Ratio and Proportion Test

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Ratio and Proportion Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

Two cars $$A$$ and $$B$$ are moving on the road with speeds $$10m/s$$ and $$36kmph$$ respectively. If their starting point and ending point is same and if they are moving in the same direction, then find the ratio of the times taken by them to reach the end point, once they start at same time, from the starting point.

A
$$1:3.6$$

B
$$3.6:1$$

C
$$1:1$$

D
$$2:1$$

Solution
Question 2
1 / -0

$$30$$ cricket players and $$20$$ kho-kho players are training on a field. What is the ratio of cricket players to the total number of players?

A
$$\dfrac {3}{2}$$

B
$$\dfrac {2}{5}$$

C
$$\dfrac {3}{5}$$

D
$$\dfrac {1}{5}$$

Solution

Number of cricket players $$=30$$
Total number of players $$=$$ Number of cricket players $$+$$ Number of kho-kho players
$$=30+20$$
$$=50$$

Required ratio $$=\dfrac{\text{Number of cricket players}}{\text{Total number of players}}$$

$$ =\dfrac{30}{30+20}$$

$$=\dfrac{30}{50} $$

$$=\dfrac{3}{5}$$
Question 3
1 / -0

Snehal has a red ribbon that is $$80cm$$ long and a blue ribbon, $$220m$$ long. What is the ratio of the length of the red ribbon to that of the blue ribbon?

A
$$\dfrac {4}{21}$$

B
$$\dfrac {4}{5}$$

C
$$\dfrac {5}{11}$$

D
$$\dfrac {4}{11}$$

Solution

$$\dfrac{\text{length of red ribbon}}{\text{length of blue ribbon}}= \dfrac{80cm}{220cm} = \dfrac{8}{22} = \dfrac{4}{11}$$
Question 4
1 / -0

Mr. Kumar earns $$Rs. \,9400$$ in a month. He spends $$Rs. \,8200$$ and saves the rest. What is the ratio of earnings to savings?

A
$$\dfrac{47}{6}$$

B
$$\dfrac{23}{6}$$

C
$$\dfrac{12}{13}$$

D
None of these

Solution
Question 5
1 / -0

Ravi and Kavi start a business by investing Rs. $$8000$$ and Rs. $$72000 $$, respectively. Find the ratio of their profits at the end of year.

A
$$2 : 9$$

B
$$5 : 9$$

C
$$7 : 9$$

D
$$1 : 9$$

Solution

Their profits must be divided in the ratio of their investment .So ,
Ravi's profit : Kavi's profit $$= 8000:72000$$
$$=\dfrac{80}{72}$$
$$ = 1:9$$
Question 6
1 / -0

Find the ratio of Rs. $$5$$ to $$50$$ paise

A
$$10:1$$ paise

B
$$100:1$$ paise

C
$$20:1$$ paise

D
None of these

Solution

$${\textbf{Step -1: Converting rupees to paise}.}$$
$${\text{We know that, 1 Rupee = 100 paise}}$$
$$\therefore {\text{ 5 Rupees = }}\dfrac{{{\text{5 }} \times {\text{ 100}}}}{{\text{1}}}{\text{ paise}}$$
$$ \Rightarrow {\text{ 5 Rupees = 500 paise}}$$ $$\quad \quad \text{......eqn (i)}$$
$${\textbf{Step -2: Substitute the above result and find the required ratio}.}$$
$${\text{Ratio of 5 Rupees}}{\text{ to 50 paise }}$$$$ = {\text{ }}\dfrac{{{\text{5 Rupees}}}}{{{\text{50 paise}}}}$$
$$ = {\text{ }}\dfrac{{{\text{500 paise}}}}{{{\text{50 paise}}}}$$ $$\quad \quad \textbf{[From eqn (i)]}$$
$$ = {\text{ 10:1}}$$
$${\textbf{Thus, the ratio of 5 Rupees to 50 paise is 10:1}.}$$
Question 7
1 / -0

The total population of a village is $$3540,$$ out of which $$2065$$ are males. Find the ratio of males to females.

