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Data Handling Test - 9

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Data Handling Test - 9
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  • Question 1
    1 / -0
    Median divides the total frequency into _____ equal parts.
    Solution
    The median of the data series is the middle term or the mean of the two middle terms.
    Hence, it divides the data series or the frequency of terms into two equal halves.
  • Question 2
    1 / -0
    If P (E) denotes the probability of an event E, then
    Solution
    Probability is the measure of the likelihood that an event will occur.
     Probability is referred as a number between 0 and 1.
     0 indicates impossibility and 1 indicates certainty. The higher the probability of an event, the more likely it is that the event will occur.
    so, the Probability of an even always lies between 0 and 1.
    $$0≤P(E)≤1$$ is correct.
  • Question 3
    1 / -0
    When a die is thrown, list the outcomes of an event of getting a prime number.
    Solution
    For a dice, the possible outcomes are, $$1,2,3,4,5,6$$

    To get a prime number, the possible outcomes are, $$2,3,5$$
  • Question 4
    1 / -0
    Which one of the following cannot be the probability of an event?
    Solution
    Probability value lies between $$0$$ and $$1.$$ 

    Where $$0$$ is the probability of an impossible event while $$1$$ is the probability of a sure event.

    and $$\dfrac{2}{3}$$ lies between $$0$$ and $$1$$.

    But $$-\dfrac{1}{6}<0$$, so it can't be the probability of any event.

    The option $$C$$ is a negative number hence is the correct option.
  • Question 5
    1 / -0
    In an experiment, the sum of probabilities of all events is :
    Solution
    A probability distribution is a collection of probabilities that defines the likelihood of observing all of the various outcomes of an event or experiment.
    The sum of the probabilities  of all the events is always 1. 
  • Question 6
    1 / -0
    Which of the following cannot be the probability of an event?
    Solution
    For any event A, the probability that A will occur is a number between 0 and 1,
    inclusive:
    $$0 ≤ P(A) ≤ 1$$
    For a sure event Probability of event is $$1$$
    $$\dfrac{3}{5}=0.6<1$$
    $$25\%=\dfrac{25}{100}=0.25<1$$
    $$0.3<1$$
    But $$1.5>1$$
    Hence option A is not possible
  • Question 7
    1 / -0
    Can the probability of an event be greater than 1? If yes enter 1 else 0.
    Solution
    No, the  probability of an event cannot be a negative number.
    This is because of the Number of outcomes favorable to an event $$(E) \le$$  Number of all possible outcomes.
    So, $$0 \le  P\left( E \right)  \le  1$$
  • Question 8
    1 / -0
    Value of the middle-most observation(s) is called:
    Solution
    To find the Median, place the numbers in value order and find the middle number
    If there are two middle numbers, take the mean of the two numbers and this will be the median of the data set.
    The middle most observation of a data series is called the median of the series.
  • Question 9
    1 / -0
    A child says that the median of $$3, 14, 18, 20, 5$$ is $$18$$. What concept does the child missed about finding the median?
    Solution
    To calculate the median of any data series. The data series has to be arranged in the ascending order. The child hasn't arranged the data series in ascending order.
  • Question 10
    1 / -0
    The marks of $$20$$ students in a test were as follows:
    $$5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20.$$
    The mean is
    Solution
    Marks are: $$5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20.$$

    Sum of marks $$= 260$$
    Number of students $$= 20$$
    Mean $$=\dfrac{\text{Sum}}{\text{Numbers}} = \dfrac{260}{20} = 13$$
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