,
    $$\Rightarrow$$  $$\dfrac{7}{9}=\dfrac{x}{18}$$

    $$\Rightarrow$$  $$x=\dfrac{7}{9}\times {18}$$

    $$\Rightarrow$$  $$x=14$$
    $$\Rightarrow$$  Out of these $$14$$ squares $$6$$ are shaded.
    $$\therefore$$    We have to shade $$8$$ more squares.
  • Question 2
    1 / -0
    What fraction of the figure is shaded?

    Solution
    If we rearrange the figure then we can conclude that out of $$9$$ squares, $$4.5$$ squares are shaded
    So the fraction of figure which is shaded is $$\dfrac{4.5}{9}=\dfrac{1}{2}$$
  • Question 3
    1 / -0
    What fraction of the given circles is crossed?

    Solution
    Total number of circle = 8
    Number of crossed circles = 5
    $$\therefore$$Required fraction = $$\dfrac{5}{8}$$
  • Question 4
    1 / -0
    Which of the following options is CORRECT for the fraction of shaded parts in figures $$I$$ and $$II$$?

    Solution
    Number of equal parts in Figure $$I = 24$$
    Number of shaded parts in Figure $$I = 20$$
    $$\therefore$$ Required shaded fraction for figure $$I = \dfrac {20}{24} = \dfrac {5}{6}$$
    Number of equal parts in figure $$II = 40$$
    Number of shaded parts in figure $$II = 32$$
    $$\therefore$$ Required shaded fraction for figure $$II = \dfrac {32}{40} = \dfrac {4}{5}$$
    Now, $$\dfrac {5}{6} = \dfrac {5\times 5}{6\times 5} = \dfrac {25}{30}$$

    and $$\dfrac {4}{5} = \dfrac {4\times 6}{5\times 6} = \dfrac {24}{30}$$

    $$\because \dfrac {25}{30} > \dfrac {24}{30}$$

    $$\therefore I > II$$.
  • Question 5
    1 / -0
    Monthly salary of a person is $$ Rs.15000 $$. The central angle of the sector representing his expenses on food and house rent on a pie chart is $$ 60^o $$. The amount he spend on food and house rent is 
    Solution
    As, total salary= $$ 15000 $$, expenses on food and house rent= $$ 60^o $$
    Food and housing expenses from monthly salary= $$ \dfrac{Central\quad  angle\quad  of\quad  the \quad part\quad  of \quad pie \quad chart}{ Central\quad  angle\quad  of \quad the \quad pie \quad chart} $$
    Given that,
    Part of salary spent on food and house rent= $$ \dfrac{60^o}{360^o}= \dfrac{1}{6}$$
    Salary spent in amount on food and housing= $$ \dfrac{1}{6}\times 15000 $$
    $$ \therefore 2500 $$ Rs is total amount spent on food and house rent.
  • Question 6
    1 / -0
    In the given figure, the shaded region is represented by the fraction:

    Solution
    Here the shaded triangles represent half of the area of the square.
    Therefore, the number of shaded squares are $$=1+0.5+0.5+0.5=2.5$$
    The total number of squares are $$=12$$
    So, the shaded fraction $$=\dfrac{2.5}{12}=\dfrac{2.5\times2}{12\times2}=\dfrac{5}{24}$$
  • Question 7
    1 / -0
    What part of the circle is coloured?

    Solution
    There is 8 parts in circle and 1 part is coloured.
    So, total parts=8 (=Denominator)
    coloured parts=1 (=numerator)
    so, $$fraction=1/8$$
  • Question 8
    1 / -0
    Represent the answer in fraction

  • Question 9
    1 / -0
    What part of the rectangle is blue and what part is grey?

    Solution

  • Question 10
    1 / -0
    What part of the circle is coloured?

    Solution
    There is 8 parts in circle and 3 part is coloured.
    So, total parts=8 (=Denominator)
    coloured parts=3 (=numerator)
    so, $$fraction=3/8$$
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