A
$$\dfrac 57$$

B
$$\dfrac 35$$

C
$$\dfrac 75$$

D
$$\dfrac 65$$

Solution

Total males $$= 2065$$
females $$=3540-2065=1475$$

Males to female ratio $$\dfrac{2065}{1475}$$

$$=\dfrac{413}{295} = \dfrac{7}{5}$$
Question 8
1 / -0

$$\dfrac x4=\dfrac 43$$ then $$x=?$$

A
$$\dfrac {16}3$$

B
$$\dfrac 34$$

C
$$\dfrac {16}9$$

D
None.

Solution

Given relation is $$\dfrac x4=\dfrac 43$$

$$\implies x=4\times \dfrac 43=\dfrac {16}3$$
Question 9
1 / -0

What is ratio in between $$7$$ months and $$7$$ years?

A
$$1 : 12$$

B
$$1 : 13$$

C
$$1 : 14$$

D
None of these

Solution

$$7 \ Years = 84 \ Months$$

$$Ratio = \ \dfrac{7 \ Months}{7 \ Years}$$

$$\rightarrow \dfrac {7 Months}{84 Months }$$

$$\rightarrow \dfrac {1}{12 }$$

$$1 :12$$
$$Correct \ Answer \ is \ A$$
Question 10
1 / -0

The ratio of the present ages of two brothers is $$1:2$$ and $$5$$ years back the ratio was $$1:3$$. What will be the ratio of their ages after $$5$$ years?

A
$$1:4$$

B
$$2:3$$

C
$$3:5$$

D
$$5:6$$

Solution

Let the age of the two brothers be $$x$$ and $$y$$ respectively

Given

At present

$$\dfrac { x }{ y } =\dfrac { 1 }{ 2 } \Rightarrow y=2x$$

Five years ago

$$\dfrac { x-5 }{ y-5 } =\dfrac { 1 }{ 3 }$$

substitute $$y=2x$$

$$\dfrac { x-5 }{ 2x-5 } =\dfrac { 1 }{ 3 }$$

$$\Rightarrow 3x-15=2x-5\Rightarrow x=10$$

$$\Rightarrow y=2x=2(10)=20$$

$$\therefore\ x=10$$ and $$y=20$$

Required ratio:

$$\displaystyle \frac { x+5 }{ y+5 } =\frac { 10+5 }{ 20+5 } =\frac { 15 }{ 25 } =\frac { 3 }{ 5 }$$

Hence option (C) is the correct option.

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Re-Attempt Weekly Quiz Competition

Ratio and Proportion Test - 13

Result

Ratio and Proportion Test - 13

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SHARING IS CARING

Question 1

$$1:3.6$$

$$3.6:1$$

$$1:1$$

$$2:1$$

Solution

Question 2

$$\dfrac {3}{2}$$

$$\dfrac {2}{5}$$

$$\dfrac {3}{5}$$

$$\dfrac {1}{5}$$

Solution

Question 3

$$\dfrac {4}{21}$$

$$\dfrac {4}{5}$$

$$\dfrac {5}{11}$$

$$\dfrac {4}{11}$$

Solution

Question 4

$$\dfrac{47}{6}$$

$$\dfrac{23}{6}$$

$$\dfrac{12}{13}$$

None of these

Solution

Question 5

$$2 : 9$$

$$5 : 9$$

$$7 : 9$$

$$1 : 9$$

Solution

Question 6

$$10:1$$ paise

$$100:1$$ paise

$$20:1$$ paise

None of these

Solution

Question 7

$$\dfrac 57$$

$$\dfrac 35$$

$$\dfrac 75$$

$$\dfrac 65$$

Solution

Question 8

$$\dfrac {16}3$$

$$\dfrac 34$$

$$\dfrac {16}9$$

None.

Solution

Question 9

$$1 : 12$$

$$1 : 13$$

$$1 : 14$$

None of these

Solution

Question 10

$$1:4$$

$$2:3$$

$$3:5$$

$$5:6$$

Solution

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