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Motion and Time Test - 10

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Motion and Time Test - 10
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  • Question 1
    1 / -0
    A man runs $$10 \ km$$ in $$30 \ min.$$ What is his speed?
    Solution
    We know that, 
    $$Speed = \dfrac{distance}{time}$$
    Given:
    Distance $$=10 \ km$$
    Time $$=30 min= \dfrac{30}{60} \ hr=0.5 \ hr$$
    Speed $$=\dfrac{10 \ km}{0.5 \ hr} = 20 \ km/h$$ 

    Option D is the answer.
  • Question 2
    1 / -0
    Find the odd one out:
    Solution
    A solar day is a time it takes for the Earth to rotate about its axis so that the Sun appears in the same position in the sky.
    A lunar day or moon is the period of time it takes for the Earth's Moon to complete one full rotation on its axis with respect to the Sun. Equivalently, it is the time it takes the Moon to make one complete orbit around the Earth and come back to the same phase.
    The second is the SI unit of time.
    A light-year is a unit of distance, and it is defined as the distance traveled by light in one year. 
    So, solar day, moon day, and second represent time while light-year represents the length.
  • Question 3
    1 / -0
    Which one of the following is travelling with the fastest speed?
    Solution
    To get the correct answer,we need to convert each speed in same unit i.e. m/s
    A)An athlete running with a speed of 10 m/s
    B)A bicycle moving with a speed of 200 m/min it can be written as
        $$=\frac{200}{60}m/s$$
        $$=3.33m/s$$
    C)A tortoise covering 100 metres in 15 minutes
       $$=\frac{100}{15}m/min$$
       $$=\frac{100}{{15}\times{60}}m/s$$
       $$=0.11m/s$$
    D)A motorcycle moving with a speed one km/h
       $$=1km/h$$
       $$=\frac{1000}{{1}\times{60}\times{60}}$$
       $$=0.27m/s$$
    Comparing A, B, C, and D one can easily say that answer is option A i.e.
    An athlete running with a speed of 10 m/s is the fastest.
  • Question 4
    1 / -0
    The cheetah is the fastest land animal that can attain a maximum speed of $$112~ km/h$$. Express this speed in $$m/s$$.
    Solution
    Given,
    The maximum speed by the cheetah, $$v=112\ km/h$$
    We know,
    $$1\ km=1000\ m$$
    $$1\ h=60\ min$$
    $$1\min=60\ s$$
    $$\therefore 1\ h=60\times 60=3600\ s$$

    $$v=\dfrac{112\times 1000}{3600}$$

    $$v=31.1\ m/s$$
  • Question 5
    1 / -0
    The odometer of a car reads $$57321.0\ km$$ when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to $$57336.0\ km$$ and also the speed will be:
    Solution

    Time from $$8.30$$ $$AM$$ to $$8.50$$ $$AM$$ = $$20$$ $$min$$ 

    $$20min=(20/60)h=(1/3)h$$
    =2060h=13h

    (a) Distance covered = Second reading - First reading = $$57336.0$$ $$km$$ - $$57321.0$$ $$km$$ = $$15$$ $$km$$

    (b) $$Speed=\dfrac{Distance}{Time}$$=$$\dfrac{15}{1/3}$$=$$45km/h$$

  • Question 6
    1 / -0
    The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 m/s. The driver sees in his rear view mirror the image of a truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be ________________.
    Solution
    Since the object and its image always remain at the same distance from the mirror, therefore, when the car is reversed at a speed of 2 m/s, its image also appears to move towards the mirror at the same speed, i.e., 2 m/s. Hence, the speed at which the image of the truck will appear to approach the car will be 2 m/s + 2 m/s = 4 m/s.
  • Question 7
    1 / -0
    Which of the following is not the unit of time ?
    Solution
    Microsecond, lunar month and leap year all represent time, but parallactic second or parsec is defined as the distance at which one astronomical unit subtends an angle of one arcsecond, which is equal to 3.26 light years.
  • Question 8
    1 / -0
    A boy running at an average speed of $$4 km/ hr$$ reaches school from his home in $$\dfrac{1}{2}\ hr$$. The distance of the school from his home is
    Solution
    Given:
    Average speed of the boy $$v =4\ km/h$$
     Time taken $$t =\dfrac{1}{2}$$hour
    Distance $$D=?$$
      
     We know that  $$Speed(v)=\dfrac{Distance(D)}{Time(t)}$$
            $$\Rightarrow Distance(D)=4\times\dfrac{1}{2}$$
            $$\Rightarrow Distance(D)=2\ km$$
  • Question 9
    1 / -0
    The SI unit of speed is:
    Solution
    The distance moved by an object in a unit time is known as speed.
    The SI unit of speed is $$m/s$$.
  • Question 10
    1 / -0
    What does the speed of a body describes about its motion ?
    Solution
    $$speed =\frac{distance}{time}$$ Speed tells us how fast or slow the distance is being covered by the moving body .Hence it denotes it's rapidity(Means how rapid the moving object is).


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