Ratio and Proportion Test

Result

Ratio and Proportion Test - 18

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The length and breadth of a rectangular field are $$50\ m$$ and $$15\ m$$ respectively. Find the ratio of the breadth to the length of the field.

A
$$3:5$$

B
$$3:10$$

C
$$3:15$$

D
$$10:3$$

Solution

The length of the rectangular field is $$50 m$$ and breadth of the field is $$15 m$$.

The ratio of breadth and length is,

$${\rm{breadth}}:{\rm{length}} = 15:50=\dfrac{15}{50}=\dfrac{3}{10}$$

$$ = 3:10$$
Question 2
1 / -0

Two numbers are in the ratio $$3 : 5$$. If the sum of numbers is $$144$$, then the small number is

A
$$54$$

B
$$72$$

C
$$90$$

D
$$48$$

Solution

$$\displaystyle 144\times \frac{3}{8}=54$$

$$\displaystyle 144\times \frac{5}{8}=90$$
the smaller number is $$54$$
Question 3
1 / -0

Find the ratio $$50$$ paise to Rs. $$5$$

A
$$10:1$$

B
$$1:1$$

C
$$1:10$$

D
None of these

Solution

$${\textbf{Step - 1: Converting rupees to paise}}$$

$${\text{We know that, 1 Rupee = 100 paise}}$$

   $$\therefore {\text{ 5 Rupees = }}\dfrac{{{\text{5 }} \times {\text{ 100}}}}{{\text{1}}}{\text{ paise}}$$

   $$ \Rightarrow {\text{ 5 Rupees = 500 paise}}$$ $$\quad \text{.........eqn(i)}$$

$${\textbf{Step - 2: Substitute above result and get required ratio}}$$

   $${\text{Ratio of 50 paise to 5 Rupees = }}$$$$ {\text{ }}\dfrac{{{\text{50 paise}}}}{{{\text{5 Rupees}}}}$$

    $$ ={\text{ }}\dfrac{{{\text{50 paise}}}}{{{\text{500 paise}}}}$$ $$\quad \textbf{[From eqn(i)]}$$

    $$= {\text{ }}\dfrac{{\text{1}}}{{{\text{10}}}}$$

$${\textbf{Thus, the ratio of 50 paise to 5 Rupees is 1:10. Option C is correct.}}$$
Question 4
1 / -0

Find the reduced form of the ratio of the first quantity to second quantity.
$$3.8$$ kg, $$1900$$ gm.

A
2:1

B
1:2

C
1:4

D
1:8

Solution

Reduced form of $$3.kg$$ and $$1900gm$$ in ratio
firstly kg change into gms
if $$1kg$$ =$$1000gm$$
than $$3.8kg$$ = $$3.8 \times 1000$$ = $$3800gm$$
then, ratio
$$\frac{{3800}}{{1900}} = \frac{2}{1} = 2:1$$
Question 5
1 / -0

Find the reduced form of the ratio of the first quantity to second quantity.
$$7$$ minutes $$20$$ seconds, $$5$$ minutes $$6$$ seconds.

A
111:345

B
234:151

C
220:153

D
None

Solution

Reduced form of 7 min 20 sec, 5 min 6 sec is
firstly change minute in second
\begin{array}{l} \frac { { 7\times 60+20 } }{ { 5\times 60+6 } } \\ =\frac { { 420+20 } }{ { 300+6 } } \\ =\frac { { 440 } }{ { 306 } } \\ =\frac { { 220 } }{ { 153 } } =220:153 \end{array}
Question 6
1 / -0

Present age of father is $$42$$ years and that of his son is $$14$$ years. Find the ratio of present age of father to the present age of son.

A
3:1

B
1:2

C
1:3

D
1:1

Solution

$$Ratio=\dfrac{Present\ age\ of\ father}{Present\ age\ of\ son.}$$
$$=\dfrac{42}{14}$$
$$\boxed{Ratio=3:1}$$
Question 7
1 / -0

Find the reduced form of the ratio of the first quantity to second quantity.
$$3$$ years $$4$$ months, $$5$$ years $$8$$ months.

A
17:10

B
10:17

C
10:15

D
15:10

Solution

firstly year change into months
$$1$$ year = $$12$$ months
$$3$$ years = 12x3 = $$36$$ months
$$5$$ years = 12x5 = $$60$$ months
Then reduced form are in ratio
\begin{array}{l} \dfrac { { 3\, years\, \, 4\, months } }{ { 5years\, \, 8\, \, months } } \\ =\dfrac { { \left( { 36+4 } \right) \, \, months } }{ { \left( { 60+8 } \right) \, \, months } } \\ =\dfrac { { 40 } }{ { 68 } } \\ =\dfrac { { 10 } }{ { 17 } } =10:17 \end{array}
Question 8
1 / -0

Find the reduced form of the ratio of the first quantity to second quantity.
$$5$$ litres, $$2500$$ ml.

A
$$1:2$$

B
$$2:1$$

C
$$1:3$$

D
$$3:4$$

Solution

Reduced form of $$5$$ liters and $$2500\text{ ml}$$
in ratio
$$[1$$ liter $$= 1000\text{ ml},$$ so $$5$$ liters$$ = 5000\text{ ml}]$$
$$=\dfrac{{5\,\text{liters}}}{{2500\text{ml}}}\,\,\,\,\,$$

$$=\dfrac{{5000}}{{2500}}\,\,\,\,\,$$

$$=\dfrac{2}{1} \implies 2:1$$
Question 9
1 / -0

The ratio of 40 minutes to 2.5 hours is:

A
$$4:17$$

B
$$4:18$$

C
$$4:13$$

D
$$4:15$$

Solution

Given quantities are $$40\ minutes$$ and $$2.5\ hours$$.

Hence, their ratio will be: $$\dfrac {40\ min}{2.5\ hr}$$

We see that the units of the two quantities are not same.

Hence, using the relation $$1 \ hour=60\ minutes$$, we get:

$$\dfrac {40\ min}{2.5\times 60\ min}=\dfrac {40}{150}$$

$$=\dfrac {40}{150}$$

$$ \Rightarrow 4:15$$

Hence, the required ratio is $$4:15$$.
Question 10
1 / -0

A class consists of 32 boys and 18 girls then the ratio of number of boys to the total number of students in the class is_____

A
16:25

B
25:16

C
9:25

D
25:9

Solution

We have,

Number of boys $$=32$$

Number of girls $$=18$$

Then,

Total students in class

$$ =32+18 $$

$$ =50 $$

The ratio of number of boys to students in class is

$$ =\dfrac{Boys}{Total\,students} $$

$$ =\dfrac{32}{50} $$

$$ =\dfrac{16}{25} $$
$$=16:25$$

Hence, this is the answer.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Ratio and Proportion Test - 18

Result

Ratio and Proportion Test - 18

Score

-

Rank

-

SHARING IS CARING

Question 1

$$3:5$$

$$3:10$$

$$3:15$$

$$10:3$$

Solution

Question 2

$$54$$

$$72$$

$$90$$

$$48$$

Solution

Question 3

$$10:1$$

$$1:1$$

$$1:10$$

None of these

Solution

Question 4

2:1

1:2

1:4

1:8

Solution

Question 5

111:345

234:151

220:153

None

Solution

Question 6

3:1

1:2

1:3

1:1

Solution

Question 7

17:10

10:17

10:15

15:10

Solution

Question 8

$$1:2$$

$$2:1$$

$$1:3$$

$$3:4$$

Solution

Question 9

$$4:17$$

$$4:18$$

$$4:13$$

$$4:15$$

Solution

Question 10

16:25

25:16

9:25

25:9

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.