Integers Test

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Integers Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

The additive identity for integers is

A
$$0$$

B
$$1$$

C
$$0.1$$

D
$$2$$

Solution

$$\textbf{Step 1: Define and find additive Identity }$$
$$\text{An identity element that in a given mathematical system leaves unchanged any element}$$
  $$\text{to which it is added. }$$
$$\text{We know that any number added to 0 is still the same number and }$$
  $$\text{hence the system doesn't change}$$
  $$\text{for any integer a we will have a+0=a=0+a }$$
$$\implies \text{0 is an additive identity}$$

$$\textbf{Thus, the additive identity for integers is 0}$$
Question 2
1 / -0

Evaluate:$$144\div-12$$

A
$$12$$

B
$$-12$$

C
$$1$$

D
$$2$$

Solution

The positive integer $$144$$ can be divided by a negative integer $$-12$$ as follows:

$$144\div -12=-\dfrac { 144 }{ 12 } $$

$$=-12$$

Hence, $$144\div -12=-12$$.
Question 3
1 / -0

Additive inverse of $$(24-(-4))$$ is:

A
$$-28$$

B
$$28$$

C
$$1$$

D
$$0$$

Solution

$$(24-(-4))= 24+4 = 28$$

Let additive inverse of $$28$$ be $$x$$.
Then $$28+x = 0$$
$$\therefore x = -28$$
Question 4
1 / -0

Additive inverse of $$10 $$ is

A
$$0$$

B
$$-10$$

C
$$8$$

D
none

Solution

Let additive inverse of $$10$$ be $$x$$.
$$10+x = 0$$

$$\therefore x = -10$$
Question 5
1 / -0

For any integer a, $$a\times1=1\times a=$$

A
$$1$$

B
$$0$$

C
$$a$$

D
can not be calculated

Solution

The multiplicative identity property states that any time you multiply an integer by $$1$$, the result, or product, is that original number.

To write out this property using variables, we can say that $$n\times 1 = n$$. It doesn't matter if $$n$$ equals to one, one million or $$3.566879$$. The property always holds true.,

Hence, $$a\times 1=1\times a=a$$
Question 6
1 / -0

Let the value of $$ A= 5$$ and $$B=9$$
Then the value of $$(-A)+(-B)$$ is

A
$$-14$$

B
$$14$$

C
$$45$$

D
$$-45$$

Solution

To add 2 negative numbers just add the absolute value of each number together, put a negative sign in front
$$(-A)+(-B)=-(A+B)\\ \Rightarrow (-5)+(-9)=-(9+5)=-14$$
Question 7
1 / -0

Solve $$(-24) + (-96) = $$

A
$$-120$$

B
$$96$$

C
$$120$$

D
$$-96$$

Solution

$$(-24) + (-96)$$
$$(-24-96)$$
$$= -120$$
Question 8
1 / -0

Evaluate:$$-456\div12$$

A
$$38$$

B
$$-38$$

C
$$1$$

D
$$2$$

Solution

The negative integer $$-456$$ can be divided by a positive integer $$12$$ as follows:

$$-456\div 12=-\dfrac { 456 }{ 12 } =-38$$

Hence, $$-456\div 12=-38$$
Question 9
1 / -0

The addition of two negative numbers is always a

A
positive number

B
zero

C
negative number

D
none of these

Solution

Addition of two negative number is always negative.
Suppose $$A$$ and $$B $$ are the absolute value of negative number $$-A$$ and $$-B$$, Then the addition number is:
$$(-A)+(-B) =-(A+B)$$ ( Where $$-(A+B)$$ is negative)
Question 10
1 / -0

The value of $$(-3) +(-11)$$ is

A
$$-33$$

B
$$-8$$

C
$$-11$$

D
$$-14$$

Solution

$$\textbf{Step -1: Calculation}$$
$$\text{Given to calculate :}(-3)+(-11)$$
$$\implies -(3+11)=-14$$
$$\textbf{Hence, option (D) is correct. }$$

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Integers Test - 28

Result

Integers Test - 28

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SHARING IS CARING

Question 1

$$0$$

$$1$$

$$0.1$$

$$2$$

Solution

Question 2

$$12$$

$$-12$$

$$1$$

$$2$$

Solution

Question 3

$$-28$$

$$28$$

$$1$$

$$0$$

Solution

Question 4

$$0$$

$$-10$$

$$8$$

none

Solution

Question 5

$$1$$

$$0$$

$$a$$

can not be calculated

Solution

Question 6

$$-14$$

$$14$$

$$45$$

$$-45$$

Solution

Question 7

$$-120$$

$$96$$

$$120$$

$$-96$$

Solution

Question 8

$$38$$

$$-38$$

$$1$$

$$2$$

Solution

Question 9

positive number

zero

negative number

none of these

Solution

Question 10

$$-33$$

$$-8$$

$$-11$$

$$-14$$

Solution

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