Data Handling Test

Result

Data Handling Test - 26

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Weekly Quiz Competition

Question 1
1 / -0

$$9898, 8998, 9889, 8899, 9988, 8989, 9998$$.
If the numbers above are arranged in an ascending or descending order. Which number will appear in the middle place?

A
$$9889$$

B
$$8998$$

C
$$8899$$

D
$$9898$$

Solution
Question 2
1 / -0

Mode of the data $$3,2,5,2,3,5,6,6,5,3,5,2,5$$ is

A
$$6$$

B
$$4$$

C
$$3$$

D
$$5$$

Solution

$${\textbf{Step -1: Find the number used maximum times.}}$$
$${\text{Given numbers: 3,2,5,2,3,5,6,6,5,3,5,2,5}} $$

$$ {x_i}:{\text{2 3 5 6}} $$

$$ {f_i}:{\text{3 3 5 2 }} $$

$$\rightarrow {x_i} = {\text{Given numbers}} $$
$$\rightarrow {f_i} = {\text{how many times Given number is written}} $$

$$ {\text{Mode of the data is the maximum times a number is repeated in the given data}}{\text{.}} $$

$${\text{Since 5 is repeated maximum times in the given data, mode is 5.}}$$

$$ {\textbf{Hence, The correct answer is option D}} $$
Question 3
1 / -0

The mean of squares of consecutive odd numbers from 1 to 13 is

A
70

B
65

C
75

D
66

Question 4

1 / -0

The following bar graph shows the number of persons killed in industrial accidents in country for some years.
Read the bar graph and choose the correct alternative in each of the following:
The year which shows the maximum decrease in the number of persons killed in industrial accidents over the preceding year is:

1996

1997

1998

1999

Solution

Let's draw a chart using the information from the above bar graph:

Year	Persons killed in industrial accidents	Persons killed in coal mines
$$1995$$	$$1600$$	$$300$$
$$1996$$	$$900$$	$$200$$
$$1997$$	$$1200$$	$$300$$
$$1998$$	$$1300$$	$$100$$
$$1999$$	$$900$$	$$100$$
$$2000$$	$$1300$$	$$100$$

Both the years, $$1996$$ and in $$1999$$ show a decrease in the amount of persons killed by industrial accidents.

$$\therefore$$ percentage decrease in the amount of death due to industrial accidents in the year $$1996\Rightarrow$$ from $$1600$$ to $$900$$.

$$\therefore$$ percentage decrease in the amount of death death due to industrial accidents in the year $$1999\Rightarrow$$ from $$1300$$ to $$900$$

So, $$\text{A}$$ is the correct option.

Question 5
1 / -0

The following bar graph shows the results of an annual examination in a secondary school. Read the bar graph and choose the alternative in each of the following:
The class having the lowest failure rate of girls is

A
VII

B
X

C
IX

D
VIII

Solution
Question 6
1 / -0

The mean for the data $$6, 7, 10, 12, 13, 4, 8 ,12$$ is:

A
$$9$$

B
$$8$$

C
$$7$$

D
$$6$$

Solution

We have,
$$x_i=6,7,10,12,13,4,8,12$$

$$\therefore \text{Mean} =\dfrac{\text{Sum of all the observations}}{\text{Total number of observations}}$$

$$=\dfrac{6+7+10+12+13+4+8+12}{8}$$

$$=\dfrac{72}{8}=9$$
Question 7
1 / -0

The choices of the fruits of 42 students in a class are as follows:
A, O, B, M, A, G, B, G, A, G, B, M. A, O, M, A, B, G, M, B, A, O, M, O, G, B, O, M, G, A, A, B, M, O, M, G, B, A, M, O, M, O,
where A, B, G, M, and O stands for Apple, Banana, Grapes, Mango and Orange respectively.
which fruit is liked
by most of the students?

A
O

B
G

C
M

D
A

Solution

The number of $$A$$ appearing in the list is $$9$$

The number of $$B$$ appearing in the list is $$8$$

The number of $$G$$ appearing in the list is $$7$$

The number of $$M$$ appearing in the list are $$10$$

The number of $$O$$ appearing in the list are $$8$$

So, $$M$$ appeared the most, and $$M$$ stands for Mango.

So, Mango $$M$$ is the fruit that is liked by most of the students.
Question 8
1 / -0

The number of trees in different parks of a city is $$ 33,38,48,33,34,34,33$$ and $$ 24$$. The mode of this data is

A
$$24$$

B
$$34$$

C
$$33$$

D
$$48$$

Solution

The given data in ascending order is $$24,33,33,33,34,34,38$$ and $$48$$,
The mode of data is $$33$$ because the frequent of occurrence of $$33$$ is highest.
Question 9
1 / -0

Let $$ x,y,z$$ be three observations. The mean of these observation is

A
$$\dfrac{x\times y \times z}{3}$$

B
$$\dfrac{x+y+z}{3}$$

C
$$\dfrac{x-y-z}{3}$$

D
$$\dfrac{x \times y+ z}{3}$$

Solution

We know that
$$\text{Mean}=\dfrac{\text{sum of observations}}{\text{number of observations}}$$

$$\therefore \text{ Mean}=\dfrac{x+y+z}{3}$$
Question 10
1 / -0

The range of the data $$ 30,61,55,56,60,20,26,46,28,56 $$ is

A
$$ 26 $$

B
$$ 30 $$

C
$$ 41 $$

D
$$ 61 $$

Solution

Range of Data= Maximum value - Minimum value $$= 61-20=41. $$

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 26

Result

Data Handling Test - 26

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Rank

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SHARING IS CARING

Question 1

$$9889$$

$$8998$$

$$8899$$

$$9898$$

Solution

Question 2

$$6$$

$$4$$

$$3$$

$$5$$

Solution

Question 3

70

65

75

66

Question 4

1996

1997

1998

1999

Solution

Question 5

VII

X

IX

VIII

Solution

Question 6

$$9$$

$$8$$

$$7$$

$$6$$

Solution

Question 7

O

G

M

A

Solution

Question 8

$$24$$

$$34$$

$$33$$

$$48$$

Solution

Question 9

$$\dfrac{x\times y \times z}{3}$$

$$\dfrac{x+y+z}{3}$$

$$\dfrac{x-y-z}{3}$$

$$\dfrac{x \times y+ z}{3}$$

Solution

Question 10

$$ 26 $$

$$ 30 $$

$$ 41 $$

$$ 61 $$

Solution

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