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Squares and Square Roots Test - 28

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Squares and Square Roots Test - 28
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  • Question 1
    1 / -0
    Find the atleast number which must  be added to each of the following numbers to get a perfect square. Also find the square root of the perfect square numbers.

    $$a)525$$
    Solution
    $$i)\ 23^2=529$$
    $$\therefore \ $$ it will add $$4$$ to $$525$$ we get $$529$$
    which is payout square
    $$\therefore \ 525+4=529=23^2$$

    $$\therefore 4$$ should be added


  • Question 2
    1 / -0
    Which of the following is a Pythagorean triplet?
    Solution
    "Pythagorean triples" are integer solutions to the Pythagorean Theorem, $$a^2 + b^2 = c^2.$$

    $$A.$$ $$8,6,10$$
    $$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$$
    $$\Rightarrow$$  $$(10)^2=(8)^2+(6)^2$$
    $$\Rightarrow$$  $$100=64+36$$
    $$\Rightarrow$$  $$100=100$$ 
    $$\therefore$$   $$8,6,10$$ is a Pythagorean triplet

    $$B.$$ $$8,9,10$$
    $$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$$
    $$\Rightarrow$$  $$(10)^2=(8)^2+(9)^2$$
    $$\Rightarrow$$  $$100=64+81$$
    $$\Rightarrow$$  $$100\ne 146$$ 
    $$\therefore$$   $$8,9,10$$ is not a Pythagorean triplet

    $$C.$$ $$10,12,13$$
    $$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$$
    $$\Rightarrow$$  $$(13)^2=(10)^2+(12)^2$$
    $$\Rightarrow$$  $$169=100+144$$
    $$\Rightarrow$$  $$100\ne 244$$ 
    $$\therefore$$   $$10,12,13$$ is not a Pythagorean triplet
  • Question 3
    1 / -0
    Find $$\sqrt {125}$$ given $$\sqrt {5}=2.23607$$
    Solution
    $$\sqrt{125}$$
    $$=\sqrt{5\times 5\times 5}$$
    $$=5\sqrt{5}$$
    $$=5\times 2.23607$$
    $$=11.180$$.
  • Question 4
    1 / -0
    If $$\sqrt{2}=1.414$$ then the value of $$\sqrt{8}$$ is
    Solution
    $$\sqrt{2}=1.414$$(given)
    $$\sqrt{8}=\sqrt{2\times 2\times 2}=2\sqrt{2}=2\times 1.414=2.828$$
    $$\therefore \sqrt{8}=2.828$$
  • Question 5
    1 / -0
    Which of the following numbers are not perfect square?
    Solution
    These all are $$not$$ perfect square numbers because perfect square numbers always ends with $$(0,1,4,5,6,9)$$ and if if last digit is $$0$$ it should be even number of zeros.
    Therefore all the given numbers are not perfect square.
  • Question 6
    1 / -0
    Simplify : $$(64)^{1/2}$$
    Solution
    $$(64)^{1/2}$$
    $$=(8\times 8)^{1/2}$$
    $$=(8^2)^{1/2}$$
    $$=8^1$$
    $$=8$$.
  • Question 7
    1 / -0
    Square root of 169 is
    Solution

  • Question 8
    1 / -0
    Mark the correct alternative of the following.
    Which of the following is/are not Pythagorean triplet(s)?
    Solution
    We have to check for pythagorean triplets.

    Option (A) $$3, 4, 5$$
    It is easy to check that $$3^2 + 4^2 = 5^2$$
                                              $$25 = 25$$
    $$3, 4, 5$$ is pythagorean triplet.

    Option (B) $$8 , 15 , 17$$
    Observe that $$8^2 + 15^2 = 64 + 225$$
                                           $$= 289 $$
                                           $$= 17^2$$
    Hence $$8, 15, 17$$ is pythagorean triplet 

    Option (C)  $$7, 24, 25$$
    observe that $$7^2 + 24^2 = 49 + 576 $$
                                          $$= 625$$
                                          $$= 25^2$$
    So $$7, 24, 25$$ is pythagorean triplet.

    Option (D) $$13, 26, 29$$
    check that $$13^2 + 26^2 = 169 + 676$$
                                       $$= 845$$
    and $$29^2 = 841$$
    So $$13^2 + 26^2 \neq 29^2$$

    Hence option D is correct.
  • Question 9
    1 / -0
    Which of the following number is not a perfect square?
    Solution
    Explanation: According to the property of square, a number ending with $$2,3,7$$ and $$8$$ is not a perfect square. 
    Hence, $$2222$$ is not a perfect square.
  • Question 10
    1 / -0
    Which of the following number is not a perfect square?
    Solution
    $$(a) 1843$$
    Explanation: According to the property of square a number ending with $$2,3,7$$ and $$8$$ is not a perfect square. Hence, $$1843$$ is not a perfect square.
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