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Data Handling Test - 24

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Data Handling Test - 24
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  • Question 1
    1 / -0
    What is the average of four tenths and five thousandths?
  • Question 2
    1 / -0
    The monthly fees for single rooms at $$5$$ colleges are $$370$$, $$310$$, $$380$$, $$340$$, and $$310$$, respectively. What is the mean of these monthly fees?
    Solution
    The mean is same like average. Add all and then divide by the number of colleges.
    Average $$=$$ $$\dfrac {(370+310+380+340+310)}{5}=\dfrac {1710}{5}=342$$
    Therefore the mean of these monthly fees is $$342$$.
    Hence, option $$C$$ is correct.
  • Question 3
    1 / -0
    In a class of $$100$$ students there are $$70$$ boys whose average marks in a subject are $$75$$. If the average marks of the complete class is $$72$$, then what is the average of the girls?
    Solution
    Number of boys $$= 70$$
    Average marks of boys  $$=75$$
    Total marks of boys $$=70 \times 75=5250$$
    Total marks of the class $$=72 \times 100 =7200$$
    Total marks of girls $$=1950$$
    Average of the girls $$=\dfrac{1950}{30}=65$$
  • Question 4
    1 / -0
    The  range of the following data is:
    $$84,56,39,45,54,39,56,54,84,21,77,56$$ 
    Solution
    Range of a data is the difference between the smallest and the largest number in the data.
    In the guven data:
    Smallest number $$=21$$
    Largest number $$=84$$
    Hence, Range $$={84-21}=63$$

  • Question 5
    1 / -0
    The Arithmetic mean of integers from $$-5$$ to $$5$$ is
    Solution
    All integers from $$-5$$ to $$5$$ are:
    $$-5,\ -4,\ -3,\ -2,\ -1,\ 0,\ 1,\ 2,\ 3,\ 4,\ 5$$.

    We know that, arithmetic mean $$=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$$

    Hence, sum of all numbers $$=(-5)+(-4)+(-3)+(-2)+(-1)+ 0+ 1+2+3+4+5$$
    $$=0$$

    Total integers $$=11$$

    Hence, arithmetic mean $$=\dfrac{0}{11}$$
    $$=0$$.

    Hence, the arithmetic mean of integers from $$-5$$ to $$5$$ is $$0$$.
  • Question 6
    1 / -0
    The Arithmetic mean of all the factors of $$24$$ is
    Solution
    $$\Rightarrow$$  Factors of $$24$$ are $$1,\,2,\,3,\,4,\,6,\,8,\,12,\,24$$
    So, the observations are $$1,2,3,4,6,8,12,24$$
    $$\therefore$$  Number of observations $$=8$$
    Arithmetic mean $$=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$$

    $$\therefore$$ Arithmetic mean $$=\dfrac{1+2+3+4+6+8+12+24}{8}$$

    $$\therefore$$  Arithmetic mean $$=\dfrac{60}{8}$$

    $$\therefore$$  Arithmetic mean $$=7.5$$
  • Question 7
    1 / -0
    The mean of first $$5$$ whole numbers is
  • Question 8
    1 / -0
    The mathematical formula for joint probabilities $$P(AB) =P(A/ B)\times P(B)$$, holds when ___________________.
  • Question 9
    1 / -0
    The probability of A passing CPT exam is $$60\%$$ and that of B's Passing is $$70\%$$, what is the probability that both of them will pass CPT exam.
  • Question 10
    1 / -0
    The bar graph shows the number of traffic accidents in a country from year $$2000$$ to $$2014$$ . What is the difference between accidents in the year $$2001$$ and $$2004$$.

    Solution
    The letter $$k$$ is used to denote $$1000$$

    Therefore, Number of traffic accidents in the year $$2001$$ $$=260k$$

                                                                                                  $$=260\times1000$$

                                                                                                  $$=260,000$$

    Number of traffic accidents in year $$2004$$ $$=220k$$

                                                                         $$=220\times1000$$

                                                                         $$=220,000$$.

    Then, the difference $$=260,000-220,000$$

                                       $$=40,000$$

    Therefore, option $$B$$ is correct.
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