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Sound Test - 27

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Sound Test - 27
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  • Question 1
    1 / -0
    The sketches I to IV in Fig. show sound waves, all formed in the same time interval. Which diagram shows a bass (low frequency) note?

    Solution
    Frequency is the speed of the vibration, and this determines the pitch of the sound.  It is only useful or meaningful for musical sounds, where there is a strongly regular waveform. In other words, frequency is the number of cycles per second in a particular wave pattern.
    In the question, figure II has the least number of cycles, and hence, it has a low frequency or a base note.

  • Question 2
    1 / -0
    Different musical instruments sound different even when they play a note with the same pitch.
    Solution
    Quality is used to describe the quality of the waveform as it appears to the listener. Therefore the quality of a note depends upon the waveform. Two notes of the same pitch and loudness, played from different instruments do not sound the same because the waveforms are different and therefore differ in quality or tone.
    The same note from different instruments has different qualities because the sounds from instruments are never pure notes, i.e. of one frequency, the only exception being a tuning fork.
  • Question 3
    1 / -0
    Sound waves requires a .......... to travel through.
    Solution
    Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.
  • Question 4
    1 / -0
    A sound of wave produces $$40$$ crests and $$40$$ troughs in $$0.4s$$. What is the frequency of the wave?
    Solution
    One complete cycle consists of one crest and one trough.
    The given source produces 40 crests and 40 troughs, hence it produces 40 wave cycles in the given interval 0.4 seconds. 

    Therefore, number of wave cycles produced in 1 second $$=\quad \dfrac { 40\times 1 }{ 0.4 } \quad =\quad 100$$

    We know that the number of wave cycles produced in one second is equal to the frequency.

    Hence, the frequency of the wave is 100 Hz.
  • Question 5
    1 / -0
    A sound wave has a frequency of 192 Hz and travels the length of a football field, 91.4 m, in 0.27 s. What is the period of the wave?
    Solution
    The frequency (f) of a wave is the number of full wave forms generated per second. This is the same as the number of repetitions per second or the number of oscillations per second.  
    Time Period (T) is the number of seconds per waveform, or the number of seconds per oscillation.  It is clear that frequency and period are reciprocals.
    That is, $$T=\dfrac { 1 }{ f } =\dfrac { 1 }{ 192 } =0.0052\quad seconds$$.
    Hence, the time period of the wave is $$5.2\times { 10 }^{ -3 }\quad seconds$$.
  • Question 6
    1 / -0
    The waves that transfer vibrations and disturbance are:
    Solution
    A wave is a disturbance that moves through a medium when the particles of the medium set neighboring particles into motion. Sound is produced due to the vibration of different objects. Sound travels as a longitudinal wave through a material medium.
    Sound waves with frequencies below the audible range are termed “infrasonic” and those above the audible range are termed “ultrasonic”.
  • Question 7
    1 / -0
    The relation between frequency(f) and time period(T) is given by
    Solution
    The frequency (f) of a wave is the number of full wave forms generated per second. This is the same as the number of repetitions per second or the number of oscillations per second.  
    Time Period (T) is the number of seconds per waveform, or the number of seconds per oscillation.  It is clear that frequency and time period are reciprocals. 
    That is,
     T=1/f.  
  • Question 8
    1 / -0
    Echocardiography is used to diagnose heart diseases which utilises infrasonic waves.
    Solution
    An echocardiogram (also called an echo) is a type of ultrasound test that uses high-pitched sound waves that are sent through a device called a transducer. The device picks up echoes of the sound waves as they bounce off from the different parts of the heart. These echoes are turned into moving pictures of the heart that can be seen on a video screen.
    Hence, the statement is false.
  • Question 9
    1 / -0
    Water waves in a shallow dish are $$6 cm$$ long. At one point, the water moves up and down at a rate of $$4.8$$ oscillations/s. What is the time period of the water waves?
    Solution
    The frequency (f) of a wave is the number of full wave forms generated per second. This is the same as the number of repetitions per second or the number of oscillations per second.  
    Time Period (T) is the number of seconds per waveform, or the number of seconds per oscillation.  It is clear that frequency and period are reciprocals. 
    That is, $$T=\dfrac{1}{f}$$

    $$\dfrac{1}{f}=\dfrac{1}{4.8}=0.208\;seconds$$
    Hence, the time period of the water wave is 0.208 seconds.
  • Question 10
    1 / -0
    In a ripple tank, 10 full ripples/s are produced. The distance between peaks of consecutive trough and crest is 15 cm. Calculate the frequency.
    Solution
    Frequency is the number of complete vibrational cycles of a medium per a given amount of time. The frequency would have units of cycles per second, waves per second or vibrations per second. The unit for frequency is the Hertz (abbreviated Hz) where 1 Hz is equivalent to 1 cycle per second. 
    In the question it is mentioned that 10 full ripples per second are produced. Hence, the frequency is 10 Hz.
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