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Motion and Time Test - 11

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Motion and Time Test - 11
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  • Question 1
    1 / -0
    Which of the following graphs represents the movement of a car that is slowing down and comes to a complete stop?
    Solution
    Slope of the distance-time graph gives the instantaneous speed of the body.
    For the car to be slowing down with time, the slope of the graph must continuously decrease and finally becomes zero so as the car to stop. Thus, distance-time graph shown in option D is the correct answer.
  • Question 2
    1 / -0
    Calculate the distance travelled by a man walking at a speed of 5 km/hr in 36 minutes.
    Solution
    Given s = 5km/hr = 5 $$\displaystyle \times \frac{5}{18}m/s$$
    t = 36 minutes = 36 $$\displaystyle \times $$ 60 sec
    $$\displaystyle \therefore $$ distance travelled = s $$\displaystyle \times $$ t
               = $$\displaystyle \frac{25}{18}\times 36\times 60 = 3000  m$$
              = $$\displaystyle \frac{3000}{1000}km = 3 km $$
  • Question 3
    1 / -0
    How many seconds are there in 12 hours?
    Solution
    Total seconds in $$12\ hours$$-
    Total minutes in one hour,
    $$1\ h = 60\ min$$
    Total seconds in one min,
    $$1\ min = 60\ s$$

    So,
    $$12\ h = 12 \times 60 \times 60\ s$$
    $$\Rightarrow 12\ h = 12 \times 3600 \ s$$
    $$\Rightarrow 12\ h = 43200\ s$$
  • Question 4
    1 / -0
    A man runs $$20 \  km$$ in $$30 \ min.$$ What is his speed?
    Solution
    Given:
    Distance $$= 20 \ km$$
    Time $$=30 \ min =\dfrac{30}{60}hr= \dfrac { 1 }{ 2 } hr$$

    $$\therefore$$ Speed = $$\dfrac { Distance }{ time } $$ = $$\dfrac { 20 \ km}{ \left( \dfrac { 1 }{ 2 }hr \right) } $$
    $$\Rightarrow$$ Speed $$=40 \ km/hr$$

    Option (C) is correct.
  • Question 5
    1 / -0
    With what speed should a bus travel so that it can cover a distance of 10 km in 5 min?
    Solution
    $$60$$ $$min$$ = $$1hour$$
    $$5$$ $$min$$ = $$\dfrac { 1 }{ 60 } \times 5=\dfrac { 1 }{ 12 } h$$

    $$Speed$$ = $$\dfrac { Distance }{ Time } $$
    $$Distance=10km$$
    $$time=\dfrac{1}{12}h$$

    $$speed$$= $$\dfrac { 10 }{ \dfrac { 1 }{ 12 }  } $$ = $$10\quad \times \quad 12$$
               = $$120$$ $$km/h$$
  • Question 6
    1 / -0
    Which is not a necessary assumption for simple pendulum
    Solution
    All the other three option are important assumption used in while deriving the time period of Simple Harmonic Motion.
  • Question 7
    1 / -0
    The quantity which tells the distance an object travels in a certain time is called -
    Solution
    The quantity which tells the distance an object travels in a certain time is called speed.
    $$Speed = \dfrac{Distance}{Time}$$
  • Question 8
    1 / -0
    A boy cycles a distance of 640 m in 2 minutes and 40 seconds. What is the speed of the cycle?
    Solution
    Distance covered = 640 m
    Time taken = 2 min 40 sec
    = $$2$$ $$\displaystyle \times 60 + 40 = 160s$$    (because 1 minute =60seconds)
    $$\displaystyle \therefore Speed = \frac{Distance}{Time}= \frac{640}{160}=4m/s$$
  • Question 9
    1 / -0
    Which of the following formulae is correct?
    Solution
    Speed of an object is defined as distance moved per unit time.It denotes how fast or how slow the object is moving.It is given by
    $$Speed=\dfrac{Distance}{time}$$
  • Question 10
    1 / -0
    Right sequence in increasing magnitude is:

    Solution
    $$1 ns = 10^{-9} s$$ 
    $$1 week = $$ 7 $$days$$ = $$604800s$$ 
    $$1 decade = 10 yrs$$ = $$3.17\times 10^{-9}s$$
    So correct order is option C.
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