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Direct and Inverse Proportions Test - 11

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Direct and Inverse Proportions Test - 11
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  • Question 1
    1 / -0
    Which is example of inverse proportion?
    Solution
    2 quantities say it be $$x , y$$ are said to be in inverse proportion when the increse in value of $$x$$ , leads to the decrease in value of $$y$$.

    we know that,
    $$speed = \dfrac{distance}{time}$$

    i.e., Speed is directly proportion to distance and at a fixed distance  inverse proportion to time.

    Hence at fixed distance, if speed increses, time taken will decrease and vice versa. which is Option B
  • Question 2
    1 / -0
    Which is an example of inverse proportion?
    Solution
    2 quantities say it be $$x , y$$ are said to be in proportion when the change in value of $$x$$ , leads to the equal change in value of $$y$$.
    If $$x$$ increases and hence  $$y$$ decreases proportionally, it is called Inverse proportion i.e $$x\propto\dfrac{1}{y}$$
    For example, In option C, if our expenses are more, then we are left with lesser savings from a fixed salary or income.
    hence, Expenditure and savings are in inverse proportion.
    So the answer is C
  • Question 3
    1 / -0
    Cost of 10 mangoes is Rs. 100. The cost of 18 mangoes is__ 
    Solution
    Here, the cost of mangoes is directly proportional to the number of mangoes bought.

    So, if $$ 10 $$ mangoes costs $$ Rs.\  100 $$, then $$ 1 $$ mango will cost $$ Rs. \dfrac{ 100 }{10}  = Rs . 10 $$

    Therefore, $$ 18 $$ mangoes will cost $$= 18 \times \dfrac{ 100 }{10}  = Rs. 180 $$

  • Question 4
    1 / -0
    Eight oranges can be bought for Rs $$10.40$$, then how many more oranges can be bought for Rs $$16.90$$?
    Solution
    Let $$x$$ oranges  be bought for Rs.$$ 16.90.$$

    Given, eight oranges are bought for Rs.$$ 10.40.$$

    Then, $$\dfrac{8}{x}=\dfrac{10.40}{16.90}$$

    $$\Longrightarrow x=\dfrac{16.90\times 8}{10.40}=13$$

    Then, $$(13-8)=5$$ more oranges can be bought.
  • Question 5
    1 / -0
    $$ x$$ $$2$$$$ 5$$$$ 25$$
    $$ y$$ $$25$$ $$10$$ $$m$$
    If $$x$$ & $$y$$ are in inverse proportion, find m

    Solution
    The given example is of inverse proportion.
    by definition, 
    $$x\propto \dfrac{1}{y}$$ i.e. $$x = K\dfrac{1}{y}$$ , where $$K$$ is constant of proportionality
    $$\therefore xy = K$$
    $$x\times y = 2\times 25 = 50 = K$$
    now, $$25\times m = 50$$
    $$\therefore m = 2$$
    Answer is option B
  • Question 6
    1 / -0
    Find the value of $$x$$ if  $$a$$ and $$ b$$  are in direct proportion
      $$a$$$$2$$$$3$$$$4$$$$5$$
      $$b$$ $$14$$$$21$$$$x$$$$35$$
    Solution
    $$a$$ and $$b$$ are in direct proportion
    $$\therefore \dfrac {a}{b} = k = \dfrac {2}{14} = \dfrac {3}{21} = \dfrac {1}{7}$$
    $$\therefore \dfrac {4}{x} = \dfrac {1}{7} \Rightarrow x = 28$$.
  • Question 7
    1 / -0
    If x & y are in direct proportion then find the value of a

    x

    2

    3

    5

    7

    y

    4

    6

    a

    14

    Solution
    We know that, in direct proportion, the ratio of the quantities remains constant
    $$\therefore \ \dfrac{x}{y}=k$$ 
    $$\dfrac{2}{4}=\dfrac{3}{6}=\dfrac{5}{a}=\dfrac{7}{14}=k\;\Rightarrow\;k=\dfrac{1}{2}=\dfrac{5}{a}\;\Rightarrow\;a=10$$

    Thus option B is the correct answer.
  • Question 8
    1 / -0
    If $$x$$ & $$y$$ are in inverse proportion then find proportionality constant at $$x=3,\;y=2$$
    Solution
    Given that. $$x$$ and $$y$$ are inverse proportion,
    i.e. $$x \propto \dfrac{1}{y}$$
    $$\therefore xy = K$$, where $$K$$ is constant proportionality
    Given. 
    $$x = 3, y = 2$$
    $$\therefore 3\times2 = K = 6$$
    Answer is $$6$$
  • Question 9
    1 / -0
    $$14$$ apples cost $$Rs. 140.$$ Then, the cost of 1 apple is__
    Solution
    The cost of apples is directly proportional to the number of apples bought.

    So, if $$ 14 $$ apples cost $$ Rs\  140 $$, then $$ 1 $$ apple will cost $$ Rs \dfrac{ 140 }{14}  =  Rs  10 $$

  • Question 10
    1 / -0
     $$x$$ $$2$$$$ 3$$$$ 5$$$$ 6$$$$10$$
    $$ y$$ $$15$$ $$10$$$$ b$$ $$5$$$$ 3$$
    Identify the inverse proportional quantities.
    Solution
    The given example is of inverse proportion.
    by definition, 
    $$x\propto \dfrac{1}{y}$$ i.e. $$x = K\dfrac{1}{y}$$ , where $$K$$ is constant of proportionality
    $$\therefore xy = K$$
    $$x\times y = 2\times 15 = 30 = K$$
    now, $$5\times b = 30$$
    $$\therefore b = 6$$
    Answer is option C
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