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Playing with Numbers Test - 12

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Playing with Numbers Test - 12
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  • Question 1
    1 / -0
    $$1$$ is a ............ of every prime number.
    Solution
    $$1$$ is a factor of prime number.
  • Question 2
    1 / -0
    Highest common factor of $$10$$ and $$100$$ is
    Solution
    First we will write $$10$$ and $$100$$ as product of its prime factors,
      $$10=5\times 2$$
    $$100=5\times 2\times 5\times 2$$

    So, from above we can observe that $$5$$ and $$2$$ is common factors,
    $$HCF (10,100)= 5\times 2$$
                                $$=10$$

    So, option $$A$$ is correct.
  • Question 3
    1 / -0
    Identify the prime number among the following options.
    Solution
    $$11$$ is a prime number because it has only two factors that are $$1$$ and $$11$$.
    So, option A is correct.
  • Question 4
    1 / -0
    Addition of prime number
    Solution
    $$2$$ and $$3$$ are prime numbers
    $$7$$ and $$5$$ are prime numbers
    $$2 + 3 = 5$$ (prime) but $$7 + 5 = 12$$ (composite).
    So, option C is correct.
  • Question 5
    1 / -0
    Choose the co-prime numbers from the following pairs
    Solution
    When two numbers have no common factors other than 1 then they are said to be co-prime numbers.
    A. 7 is the common factor of 7 & 63.
    B. 4 is the common factor of 36 & 28.
    C. 7 is the common factor of 35 & 21.
    Hence, answer will be D.
  • Question 6
    1 / -0
    Which of the following is the factor of all prime numbers?
    Solution
    Option $$A$$ is correct because $$1$$ is the factor of all prime numbers.
  • Question 7
    1 / -0
    Which of the following numbers are divisible by $$2$$ ?
    Solution
    Divisibility by 2:
    If the number contains an even number (0, 2, 4, 6, 8) in the units place, 
    then the number is completely divisible by $$2$$.

    All the options given here are even numbers i.e $$64$$ ends with $$4$$, 
    $$16$$ with $$6$$ and $$32$$ ends with $$2$$

    So, option D is correct.
  • Question 8
    1 / -0
    Which of the following numbers are divisible by $$2$$?
    Solution
    For a number to be divisible by $$2$$, it must contain an even digit in its unit place.
    Since, $$62$$ ends with $$2$$.
    Therefore, it is divisible by $$2$$.
    So, option B is correct.
  • Question 9
    1 / -0
    Identify co-prime numbers.
    Solution
    $$(2, 3)$$ has $$1$$ factor in common
    $$(3, 5)$$ has $$1$$ factor in common
    $$(5, 7)$$ has $$1$$ factor in common
    So, option D is correct.
  • Question 10
    1 / -0
    Co-prime numbers
    Solution
    Co-prime numbers have one factor in common.
    So, option B is correct.
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