Data Handling Test

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Data Handling Test - 20

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Weekly Quiz Competition

Question 1
1 / -0

The mean of 3, 8, 6 , 17, 16 , is

A
8

B
10

C
12

D
14

Solution

The mean is nothing but the average of the given quantities,
$$\therefore mean=\dfrac{3+8+6+17+16}{5}$$
$$\to mean=\dfrac{50}{5}$$
$$mean=10$$
Question 2
1 / -0

The marks of a class test are given below.
$$28, 26, 17, 12, 14, 19, 27, 26, 21, 16, 15$$. Find the median.

A
$$15$$

B
$$17$$

C
$$19$$

D
$$21$$

Solution

The marks in the test are: $$28, 26, 17, 12, 14, 19, 27, 26, 21, 16, 15$$
Arranging the marks in the test in ascending order: $$12, 14, 15, 16, 17, 19, 21, 26, 26, 27, 28$$
There are $$11$$ values. Since, it is an odd number, median will be the $$6^{th}$$ number after arranging the marks in ascending order.
Hence, median $$= 19$$
Question 3
1 / -0

The mode of 9, 8, 7, 7, 6, 3, 7, 2, 1, 7, 9 is

A
6

B
7

C
3

D
9

Solution
Question 4
1 / -0

The attendance of a class of $$45$$ boys for $$10$$ days is given as $$40, 42, 30, 35, 45, 44, 41, 38, 44$$ and $$41$$, then the mean attendance of a class is

A
$$39$$

B
$$40$$

C
$$41$$

D
$$43$$

Solution

Mean attendance of the class for 10 days $$= \cfrac{\text{Total attendance}}{\text{Number of days}}$$
$$=\cfrac{40 + 42 + 30 + 35 + 45 + 44+ 41 + 38+ 44 +41}{10}$$
$$=\cfrac{400}{10}$$
$$= 10$$
Question 5
1 / -0

If the range of $$14, 12, 17, 18, 16, x$$ is $$20$$ and $$x>0$$, the value of $$x$$ is:

A
$$2$$

B
$$28$$

C
$$32$$

D
cannot be determined

Solution

The range is the difference between the smallest value and the largest value of the data set.
Given data set is $$14, 12, 17,18,16,x$$ and the range is given as $$20$$.
In the given set the smallest value is $$12$$ and the largest value is $$18$$.
Therefore the range is $$18-12=6\neq20$$
Hence, $$18$$ is not the largest value. Variable $$x$$ is the largest value.
Therefore, range is $$x-12=20$$
$$\implies x=20+12=32$$
Question 6
1 / -0

Shrikant reads the following number of pages of a book daily. Find the mean.
$$34, 43, 29, 51, 36, 41, 38, 35, 34, 36, 34, 38, 40, 36, 35,$$
$$35, 34, 35, 36, 34, 38, 38, 35, 36, 34, 38, 36, 34, 35, 36 $$

A
$$35.47$$

B
$$35.67$$

C
$$36$$

D
$$36.47$$

Solution

The data numbers are: $$34, 43, 29, 51, 36, 41, 38, 35, 34, 36, 34, 38, 40, 36, 35, 35, 34, 35, 36, 34, 38, 38, 35, 36, 34, 38, 36, 34, 35, 36$$
Mean = $$\cfrac{\text{Sum}}{\text{Total Numbers}}$$
Sum of Numbers $$= 34 + 43 + 29 + 51 + 36 + 41 + 38 + 35 + 34 + 36 + 34 + 38 + 40 + 36 + 35 + 35$$
$$+ 34 + 35 + 36 + 34 + 38 + 38 + 35 + 36 + 34 + 38 + 36 + 34 + 35 + 36$$
Sum $$= 1094$$
Total Numbers $$= 30$$
Mean $$= \cfrac{1094}{30}$$
Mean $$= 36.47$$
Question 7
1 / -0

Find the mean of:
$$6.2, 5.6, 4.8, 11.2, 12.5, 7.4$$ and $$6.3$$

A
$$\displaystyle 7\frac{5}{7}$$

B
$$\displaystyle 8\frac{5}{7}$$

C
$$\displaystyle 9\frac{5}{7}$$

D
$$\displaystyle 10\frac{5}{7}$$

Solution

We need to find mean of $$6.2, 5.6, 4.8, 11.2, 12.5, 7.4$$ and $$6.3$$.
Therefore, mean $$=\dfrac {6.2+5.6+4.8+11.2+12.5+7.4+6.3}{7}$$
$$=\dfrac {54}{7}$$
$$=7+\dfrac {5}{7}$$
$$=7\dfrac {5}{7}$$
Question 8
1 / -0

Find the Arithmetic Mean of the numbers 7, 6, 5, 9, 8, 0, 7

A
5

B
6

C
7

D
14

Solution

The Arithmetic Mean of numbers is calculated by using the below formula,

A.M of numbers$$=\dfrac{\text{sum of the numbers}}{ \text{Total numbers}}$$

$$=\dfrac{7+6+5+3+8+6+7}{7}$$

$$=\dfrac{42}{7}$$

$$=6$$

Option $$[B]$$ is correct.
Question 9
1 / -0

The mean monthly salary of the $$12$$ employees of a firm is Rs. $$1450$$. If one more person joins the firm who gets Rs. $$1645$$ per month, what will be the mean monthly salary of $$13$$ employees?

A
Rs. $$1465$$

B
Rs. $$1954$$

C
Rs. $$2175$$

D
Rs. $$2569$$

Solution

Mean salary of $$12$$ employees $$=$$ Rs. $$1450$$
Sum of salary of $$12$$ employees $$= 12\times 1450 =$$ Rs. $$17400$$
A new employee joins the firm and he gets, Rs $$1645$$
Hence, new sum of salary $$= 17400 + 1645 = 19045$$
New mean $$= \dfrac{19045}{13} = 1465$$
The new mean salary of all the employees is Rs. $$1465$$
Question 10
1 / -0

The heights (in $$cm$$) of $$8$$ girls of a class are $$140, 142, 135, 133, 137, 150, 148$$ and $$138$$ respectively. Find the mean height of these girls.

A
$$137.375$$

B
$$139.375$$

C
$$140.375$$

D
$$143.375$$

Solution

Mean is the average of the values of the data set.
Given the height of the girls are $$140,142,135,133,137,150,148,138$$
The total number of girls is $$8$$

Therefore, $$\text{mean}=\dfrac{140+142+135+133+137+150+148+138}{8}$$

$$\implies \text{mean}=\dfrac{1123}{8}=140.375$$

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 20

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Data Handling Test - 20

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Question 1

8

10

12

14

Solution

Question 2

$$15$$

$$17$$

$$19$$

$$21$$

Solution

Question 3

6

7

3

9

Solution

Question 4

$$39$$

$$40$$

$$41$$

$$43$$

Solution

Question 5

$$2$$

$$28$$

$$32$$

cannot be determined

Solution

Question 6

$$35.47$$

$$35.67$$

$$36$$

$$36.47$$

Solution

Question 7

$$\displaystyle 7\frac{5}{7}$$

$$\displaystyle 8\frac{5}{7}$$

$$\displaystyle 9\frac{5}{7}$$

$$\displaystyle 10\frac{5}{7}$$

Solution

Question 8

5

6

7

14

Solution

Question 9

Rs. $$1465$$

Rs. $$1954$$

Rs. $$2175$$

Rs. $$2569$$

Solution

Question 10

$$137.375$$

$$139.375$$

$$140.375$$

$$143.375$$

Solution

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