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Sound Test - 14

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Sound Test - 14
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  • Question 1
    1 / -0
    What is the time period of a wave having frequency of $$50 \ Hz$$?
    Solution
    $$\text {Time period} = \dfrac{1}{\text{frequency}}= \dfrac{1}{50}=\ 0.02 \ s$$
  • Question 2
    1 / -0
    Vocal cords in men are about ____ long.
    Solution
    The vocal cords in men are of 20 mm of length. 
  • Question 3
    1 / -0
    Which is true for a wave? (here n = frequency, T = time period).
    Solution
            Option A

    Frequency is number of vibrations per (one) second, and time period is the time taken to complete one vibration.
          Let a vibrating body completes n vibrations in 1 s,
    therefore time taken to complete one vibration , $$T=(1/n)$$ second
      therefore we have , $$T=1/n$$ ,
                or                  $$nT=1$$
      
  • Question 4
    1 / -0
    A tuning fork vibrates with $$2$$ vibrations in $$0.4\ s$$. Its frequency is:
    Solution
    Frequency is defined as the number of vibrations per second. 
    Given,
    A tuning fork vibrates with $$2$$ vibrations in $$0.4\ s$$.
    Number of vibrations $$=2$$
    Time $$=0.4\ s$$
    Frequency, $$f=\dfrac{number\ of\ vibrations}{time}$$
    $$f=\dfrac{2}{0.4}$$

    $$f=5\ Hz$$ 
  • Question 5
    1 / -0
    Some animals get disturbed and start running here and there just before the earthquakes occur because they can hear______________?
    Solution
    Answer is A.

    An earthquake produces infra-sound before the main shock wave. Infra-sound is a low-frequency sound. It is sound that is lower in frequency than 20 Hz (hertz) or cycles per second, the normal limit of human hearing. Hearing becomes gradually less sensitive as frequency decreases, so for humans to perceive infra-sound, the sound pressure must be sufficiently high. 
    Rhinos have extremely good ears, picking up infra-sound far deeper than the range of human hearing.
    Rhinos can hear down to a frequency of four hertz, whereas even a human baby, with entirely undamaged ears, can normally only pick up sounds as low as 20 hertz. Giraffes and elephants can also hear in this infra-sound range.
    Hence, we can see some animals get disturbed and start running here and there just before the earthquakes because they can hear infrasonic sound.
  • Question 6
    1 / -0
    The difference between musical sound and noise is due to: 
    Solution
    Pitch is that characteristic of a musical sound by which a shrill sound can be distinguished from a grave one, even though the two sounds may be of the same intensity. It is also defined as that characteristic of sound by which the ear assigns it a place on a musical scale. When a stretched string is plucked, a sound of a certain pitch sensation is produced. If the tension in the string is increased, the pitch (the shrillness) becomes higher. Increasing the tension also increases the frequency of vibration. Therefore, the pitch is intimately related to frequency. But frequency alone does not determine the pitch. Below $$1000\ Hz$$, the pitch is slightly higher than the frequency and above $$1000\ Hz$$ the position is reversed. The loudness of sound also affects the pitch up to $$1000\ Hz$$. An increase in loudness causes a decrease in pitch. From about $$1000$$ to $$3000\ Hz$$, the pitch is independent of loudness, while above $$3000\ Hz$$ an increase in loudness causes an increase in pitch.
    Hence, the difference between musical sound and noise is due to pitch.
  • Question 7
    1 / -0
    The characteristic of sound which helps to distinguish between a man's voice and a woman's voice is.
    Solution
    Answer is A.

    Pitch of a sound depends upon the frequency of waves.
    The greater the frequency, the higher is the pitch and vice versa. It is the pitch of sounds that enable us to distinguished between a sound of man and woman. Sound of a woman is shrill due to high pitch. Sound of a man is grave due to low pitch and low frequency.
  • Question 8
    1 / -0
    Time period of a sound wave having the wavelength 0.2 m and frequency 10 Hz will be
    Solution
    Given -  $$    n=10Hz$$ ,
    we have , time period , $$T=1/n=1/10=0.1s$$
  • Question 9
    1 / -0
    A sound wave completes $$24$$ cycles in $$0.8\;s$$. The frequency of the wave is :
    Solution
    Frequency is the number of times the cycle repeats in a one-time unit.

    Given that, the sound wave completes $$24$$ cycles in $$0.8\,s$$.

    So, the number of cycles in $$0.1\,s =\dfrac{24}{0.8}=30\,Hz$$

    Hence the frequency is $$30\, Hz$$


  • Question 10
    1 / -0
    The sound of the human voice is produced due to
    Solution
    Vibration means rapid to and fro movement of an object. Sound of the human voice is produced due to vibrations in the vocal cords.
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